SAME RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

The first ship!

First ship = d/35 + d/35 = 2d/35 = 0.0571d

Second ship = d/30 = d/40 = 70d/1200 = 0.058 Did you answer this riddle correctly?
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The first ship!

First ship = d/35 + d/35 = 2d/35 = 0.0571d

Second ship = d/30 = d/40 = 70d/1200 = 0.058 Did you answer this riddle correctly?
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6 was afraid of 7 because the 7 ate 9! Did you answer this riddle correctly?
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We can easily solve this mathematical problem by using the following mathematical process.

Initial loss amount = Rs. 1000

Now, we have to calculate the recovered amount,

As the man spends Rs. 700 in the shop, the shop owner will surely provide the man goods/services of Rs. 700. So, nothing will be recovered in this case.

Now, the man gave Rs. 1000 against the goods/services of Rs. 700 and got Rs. 300 change, so there will be no recovering of money for the shopkeeper.

Final loss = Initial loss - Recovered amount = 1000-0 = Rs. 1000 Did you answer this riddle correctly?
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They were two of a set of triplets. Did you answer this riddle correctly?
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A Barber Did you answer this riddle correctly?
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Take any six pills and divide them into two groups of three each. Weigh putting the 3 pills on each side. If one side weigh's heavier than another, the heavier side consists of the poisonous pill. From the three pill in heavier side, weigh two pills. If one pill is heavier than another, the heavy one is poisonous pill. If both pill weigh same, the remaining third pill is poisonous. If all the 6 pill weigh the same, weigh the remaining two pill and heavy one is poisonous. Did you answer this riddle correctly?
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E = easier in "1", H = heavier in "1". 1: Weight 4:4. If they balance go to "2", if they don't balance, go to "3". 2: Balance 1:1 of the pills you didn't weight yet. Then weight one you didn't weight and one you did weight. If they balanced in the first weighing, and balanced in the second weighing, the last pill is the right one. If they balanced in the first weighing and didn't balance in the second, the one you didn't use before is the right pill. If they didn't balance at all, it's the pill you weighed twice. If they didn't balance in the first weighing, but balanced in the second, it is the first pill. 3: Weight EHH : EHH. If they balance, weight one you already weighed, with an unweighed and go to "4". If they don't balance go to "5". 4: If they balance, the one you didn't weight at all is the right pill. If they don't balance, the one you only weighed once is the right one. 5: Give away every pill that was once easier AND once heavier. You should only have EHH left. Weight H:H. If they balance, E is the right one. If the don't balance, the one which was only heavier the whole time, is the right pill. Did you answer this riddle correctly?
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Both barbers must go to the other barber to get their haircuts. Since the first barber had a clean haircut, that means the second barber gives good haircuts and the first barber doesn't. Did you answer this riddle correctly?
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He is self-employed. He is his own boss. Did you answer this riddle correctly?
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Password Did you answer this riddle correctly?
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Use the number 5 three times, 55 + 5 = 60 Did you answer this riddle correctly?
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They are triplets, not twins. Did you answer this riddle correctly?
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Six on one side - six on the other = one side is heavier.

Take the heavier six men, divide them into three and three (random).

Three on one side - three on the other = one side will one heavier.

Divide that three men from the heavier side side, have one on one side - one on the other.

Two results can determine which of the last three men weight is a different weight than each other.

With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.

Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.

You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."

Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
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It's his grandma Did you answer this riddle correctly?
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