MY SON WAS PLAYING WITH A BOOK AND TORE OUT PAGES 7 8 100 101 222 AND 223 HOW MANY PAGES WERE TORN OUT 8 100 101 222 AND 223 HOW MANY PAGES WERE TORN OUT RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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My Son Was Playing With A Book And Tore Out Pages 7 8 100 101 222 And 223 How Many Pages Were Torn Out 8 100 101 222 And 223 How Many Pages Were Torn Out Riddles To Solve

Solving My Son Was Playing With A Book And Tore Out Pages 7 8 100 101 222 And 223 How Many Pages Were Torn Out 8 100 101 222 And 223 How Many Pages Were Torn Out Riddles

Here we've provide a compiled a list of the best my son was playing with a book and tore out pages 7 8 100 101 222 and 223 how many pages were torn out 8 100 101 222 and 223 how many pages were torn out puzzles and riddles to solve we could find.

Our team works hard to help you piece fun ideas together to develop riddles based on different topics. Whether it's a class activity for school, event, scavenger hunt, puzzle assignment, your personal project or just fun in general our database serve as a tool to help you get started.

Here's a list of related tags to browse: Hard Brain Teasers Book Riddles Tricky Riddles Book Riddles Harry Potter Riddles Book Riddles Mystery Riddles Middle School Riddles

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Playing With A Book Riddle

Hint:
10. Remember pages of a book are double-sided.

7+8, 99+100, 101+102, 221+222, 223+224s.
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My Nephew Was Playing With A Book Riddle

Hint:
This is a tricky riddle indeed. Each page in a book has a odd and even number( assuming its printed both sides).Hence page number looks like 1-2, 3-4, 5-6 and so on..Now looking at above riddle.

7-8 is single page
99-100 is single page
101-102 is single page
221-222 is single page
223-224 is single page.

So total of 5 pages
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Between The Pages Riddle

Hint:
Harry Potter, like all other books, has odd-numbered pages on the right. Therefore, pages 15 and 16 are the front and back of a single page, and nothing could have been found between them.
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Halfway To 100

Hint:
50
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I Am Close To 100

Hint:
98.
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60 Pages Riddle

Hint:
Pages 19, 20, 23, 37, 38, & 42 will also be missing
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I Bought A Cow For 800 Riddle

Hint:
You earned $500 $100 = $400.
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Speaking Without Voice Riddle

Hint:
A book
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100 Floors Riddle

Hint:
He is short, so he can't reach the 100th floor button. On rainy days, he can use his umbrella to poke the button.
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Who Stole The $100,000 Riddle

Hint:
The mail guy did it because if he checked between page numbers 1 and 2 page numbers 2 and 3 are opposite sides of one page and could not hold the dollar bill.
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A Man Steals 1000 From A Shop Riddle

Hint:
We can easily solve this mathematical problem by using the following mathematical process.

Initial loss amount = Rs. 1000

Now, we have to calculate the recovered amount,

As the man spends Rs. 700 in the shop, the shop owner will surely provide the man goods/services of Rs. 700. So, nothing will be recovered in this case.

Now, the man gave Rs. 1000 against the goods/services of Rs. 700 and got Rs. 300 change, so there will be no recovering of money for the shopkeeper.

Final loss = Initial loss - Recovered amount = 1000-0 = Rs. 1000
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The 100 Pound Watermelon

Hint:
50 pounds.

In the beginning it is 99 pounds water and 1 pound other stuff. At the end the 1 pound other stuff is 2 percent so the total weight is 50 pounds. 50 pounds - 1 pound other stuff = 49 pounds water. So 99 pounds - 49 pounds = 50 pounds water lost.
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A 100 Year Old Ant

Hint:
An antique!
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Tornado Games Riddle

Hint:
Twister!
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The 100 Seat Airplane

Hint: You don't need to use complex math to solve this riddle. Consider these two questions: What happens if somebody sits in your seat? What happens if somebody sits in Steve's assigned seat?
The correct answer is 1/2.

The chase that the first person in line takes your seat is equal to the chance that he takes his own seat. If he takes his own seat initially then you have a 100% chance of sitting in your seat, if he takes your seat you have a 0 percent chance. Now after the first person has picked a seat, the second person will enter the plan and, if the first person has sat in his seat, he will pick randomly, and again, the chance that he picks your seat is equal to the chance he picks someone your seat. The motion will continue until someone sits in the first persons seat, at this point the remaining people standing in line which each be able to sit in their own seats. Well how does that probability look in equation form? (2/100) * 50% + (98/100) * ( (2/98) * 50% + (96/98) * ( (2/96) * (50%) +... (2/2) * (50%) ) ) This expansion reduces to 1/2.
An easy way to see this is trying the problem with a 3 or 4 person scenario (pretend its a car). Both scenarios have probabilities of 1/2.
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