I Can Speak Any Language Riddle
My stem's planted firmly where I am allotted.
My tail is wavy and my face is quite blotted.
I relay much emotion though flatly I'm spotted,
And I grow half my size whenever I'm dotted.
I can speak any language, yet utter no words.
I'm no seed, yet I am well known among birds.
But I do have a speech impediment:
I can say cage but not page, aged but not wage.
I can say deaf but not red, bed but not sled.
I live on a highway that's structurally sound,
Where you might see my friends accidentally bound.
It has many lanes, and also long lines.
There are lots of sharp turns, but plenty of signs.
I am played but not won, made but not spun.
The key is to measure before you've begun.
What am I?
My tail is wavy and my face is quite blotted.
I relay much emotion though flatly I'm spotted,
And I grow half my size whenever I'm dotted.
I can speak any language, yet utter no words.
I'm no seed, yet I am well known among birds.
But I do have a speech impediment:
I can say cage but not page, aged but not wage.
I can say deaf but not red, bed but not sled.
I live on a highway that's structurally sound,
Where you might see my friends accidentally bound.
It has many lanes, and also long lines.
There are lots of sharp turns, but plenty of signs.
I am played but not won, made but not spun.
The key is to measure before you've begun.
What am I?
Hint:
Wall Clock Riddle
My only timepiece is a wall clock. One day I forgot to wind it and it stopped. I went to visit a friend whose watch is always correct, stayed awhile, and returned home. There I made a simple calculation and set the clock right. How did I do this when I had no watch on me to tell how long it took me to return home from my friends house?
Hint:
Before I left, I wound the wall clock. When I returned, the change in time it showed equaled the time it took to go to my friend's and return, plus the time I spent there. But I knew the latter, because I looked at my friend's watch both when I arrived and when I left. Subtracting the time of the visit from the time I was absent from my house, and dividing by 2, I obtained the time it took me to return home. I added this time to the time my friend's watch showed when I left, and set this sum on my wall clock. Did you answer this riddle correctly?
YES NO
YES NO
The New Iphone Riddle
Hint:
Sharing Is Caring Riddle
Hint:
Ariel's Lost Friend Riddle
Hint:
On A Hiking Trip Riddle
How did they manage to achieve this formation ?
Hint:
You can see that they decided to form a pentagonal formation. Did you answer this riddle correctly?
YES NO
YES NO
A Walk In The Desert Riddle
Four men walk into the desert. Suddenly all four are simultaneously knocked out. They awake buried to their heads in the sand unable to look anywhere but straight ahead. They are positioned so that each man sees another's head before him. However between the first and second man there is a separating wall.
So the first man sees only desert. The second man sees only wall. The third man sees another's head and a wall. The fourth man sees two heads and a wall. On top of each mans head is a hat. The underside of each cap is black, but the outside of each cap is either blue or white. Before any of the men can speak, their captors tell them if they speak, they die. However, if any of them can guess the color of their cap on the first try they go free. The captors tell them that there are two blue caps and two white caps.
Being an omniscient observer of the situation, we know that the order of the caps are: blue, white, blue, white. So knowing the perspective of each man in the sand, and that they can only see the color of caps/wall/desert in front of them, which of the four men knows for certain the color of his own cap. More importantly: why?
So the first man sees only desert. The second man sees only wall. The third man sees another's head and a wall. The fourth man sees two heads and a wall. On top of each mans head is a hat. The underside of each cap is black, but the outside of each cap is either blue or white. Before any of the men can speak, their captors tell them if they speak, they die. However, if any of them can guess the color of their cap on the first try they go free. The captors tell them that there are two blue caps and two white caps.
Being an omniscient observer of the situation, we know that the order of the caps are: blue, white, blue, white. So knowing the perspective of each man in the sand, and that they can only see the color of caps/wall/desert in front of them, which of the four men knows for certain the color of his own cap. More importantly: why?
Hint:
The third man. This is because he knows there are only two of each color cap. If the man behind him (the fourth man) saw two caps that were the same color in front of him, he would know that his own must be the opposite. However, because the caps alternate in color. The fourth man has only a 50% chance of getting his hat color correct, so therefore he stays quiet. The third man realizes that the fourth man is quiet because he must not see two caps of the same color in front of him, otherwise the fourth man would say the opposite of the caps in front of him. Therefore, the third man presumes his own cap must be the opposite of the mans in front of him, and his presumption is correct. Under this same logic, after the third man speaks his color hat, the second man, even though he sees only wall, would be the next to go free, because he knows his cap must be the opposite of whichever color the third mans cap was. Did you answer this riddle correctly?
YES NO
YES NO
You Must Follow Riddle
I am a paradox. Three pieces of one picture, a cataclysmic fire, a scorching flame. A tender whisper to wipe away tears. With a nail and a tree I dispel all fears. Except fears of myself. My blood was spilled but never runs dry. I was murdered by men but never will die.
I walked with my enemies to make them my friends, my road is a hard walk, but the joy never ends. The question is my name, but for the answer you must follow. Who am I?
I walked with my enemies to make them my friends, my road is a hard walk, but the joy never ends. The question is my name, but for the answer you must follow. Who am I?
Hint:
Jump Up And Down Riddle
I am a toy and can be any color. I make you and your friends jump up and down. Everyone stand on me and bounce! What am I?
Hint:
The Youngest Girl Scout Riddle
I am the youngest level of Girl Scouts
Im a flower and a females name
Im a railcar in Thomas And Friends
And a Princess in a Mario game
Im a flower and a females name
Im a railcar in Thomas And Friends
And a Princess in a Mario game
Hint:
Sun, Planet Or Moon Riddle
I am here all the time,
Even if you can not see me,
I appear to be as big as a dime,
I am able to do something different,
But closer than another galaxy,
I am important in your life,
In more than just a couple ways.
Am I the Sun, a Planet, or the Moon?
Even if you can not see me,
I appear to be as big as a dime,
I am able to do something different,
But closer than another galaxy,
I am important in your life,
In more than just a couple ways.
Am I the Sun, a Planet, or the Moon?
Hint: Read it again closely, because there is a clue!
Skeleton Communication Riddle
Hint:
Helping You Learn Riddle
I come in many colors and I am very thin, I am found in every country, even in your home, I am very important, you can be very creative with me, I can even help you learn.
What am I?
What am I?
Hint:
Swinging At The Park Riddle
Which swings faster? And more importantly, why?
Hint:
The speed at which a pendulum swings is called the period and given by the equation:
2 x pi x square root of (length of rope from fulcrum to Center of Mass divided by gravity)
Since gravity is constant, the only thing that effects the period is the length of rope. In the above scenario, you assume the man is taller then the child. Therefore his center of mass is higher. This makes the distance between the fulcrum to the center of mass shorter then for the child. The man swings faster. Did you answer this riddle correctly?
YES NO
2 x pi x square root of (length of rope from fulcrum to Center of Mass divided by gravity)
Since gravity is constant, the only thing that effects the period is the length of rope. In the above scenario, you assume the man is taller then the child. Therefore his center of mass is higher. This makes the distance between the fulcrum to the center of mass shorter then for the child. The man swings faster. Did you answer this riddle correctly?
YES NO
Dwarf Tickets Riddle
Recently, Snow White's seven dwarfs met up with three of their friends and went to the cinema to see Bambi. From the clues below, can you determine the order in which they stood in the ticket queue?
Grumpy was in front of Dopey. Stumpy was behind Sneezy and Doc. Doc was in front of Droopy and Happy.
Sleepy was behind Stumpy, Smelly and Happy.
Happy was in front of Sleepy, Smelly and Bashful.
Bashful was behind Smelly, Droopy and Sleepy.
Sneezy was in front of Dopey. Smelly was in front of Grumpy, Stumpy and Sneezy.
Dopey was in front of Droopy.
Sleepy was in front of Grumpy and Bashful.
Dopey was behind Sneezy, Doc and Sleepy.
Stumpy was in front of Dopey. Smelly was behind Doc.
Grumpy was in front of Dopey. Stumpy was behind Sneezy and Doc. Doc was in front of Droopy and Happy.
Sleepy was behind Stumpy, Smelly and Happy.
Happy was in front of Sleepy, Smelly and Bashful.
Bashful was behind Smelly, Droopy and Sleepy.
Sneezy was in front of Dopey. Smelly was in front of Grumpy, Stumpy and Sneezy.
Dopey was in front of Droopy.
Sleepy was in front of Grumpy and Bashful.
Dopey was behind Sneezy, Doc and Sleepy.
Stumpy was in front of Dopey. Smelly was behind Doc.
Hint:
Doc,
Happy,
Smelly,
Sneezy,
Stumpy,
Sleepy,
Grumpy,
Dopey,
Droopy, Did you answer this riddle correctly?
YES NO
Happy,
Smelly,
Sneezy,
Stumpy,
Sleepy,
Grumpy,
Dopey,
Droopy, Did you answer this riddle correctly?
YES NO
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