Weighs Riddles To Solve
Solving Weighs Riddles
Here we've provide a compiled a list of the best weighs puzzles and riddles to solve we could find.Our team works hard to help you piece fun ideas together to develop riddles based on different topics. Whether it's a class activity for school, event, scavenger hunt, puzzle assignment, your personal project or just fun in general our database serve as a tool to help you get started.
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The results compiled are acquired by taking your search "weighs" and breaking it down to search through our database for relevant content.
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A Barrel Of Water Weighs 60 Pounds Riddle
Hint:
Eight Pills Riddle
There are 8 pills. They are all the same size and color. One pill weighs slightly more and is poisonous. You have a balanced scale and you can only use it twice. How can you find the poisonous Pill?
Hint:
Take any six pills and divide them into two groups of three each. Weigh putting the 3 pills on each side. If one side weigh's heavier than another, the heavier side consists of the poisonous pill. From the three pill in heavier side, weigh two pills. If one pill is heavier than another, the heavy one is poisonous pill. If both pill weigh same, the remaining third pill is poisonous. If all the 6 pill weigh the same, weigh the remaining two pill and heavy one is poisonous. Did you answer this riddle correctly?
YES NO
YES NO
12 Islanders Teeter Totter Riddle
There is an island with 12 islanders. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11.
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
Hint:
Six on one side - six on the other = one side is heavier.
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Mermaid Weighs Riddle
Hint:
Having More But Weighing Less
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Pound For Pound Riddle
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As Big As A Dino Riddle
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A Couple Of Cannibals Riddle
Michelangelo is being chased by a couple of cannibals who will kill him as soon as they get a hold of him. The only way to get rid of them is crossing the river bridge made of ropes and cut it on reaching the other end. He have found two diamonds in the woods each weighing 8 lbs. The rope is weak and can only accommodate a weight of 150 lbs. He weighs 140 lbs. Still he manages to cross the bridge and get rid of the cannibals with the diamonds without taking off any kind of clothing.
How?
How?
Hint:
Michelangelo juggles the diamonds across while crossing the bridge. Did you answer this riddle correctly?
YES NO
YES NO
A Boy At The Carnival
A boy was at a carnival and went to a booth where a man said to the boy, "If I write your exact weight on this piece of paper then you have to give me $50, but if I cannot, I will pay you $50."
The boy looked around and saw no scale so he agrees, thinking no matter what the carny writes he'll just say he weighs more or less.
In the end the boy ended up paying the man $50. How did the man win the bet?
The boy looked around and saw no scale so he agrees, thinking no matter what the carny writes he'll just say he weighs more or less.
In the end the boy ended up paying the man $50. How did the man win the bet?
Hint:
The man did exactly as he said he would and wrote "your exact weight" on the paper. Did you answer this riddle correctly?
YES NO
YES NO
Changing Jackets Riddle
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Going To The Gym Riddle
A 180lb man goes to the gym six days a week for 5 months. At the end of the 5 months, he still weighs 180lbs, how is that possible?
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A Item Of Danger Riddle
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10 Boxes Riddle
There are ten boxes containing some balls. Each of the ball weighs exactly 10 grams. One of those boxes have defective balls (all the defective balls weigh 9 grams each).
An electronic weighing machine is provided to you and you are allowed only one chance of weighing on it.
How will you find out which box has defective balls ?
An electronic weighing machine is provided to you and you are allowed only one chance of weighing on it.
How will you find out which box has defective balls ?
Hint:
Let us simplify boxes by naming them from 1 to 10.
Now the trick here is to pick different number of balls from different boxes. So to simplify things, we will pick balls corresponding to box number.
Thus, pick 1 ball from Box 1, 2 balls from box 2, 3 balls from box 3 and so on. You will have 55 balls altogether. Now, put them all in the balance.
If all balls were weighing accurate 10 grams, the total weight of the 55 balls would have been 550 grams. But one of the box must have had the defective balls.
Suppose if the defective balls were in box number 2, then the total weight will be 2 grams less than 550. If the defective balls were in box 8, the total weight will be less than 8 grams from 550. In this way, you will be able to identify which box has the defective balls. Did you answer this riddle correctly?
YES NO
Now the trick here is to pick different number of balls from different boxes. So to simplify things, we will pick balls corresponding to box number.
Thus, pick 1 ball from Box 1, 2 balls from box 2, 3 balls from box 3 and so on. You will have 55 balls altogether. Now, put them all in the balance.
If all balls were weighing accurate 10 grams, the total weight of the 55 balls would have been 550 grams. But one of the box must have had the defective balls.
Suppose if the defective balls were in box number 2, then the total weight will be 2 grams less than 550. If the defective balls were in box 8, the total weight will be less than 8 grams from 550. In this way, you will be able to identify which box has the defective balls. Did you answer this riddle correctly?
YES NO
Weight From A Barrel Riddle
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As Big As An Elephant Riddle
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