If We Did Not Exist Riddle
Hint:
The Chocolate Exchange
A confectionery shop owner allows children to purchase a chocolate in exchange of five wrappers of the same chocolate. Children from the locality consumed 77 chocolates in a month. Now, they all collected them together and decide to buy back chocolates.
How many chocolates do you think they can buy using those 77 wrappers ?
How many chocolates do you think they can buy using those 77 wrappers ?
Hint:
19... Explanation:
The children can purchase 19 chocolates in return.
Out of 77 wrappers, 75 will be used to buy 15 chocolates and two will be left spare.
The 15 chocolates will create 15 empty wrappers that can be exchanged to get three chocolates.
Three chocolates will return three wrappers which will help them buy another chocolate.
Now the wrapper from this chocolate and the two spare that were left earlier will get them another chocolate. 15 + 3 + 1 = 19 Did you answer this riddle correctly?
YES NO
The children can purchase 19 chocolates in return.
Out of 77 wrappers, 75 will be used to buy 15 chocolates and two will be left spare.
The 15 chocolates will create 15 empty wrappers that can be exchanged to get three chocolates.
Three chocolates will return three wrappers which will help them buy another chocolate.
Now the wrapper from this chocolate and the two spare that were left earlier will get them another chocolate. 15 + 3 + 1 = 19 Did you answer this riddle correctly?
YES NO
Gone Extinct Riddle
Hint:
The Excited Gardener Riddle
Hint:
Lost Without Being Stolen Riddle
They come out at night without being called, and are lost in the day without being stolen. What are they?
Hint:
This Does Not Exist Riddle
Hint:
The Expensive Restaurant Riddle
A man enters an expensive restaurant and orders a meal. When the waiter brings him his meal the man takes out a slip of paper and writes down 102004180, then leaves. The cashier hands the slip of paper to the cashier who understood it immediately.
What did the slip of paper say?
What did the slip of paper say?
Hint:
I =1, 0=Ought, 2=To, 0=Owe, 0=Nothing, 4=For, 1=I, 8=Ate, 0=Nothing. I Ought To Owe Nothing For I Ate Nothing. 102004180 Did you answer this riddle correctly?
YES NO
YES NO
Exotic Stores Riddle
Hint:
Living An Exhausting Life Riddle
Hint:
Swimming Exercises Riddle
Hint:
I Was Created By A Scientific Experiment Riddle
I was created by a scientific experiment but I’m not a drug
I have yellow skin but I’m not a banana
I have bolts but I’m not lightning
I’m brought to life by electricity but I’m not a light bulb
I’m 8 feet tall but I’m not a basketball player
What am I?
I have yellow skin but I’m not a banana
I have bolts but I’m not lightning
I’m brought to life by electricity but I’m not a light bulb
I’m 8 feet tall but I’m not a basketball player
What am I?
Hint:
A Policeman Sees Her
A woman with no driver license goes the wrong way on a one-way street and turns left at a corner with a 'no left' turn sign. A policeman sees her but does nothing. Why?
Hint:
Sleepy Policeman Riddle
Hint:
Excellent Volleyball Players Riddle
Hint:
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
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