Presen Riddles To Solve
Solving Presen Riddles
Here we've provide a compiled a list of the best presen puzzles and riddles to solve we could find.Our team works hard to help you piece fun ideas together to develop riddles based on different topics. Whether it's a class activity for school, event, scavenger hunt, puzzle assignment, your personal project or just fun in general our database serve as a tool to help you get started.
Here's a list of related tags to browse: Rhyming Riddles What Am I Riddles Brain Teasers Riddles To Solve Word Riddles Christmas Riddles For Kids Dog Riddles Advent Calendar Riddles Car Riddles
The results compiled are acquired by taking your search "presen" and breaking it down to search through our database for relevant content.
Browse the list below:
I Go Up And I Go Down Towards The Sky And The Ground Riddle
towards the sky and the ground.
I'm present and past tense too,
Let's go for a ride, me and you.
What am I?
Hint:
Not Often Riddle
Hint:
Dog Presents Riddle
Hint:
The Traffic Light Riddle
There is a traffic light at the top of a hill. Cars can't see the light until they are 200 feet from the light.
The cycle of the traffic light is 30 seconds green, 5 seconds yellow and 20 seconds red.
A car is traveling 45 miles per hour up the hill.
What is the probability that the light will be yellow when the driver first crests the hill and that if the driver continues through the intersection at her present speed that she will run a red light?
The cycle of the traffic light is 30 seconds green, 5 seconds yellow and 20 seconds red.
A car is traveling 45 miles per hour up the hill.
What is the probability that the light will be yellow when the driver first crests the hill and that if the driver continues through the intersection at her present speed that she will run a red light?
Hint:
The probability of the driver encountering a yellow light and the light turning red before the car enters the intersection is about 5.5%.
At 45 mph the car is traveling at 66 feet/second and will take just over 3 seconds (3.03) to travel the 200 feet to the intersection. Any yellow light that is in the last 3.03 seconds of the light will cause the driver to run a red light.
The entire cycle of the light is 55 seconds. 3.03/55 = 5.5%. Did you answer this riddle correctly?
YES NO
At 45 mph the car is traveling at 66 feet/second and will take just over 3 seconds (3.03) to travel the 200 feet to the intersection. Any yellow light that is in the last 3.03 seconds of the light will cause the driver to run a red light.
The entire cycle of the light is 55 seconds. 3.03/55 = 5.5%. Did you answer this riddle correctly?
YES NO
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
A Gift To His Daughter
Father offered a gift to his Daughter and told her "If you feel hungry, you may eat it. If you feel thirsty, you may drink it. If you feel coldish, you may burn it." So, what is that gift that father presented to the daughter?
Hint:
Born In Silence
Sometimes I am born in silence,
Other times, no.
I am unseen,
But I make my presence known.
In time, I fade without a trace.
I harm no one,
but I am unpopular with all.
What am I?
Other times, no.
I am unseen,
But I make my presence known.
In time, I fade without a trace.
I harm no one,
but I am unpopular with all.
What am I?
Hint:
Aircraft Riddle
This aircraft helps news teams
Present traffic reports
It can take off and land
From special heliports
What is this aircraft?
Present traffic reports
It can take off and land
From special heliports
What is this aircraft?
Hint:
Prince Age Riddle
What are their ages?
Hint:
Current Future Past
Princess x 2z (x+y)/2
Prince y x z
I then created three equations, since the difference in their age will always be the same.
d = the difference in ages
x y = d
2z x = d
x/2 + y/2 z = d
I then created a matrix and solved it using row reduction.
x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d
It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
This means that you can pick any difference you want (an even one presumably because you want integer ages).
Princess age: 4d
Prince age: 3d
Ages that work
Princess:
4
8
16
24
32
40
48
56
64
72
80
Prince:
3
6
12
18
24
30
36
42
48
54
60 Did you answer this riddle correctly?
YES NO
Princess x 2z (x+y)/2
Prince y x z
I then created three equations, since the difference in their age will always be the same.
d = the difference in ages
x y = d
2z x = d
x/2 + y/2 z = d
I then created a matrix and solved it using row reduction.
x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d
It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
This means that you can pick any difference you want (an even one presumably because you want integer ages).
Princess age: 4d
Prince age: 3d
Ages that work
Princess:
4
8
16
24
32
40
48
56
64
72
80
Prince:
3
6
12
18
24
30
36
42
48
54
60 Did you answer this riddle correctly?
YES NO
Lights Ornaments And Stars
Hint:
Making A List Riddle
Hint:
Eight Candles Riddle
I am a special candle holder for Hanukkah. I have eight candles and one special candle called a shamash that lights all the other candles. I represent the miracle of the oil lasting for 8 days. What am I?
Hint:
I Bring Luck Riddle
At Chinese New Year celebrations
I breathe fire, dance and run amuck
With a few men to guide my steps
My presence brings good fortune and luck
What am I?
I breathe fire, dance and run amuck
With a few men to guide my steps
My presence brings good fortune and luck
What am I?
Hint:
Represent 8 But Counted As 10
I represent 8 but listed as 10,
I have shortened days until time changes again.
What am I? Body parts remaining: 6
I have shortened days until time changes again.
What am I? Body parts remaining: 6
Hint: I have 2 birthstones
I See London, I See France
Hint:
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