Clown And A Goat Riddle
Hint:
A 7 Foot Clown Riddle
A 7 foot clown stood up and held a water glass over his head. He accidentally dropped the glass, but nothing spilled. How is this possible?
Hint:
12 Clowns Riddle
On my way to the fair, I met a group. The group consisted of 12 clowns. Each clown had 30 cats, each cat had 20 hats, each hat had 41 rats, each rat had 4 mice, and each mice had 79 lice. How many of us were going to the fair?
Hint:
A Grandfather Clock Riddle
A grandfather clock chimes the appropriate number of times to indicate the hour, as well as chiming once at each quarter hour. If you were in another room and heard the clock chime just once, what would be the longest period of time you would have to wait in order to be certain of the correct time? Assuming you had absolutely no clue what time it was.
Hint:
You would have to wait 90 minutes between 12:15 and 1:45. Once you had heard seven single chimes, you would know that the next chime would be two chimes for 2 oclock.
In order for daylight savings time to come into play, you would have to manually set the clock back, which unless you did it with your eyes closed would indicate the time to you. Did you answer this riddle correctly?
YES NO
In order for daylight savings time to come into play, you would have to manually set the clock back, which unless you did it with your eyes closed would indicate the time to you. Did you answer this riddle correctly?
YES NO
Clock Calculator Bulb Riddle
Hint:
Find the value of one clock using the first equation. According to first equation, 9’o clock + 9’o clock + 3'o clock = 9 + 9 + 3 = 21.
Therefore; 1 Clock = 1
Using equation two, three calculators are equal to 30. Therefore, one calculator is equal to 10.
Also, the sum of numbers inside the calculator is 1 + 2 + 3 + 4 = 10.
Therefore, the value of the calculator depends on the sum of the numbers inside it.
According to equation three, 1 Bulb + 1 Bulb - 1 Bulb = 15.
Cancelling out the + and -; we get 1 Bulb with five lights = 15
.
Therefore, one bulb with one light = 3.
Bulb with four lights = 4 x 3 = 12.
The final equation is - 9’o clock + Calculator (1+2+2+4) x 3 bulbs (with four light rays each)
Translating the final equation into numbers - 9 + (1+2+2+4) x 3(12)
9 + 9 x 36 = 9 + 324 = 333.
Answer to 'Watch Calculator bulb' puzzle is 333. Did you answer this riddle correctly?
YES NO
Therefore; 1 Clock = 1
Using equation two, three calculators are equal to 30. Therefore, one calculator is equal to 10.
Also, the sum of numbers inside the calculator is 1 + 2 + 3 + 4 = 10.
Therefore, the value of the calculator depends on the sum of the numbers inside it.
According to equation three, 1 Bulb + 1 Bulb - 1 Bulb = 15.
Cancelling out the + and -; we get 1 Bulb with five lights = 15
.
Therefore, one bulb with one light = 3.
Bulb with four lights = 4 x 3 = 12.
The final equation is - 9’o clock + Calculator (1+2+2+4) x 3 bulbs (with four light rays each)
Translating the final equation into numbers - 9 + (1+2+2+4) x 3(12)
9 + 9 x 36 = 9 + 324 = 333.
Answer to 'Watch Calculator bulb' puzzle is 333. Did you answer this riddle correctly?
YES NO
Cookie Banana Clock Riddle
Hint:
Look closely and notice 2 things in above picture:
No. of chocolate pieces on each cookie
Time in clock
Cookie(10 chocs) + Cookie(10 chocs) + Cookie(10 chocs) = 30 ==> Cookie with 10 chocs = 10
2 bananas + 2 bananas + Cookie(10 chocs) = 14
4 Bananas + 10 =14 ==> Banana = 1
2 Bananas + Clock(3 O'clock) + Clock(3 O'clock) = 8 Did you answer this riddle correctly?
YES NO
No. of chocolate pieces on each cookie
Time in clock
Cookie(10 chocs) + Cookie(10 chocs) + Cookie(10 chocs) = 30 ==> Cookie with 10 chocs = 10
2 bananas + 2 bananas + Cookie(10 chocs) = 14
4 Bananas + 10 =14 ==> Banana = 1
2 Bananas + Clock(3 O'clock) + Clock(3 O'clock) = 8 Did you answer this riddle correctly?
YES NO
Closed Areas Riddle
Hint:
4
Look at how many closed areas there are.
9999 has 4 closed areas (the top of the '9')
8888 has 8 closed areas, the top and bottom parts of the 8 and there are no other digits
1816 has 3 closed areas, (top and bottom of 8 and bottom of 6, and it has 2 other digits ( 3*2=6)
1212 has 0 closed areas,(0*4=0) Did you answer this riddle correctly?
YES NO
Look at how many closed areas there are.
9999 has 4 closed areas (the top of the '9')
8888 has 8 closed areas, the top and bottom parts of the 8 and there are no other digits
1816 has 3 closed areas, (top and bottom of 8 and bottom of 6, and it has 2 other digits ( 3*2=6)
1212 has 0 closed areas,(0*4=0) Did you answer this riddle correctly?
YES NO
How Many Times A Day?
Hint:
22 times: 12:00:00, 1:05:27, 2:10:55, 3:16:22, 4:21:49, 5:27:16, 6:32:44, 7:38:11, 8:43:38, 9:49:05, 10:54:33. Each twice a day. Did you answer this riddle correctly?
YES NO
YES NO
Find Me In The Classroom Riddle
I have two hands. I have a face.
My hands go round and round.
I have the numbers 1 to 12
Instead of smiles and frowns.
Find me in the classroom.
What am I?
My hands go round and round.
I have the numbers 1 to 12
Instead of smiles and frowns.
Find me in the classroom.
What am I?
Hint:
Pirate Class Riddle
Hint:
Floor Math Riddle
Hint:
Snake Math Riddle
Hint:
Clumsy Pilgrims Riddle
Hint:
Hiding Behind Clovers Riddle
Hint:
Banana Clock Riddle
Hint: 1. Look closely at the clock.
2. Number of Bananas.
3. Some thing regarding the sides of the Shapes figure.
38
Logic :
From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38. Did you answer this riddle correctly?
YES NO
Logic :
From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38. Did you answer this riddle correctly?
YES NO
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