Shiny Red Nose
Hint:
Uncouth Dolf Riddle
Hint:
A Sound Economic Reason
You will know that I am coming from the jingle of my bell, but exactly who I am is not an easy thing to tell. Children, they adore me for they find me jolly, but I do not see them when the halls are decked with holly.
My job often leaves me frozen, I am a man that all should know, but I do not do business in times of sleet or ice or snow. I travel much on business, but no reindeer haul me around, I do all my traveling firmly on the ground.
I love the time of Christmas, but that's not my vocational season, and I assure that is because of a sound economic reason.
Who am I?
My job often leaves me frozen, I am a man that all should know, but I do not do business in times of sleet or ice or snow. I travel much on business, but no reindeer haul me around, I do all my traveling firmly on the ground.
I love the time of Christmas, but that's not my vocational season, and I assure that is because of a sound economic reason.
Who am I?
Hint:
An Icy Treat You Know
You will know that I am coming from the jingle of my bell, but exactly who I am is not an easy thing to tell. Children, they adore me for they find me jolly, but I do not see them when the halls are decked with holly.
My job often leaves me frozen, I am a man that all should know, but I do not do business in times of sleet or ice or snow. But I have a cold and icy treat you definitely know. I travel much on business, but no reindeer haul me around, I do all my traveling firmly on the ground.
I love the time of Christmas, but that's not my vocational season, and I assure that is because of a sound economic reason.
Who am I?
My job often leaves me frozen, I am a man that all should know, but I do not do business in times of sleet or ice or snow. But I have a cold and icy treat you definitely know. I travel much on business, but no reindeer haul me around, I do all my traveling firmly on the ground.
I love the time of Christmas, but that's not my vocational season, and I assure that is because of a sound economic reason.
Who am I?
Hint:
Santa's Transportation
Hint:
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
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