A Man Weighing 14 Stone And His Two Sons Weighing 7 Stone Each Were Stranded On An Island All They Had To Get Of The Is Riddles To Solve
Solving A Man Weighing 14 Stone And His Two Sons Weighing 7 Stone Each Were Stranded On An Island All They Had To Get Of The Is Riddles
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Two Tablets Of Stone
He led Israelites out of Egypt
And went up Mount Sinai alone
He came back down with ten commandments
Written on two tablets of stone
Who is this man?
And went up Mount Sinai alone
He came back down with ten commandments
Written on two tablets of stone
Who is this man?
Hint:
Her Pretty Wings As Still As Stone Riddle
What is it?
Hint:
Fake Ireland Stones Riddle
Hint:
Farmer Stones Riddle
A farmer had a stone that he used to measure grain on his scale. One day his neighbor borrowed the stone, and when he returned, it was broken into four pieces. The neighbor was very apologetic, but the farmer thanked the neighbor for doing him a big favor. The farmer said that now he can measure his grain in one pound increments starting at one pound all the way to forty pounds (1, 2, 3, 17, 29, 37, etc.) using these four stones.
How much do the four stones weight?
How much do the four stones weight?
Hint:
The stones weight 1 pound, 3 pounds, 9 pounds and 27 pounds. These can be used in combination with each other on both sides of the scale to come up with any counterweight from 1 to 40 pounds. Did you answer this riddle correctly?
YES NO
YES NO
Stones In The Sea Riddle
Hint:
Rolling Stones And Borimir Riddle
Hint:
Have you not heard? One does not simply rock into Mordor! Did you answer this riddle correctly?
YES NO
YES NO
As Hard As Stone Riddle
Im hard but Im not a stone
Im cold but I dont need a coat
If I get warmed up I change appearance but Im not popcorn
I get put in drinks but Im not a straw
Im made of H20 but Im not running water Body parts remaining: 6
Im cold but I dont need a coat
If I get warmed up I change appearance but Im not popcorn
I get put in drinks but Im not a straw
Im made of H20 but Im not running water Body parts remaining: 6
Hint:
Red Stone In The Sea
Hint:
As A Stone Inside A Tree Riddle
What am I?
Hint:
Precious Stones In A Pack Of Cards Riddle
Hint:
Robert And Cindy Were Stranded On An Island Riddle
How does he do it?
Hint:
Dissolve all 4 pills in water and drink the half water.
The Robert And Cindy will dissolve all the pills in water and will drink the half water so that he each person can get 1 red and 1 blue pills and they both get save. Did you answer this riddle correctly?
YES NO
The Robert And Cindy will dissolve all the pills in water and will drink the half water so that he each person can get 1 red and 1 blue pills and they both get save. Did you answer this riddle correctly?
YES NO
Solved: 54%
Having More But Weighing Less
Hint:
12 Islanders Teeter Totter Riddle
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
Hint:
Six on one side - six on the other = one side is heavier.
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Shipwrecked On A Deserted Island
Two men and women have shipwrecked on a deserted island. They are bored so they want to want to have some fun. As there is a plenty of time each one of them wants to try all possible (heterosexual) partners.
The problem is that each of them has a different STD and if anyone was to catch another one he/she would hardly survive. They have two condoms that the men had brought. How are they supposed to plan theyre sexual activities so that every woman would have sex with every man and they would prevent spreading STDs at the same time?
(Condoms are ideal, they last a lot but the used side cant get to contact with the particular part of a different body)
The problem is that each of them has a different STD and if anyone was to catch another one he/she would hardly survive. They have two condoms that the men had brought. How are they supposed to plan theyre sexual activities so that every woman would have sex with every man and they would prevent spreading STDs at the same time?
(Condoms are ideal, they last a lot but the used side cant get to contact with the particular part of a different body)
Hint:
To solve this problem they have to use two condoms at the same time.
man 1 uses two condoms and has sex with woman 1
man 1 takes off one condom and has sex with woman 2
man 2 takes condom that man 1 has taken off and has sex with woman 1
man 2 puts the second condom over the one he is already wearing and has sex with woman 2 Did you answer this riddle correctly?
YES NO
man 1 uses two condoms and has sex with woman 1
man 1 takes off one condom and has sex with woman 2
man 2 takes condom that man 1 has taken off and has sex with woman 1
man 2 puts the second condom over the one he is already wearing and has sex with woman 2 Did you answer this riddle correctly?
YES NO
A Man Steals 1000 From A Shop Riddle
Hint:
We can easily solve this mathematical problem by using the following mathematical process.
Initial loss amount = Rs. 1000
Now, we have to calculate the recovered amount,
As the man spends Rs. 700 in the shop, the shop owner will surely provide the man goods/services of Rs. 700. So, nothing will be recovered in this case.
Now, the man gave Rs. 1000 against the goods/services of Rs. 700 and got Rs. 300 change, so there will be no recovering of money for the shopkeeper.
Final loss = Initial loss - Recovered amount = 1000-0 = Rs. 1000 Did you answer this riddle correctly?
YES NO
Initial loss amount = Rs. 1000
Now, we have to calculate the recovered amount,
As the man spends Rs. 700 in the shop, the shop owner will surely provide the man goods/services of Rs. 700. So, nothing will be recovered in this case.
Now, the man gave Rs. 1000 against the goods/services of Rs. 700 and got Rs. 300 change, so there will be no recovering of money for the shopkeeper.
Final loss = Initial loss - Recovered amount = 1000-0 = Rs. 1000 Did you answer this riddle correctly?
YES NO
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