HOSE RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Hose Riddles To Solve

Solving Hose Riddles

Here we've provide a compiled a list of the best hose puzzles and riddles to solve we could find.

Our team works hard to help you piece fun ideas together to develop riddles based on different topics. Whether it's a class activity for school, event, scavenger hunt, puzzle assignment, your personal project or just fun in general our database serve as a tool to help you get started.

Here's a list of related tags to browse: Life Riddles What Am I Riddles Long Riddles Math Brain Teasers Hard Riddles Puzzle Questions Number Riddles Bad Riddles Queen Riddles

The results compiled are acquired by taking your search "hose" and breaking it down to search through our database for relevant content.

Browse the list below:

Those Who Make Me Are Likely To Break Me Riddle

Hint:
A promise
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12 Islanders Teeter Totter Riddle

Hint:
Six on one side - six on the other = one side is heavier.

Take the heavier six men, divide them into three and three (random).

Three on one side - three on the other = one side will one heavier.

Divide that three men from the heavier side side, have one on one side - one on the other.

Two results can determine which of the last three men weight is a different weight than each other.

With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.

Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.

You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."

Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less.
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Find Those Missing Numbers Riddle

Hint:
The number missing on the left is 8 and the one on right is 7.

Explanation:
The pattern:
The number in the center of triangle is the square root of the sum of the numbers sitting outside on the corners.

Thus,
10 + 22 + 4 = 36
Square Root of 36 = 6

In the same manner:

10 + 42 + 12 = 64
Square Root of 64 = 8

12 + 22 + 15 = 49
Square Root of 49 = 7
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A Queen's Twins Riddle

Hint:
He is a male.
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The Prime Number Riddle

Hint: Remember that 1 is not a prime number.
Those that remain behind must have written {1,4,6,8,9} and from this only {1,9} are odd. The probability of an odd number is thus 2/5.
Expected number of odds is 2/5 * 90 = 36
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The Coin Toss Riddle

Hint: Think what would be most likely to happen if you chose HHH, would this be a good decision?
The answer is to let your friend go first. This puzzle is based on an old game/scam called Penny Ante. No matter what you picked, your friend would be able to come up with a combination which would be more likely to beat yours. For example, if you were to choose HHH, then unless HHH was the first combination to come up you would eventually lose since as soon as a Tails came up, the combination THH would inevitably come up before HHH. The basic formula you can use for working out which combination you should choose is as follows. Simply take his combination (eg. HHT) take the last term in his combination, put it at the front (in this case making THH) and your combination will be more likely to come up first. Try it on your friends!
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The Secret Santa Exchange

Hint: It's not as difficult as it seems. It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10

For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is

(n-1)! / n!

Since n! = (n-1)! * n (for n > 1), this can be rewritten as

(n-1)! / (n*(n-1)!)

Factoring out the (n-1)! from the numerator and denominator leaves

1/n

as the probability.
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Coconut Money Riddle

Hint:
He's a millionaire already.
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Five Prom Couples Riddle

Hint:
Mark and Susan wore red.
Quintin and Jessica wore blue.
Jim and Amanda wore pink.
Bob and Betty wore green.
James and Jasmin wore yellow.
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100 Birds

Hint:
All of the birds flew away from the tree.
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Brown And Hairy Riddle

Hint:
Coconut
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Baking Cookies And Pizza

Hint:
Oven
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Tub Sink And Towels

Hint:
Bathroom
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Golf And Pizza Riddle

Hint:
Eleven, David won 7 matches, 4 to cancel out Robert's 4 wins, and 3 more to win the pizzas.
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Almost Blind Riddle

Hint:
Eye glasses.
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