Deter Riddles To Solve
Solving Deter Riddles
Here we've provide a compiled a list of the best deter puzzles and riddles to solve we could find.Our team works hard to help you piece fun ideas together to develop riddles based on different topics. Whether it's a class activity for school, event, scavenger hunt, puzzle assignment, your personal project or just fun in general our database serve as a tool to help you get started.
Here's a list of related tags to browse: Holiday Riddles Christmas Riddles For Kids God Riddles Unknown Riddles Math Brain Teasers Hard Brain Teasers Impossible Riddles Probability Riddles Secret Santa Riddles
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Laundry Detergent Santa Riddle
Hint:
Three Gods Riddle
Three gods A, B, and C are called, in no particular order, True, False, and Random. True always speaks truly, False always speaks falsely, but whether Random speaks truly or falsely is a completely random matter. Your task is to determine the identities of A, B, and C by asking three yes-no questions; each question must be put to exactly one god. The gods understand English, but will answer all questions in their own language, in which the words for yes and no are da and ja, in some order. You do not know which word means which.
What three questions can you ask?
What three questions can you ask?
Hint:
A possible solution is:
Q1: Ask god B, "If I asked you 'Is A Random?', would you say ja?". If B answers ja, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is indeed Random. Either way, C is not Random. If B answers da, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is not Random. Either way, you know the identity of a god who is not Random.
Q2: Go to the god who was identified as not being Random by the previous question (either A or C), and ask him: "If I asked you 'Are you False?', would you say ja?". Since he is not Random, an answer of da indicates that he is True and an answer of ja indicates that he is False.
Q3: Ask the same god the question: "If I asked you 'Is B Random?', would you say ja?". If the answer is ja, B is Random; if the answer is da, the god you have not yet spoken to is Random. The remaining god can be identified by elimination. Did you answer this riddle correctly?
YES NO
Q1: Ask god B, "If I asked you 'Is A Random?', would you say ja?". If B answers ja, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is indeed Random. Either way, C is not Random. If B answers da, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is not Random. Either way, you know the identity of a god who is not Random.
Q2: Go to the god who was identified as not being Random by the previous question (either A or C), and ask him: "If I asked you 'Are you False?', would you say ja?". Since he is not Random, an answer of da indicates that he is True and an answer of ja indicates that he is False.
Q3: Ask the same god the question: "If I asked you 'Is B Random?', would you say ja?". If the answer is ja, B is Random; if the answer is da, the god you have not yet spoken to is Random. The remaining god can be identified by elimination. Did you answer this riddle correctly?
YES NO
Age Of Three Daughters Riddles
I was visiting a friend one evening and remembered that he had three daughters. I asked him how old they were. The product of their ages is 72, he answered. Quizzically, I asked, Is there anything else you can tell me? Yes, he replied, the sum of their ages is equal to the number of my house. I stepped outside to see what the house number was. Upon returning inside, I said to my host, Im sorry, but I still cant figure out their ages. He responded apologetically, Im sorry, I forgot to mention that my oldest daughter likes strawberry shortcake. With this information, I was able to determine all three of their ages. How old is each daughter?
Hint:
3, 3, and 8. The only groups of 3 factors of 72 to have non-unique sums are 2 6 6 and 3 3 8 (with a sum of 14). The rest have unique sums:
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
The Parrot Doors Riddle
There are two doors. One door lead to Heaven, while the other leads to Hell. A parrot stands in front of each door. One parrot always tells a lie, while the other always tells the truth. You do not know which parrot or door is which. You are allowed to only ask one question. So, what one question must you ask to determine which door is which, so you can finally go to Heaven? (Hint: The question involves what one parrot would say about the doors.)
Hint:
It doesn't matter which parrot you ask the question to, but the question would be, "What door would the other parrot say is Heaven?". Then you would choose the other door. Did you answer this riddle correctly?
YES NO
YES NO
T Shirt And Jeans
When your jeans and T-shirts get dirty
Then you put them in this to get clean
Its filled with water and detergent
Which means that its a...
Then you put them in this to get clean
Its filled with water and detergent
Which means that its a...
Hint:
Metal Rods Riddle
You are in a room with two metal rods and no other metal. One of them is magnetized and the other is not.
How can you determine which one is magnetized and which is not?
How can you determine which one is magnetized and which is not?
Hint:
Solution 1: Touch the end of one bar (A) to the middle of the other bar (B) forming a 'T' shape. If the bars are attracted then bar A is magnetized and if they are not attracted then bar B is the magnet. This is because magnets have fields at the poles (the ends) but not in the middle. So the end would attract and middle would not.
Solution 2: Hang a rod from the ceiling and if it turns north than it is the magnetized rod. Did you answer this riddle correctly?
YES NO
Solution 2: Hang a rod from the ceiling and if it turns north than it is the magnetized rod. Did you answer this riddle correctly?
YES NO
Counterfeit Coins Riddle
You are given eight coins and told that one of them is counterfeit. The counterfeit one is slightly heavier than the other seven. Otherwise, the coins look identical. Using a simple balance scale, how can you determine which coin is counterfeit using the scale only twice?
Hint:
First weigh three coins against three others. If the weights are equal, weigh the remaining two against each other. The heavier one is the counterfeit. If one of the groups of three is heavier, weigh two of those coins against each other. If one is heavier, its the counterfeit. If theyre equal weight, the third coin is the counterfeit. Did you answer this riddle correctly?
YES NO
YES NO
Power Outage Riddle
Julie is going on an extended trip for three weeks. She lives in a remote area where there are frequent electrical power outages which can last up to three or four days. Julie has quite a bit of food in her freezer which would go bad if it thawed and then re-froze. She does have digital clock and a VCR which would flash 12:00 if the power went out. Unfortunately the clock and VCR flash even if the power only goes out for a few seconds. What can Julie do so that when she returns home she will be able to determine whether the power was out long enough to thaw her food? Asking a neighbor whether the power was out, isn't a reliable option because the nearest house is half a mile away, and one house may have power, while another house may have no power. She won't be able to have a neighbor check on her house every day, and has no one to house sit.
Hint:
One thing Julie could do is freeze a tray of ice-cubes, and turn the tray of ice upside down in her freezer. When she comes home, she should check the tray. If the ice cubes are still in the tray, the food is safe to eat. If the trays are empty, it's time to clean out the freezer. She will have to make a judgment call if the ice-cubes are only slightly thawed. Did you answer this riddle correctly?
YES NO
YES NO
The Elf Plans Riddle
Santa always leaves plans for his elves to determine the order in which the reindeer will pull his sleigh. This year, for the European leg of his journey, his elves are working to the following schedule, that will form a single line of nine reindeer:
Comet behind Rudolph, Prancer and Cupid. Blitzen behind Cupid and in front of Donder, Vixen and Dancer. Cupid in front of Comet, Blitzen and Vixen. Donder behind Vixen, Dasher and Prancer. Rudolph behind Prancer and in front of Donder, Dancer and Dasher. Vixen in front of Dancer and Comet. Dancer behind Donder, Rudolph and Blitzen. Prancer in front of Cupid, Donder and Blitzen. Dasher behind Prancer and in front of Vixen, Dancer and Blitzen. Donder behind Comet and Cupid. Cupid in front of Rudolph and Dancer. Vixen behind Rudolph, Prancer and Dasher.
Comet behind Rudolph, Prancer and Cupid. Blitzen behind Cupid and in front of Donder, Vixen and Dancer. Cupid in front of Comet, Blitzen and Vixen. Donder behind Vixen, Dasher and Prancer. Rudolph behind Prancer and in front of Donder, Dancer and Dasher. Vixen in front of Dancer and Comet. Dancer behind Donder, Rudolph and Blitzen. Prancer in front of Cupid, Donder and Blitzen. Dasher behind Prancer and in front of Vixen, Dancer and Blitzen. Donder behind Comet and Cupid. Cupid in front of Rudolph and Dancer. Vixen behind Rudolph, Prancer and Dasher.
Hint: Poor old Dancer was last.
Prancer
Cupid
Rudolph
Dasher
Blitzen
Vixen
Comet
Donder
Dancer Did you answer this riddle correctly?
YES NO
Cupid
Rudolph
Dasher
Blitzen
Vixen
Comet
Donder
Dancer Did you answer this riddle correctly?
YES NO
Desire To Achieve Riddle
This quality is a strong desire to achieve your goals. With determination and hard work you will have it. What is it?
Hint:
Dwarf Tickets Riddle
Recently, Snow White's seven dwarfs met up with three of their friends and went to the cinema to see Bambi. From the clues below, can you determine the order in which they stood in the ticket queue?
Grumpy was in front of Dopey. Stumpy was behind Sneezy and Doc. Doc was in front of Droopy and Happy.
Sleepy was behind Stumpy, Smelly and Happy.
Happy was in front of Sleepy, Smelly and Bashful.
Bashful was behind Smelly, Droopy and Sleepy.
Sneezy was in front of Dopey. Smelly was in front of Grumpy, Stumpy and Sneezy.
Dopey was in front of Droopy.
Sleepy was in front of Grumpy and Bashful.
Dopey was behind Sneezy, Doc and Sleepy.
Stumpy was in front of Dopey. Smelly was behind Doc.
Grumpy was in front of Dopey. Stumpy was behind Sneezy and Doc. Doc was in front of Droopy and Happy.
Sleepy was behind Stumpy, Smelly and Happy.
Happy was in front of Sleepy, Smelly and Bashful.
Bashful was behind Smelly, Droopy and Sleepy.
Sneezy was in front of Dopey. Smelly was in front of Grumpy, Stumpy and Sneezy.
Dopey was in front of Droopy.
Sleepy was in front of Grumpy and Bashful.
Dopey was behind Sneezy, Doc and Sleepy.
Stumpy was in front of Dopey. Smelly was behind Doc.
Hint:
Doc,
Happy,
Smelly,
Sneezy,
Stumpy,
Sleepy,
Grumpy,
Dopey,
Droopy, Did you answer this riddle correctly?
YES NO
Happy,
Smelly,
Sneezy,
Stumpy,
Sleepy,
Grumpy,
Dopey,
Droopy, Did you answer this riddle correctly?
YES NO
Five Bridesmaids Riddle
Five bridesmaids threw a shower for their bride. Each brought a gift and made a favorite food of the bride. They all arrived at different times, and during the wedding each was wearing a different color of her choice. Determine the gift and food each bridesmaid brought, the time she arrived, and what color she chose for her dress.
1. The bridesmaid with the painting had trouble getting it in her car, and the bridesmaid with the potato salad got lost on the way, so they were the last two to arrive.
2. Amanda hated the color green and potato salad.
3. Kourtney and Selena did not wear the blue dress and did not bring the turkey sandwiches.
4. Stacie arrived before the bridesmaid with the painting, but after the bridesmaid who brought the sheets, and the bridesmaid who made the cheese dip.
5. The bridesmaid with a blue dress arrived 10 minutes before the bridesmaid who brought the sandwiches.
6. The bridesmaid with the veggie tray arrived 25 minutes after the bridesmaid who brought flatware, but before the bridesmaid who would be wearing a blue dress.
7. The five bridesmaids arrived in the following order: The one who baked the cake, Amanda, the one who would be wearing a yellow dress, the one with a toaster for a gift, and the one who arrived last.
8. Selena brought a cake with green frosting, the same color as her dress.
9. Amanda brought pink sheets as a gift to the bride, but she did not like pink for herself.
1. The bridesmaid with the painting had trouble getting it in her car, and the bridesmaid with the potato salad got lost on the way, so they were the last two to arrive.
2. Amanda hated the color green and potato salad.
3. Kourtney and Selena did not wear the blue dress and did not bring the turkey sandwiches.
4. Stacie arrived before the bridesmaid with the painting, but after the bridesmaid who brought the sheets, and the bridesmaid who made the cheese dip.
5. The bridesmaid with a blue dress arrived 10 minutes before the bridesmaid who brought the sandwiches.
6. The bridesmaid with the veggie tray arrived 25 minutes after the bridesmaid who brought flatware, but before the bridesmaid who would be wearing a blue dress.
7. The five bridesmaids arrived in the following order: The one who baked the cake, Amanda, the one who would be wearing a yellow dress, the one with a toaster for a gift, and the one who arrived last.
8. Selena brought a cake with green frosting, the same color as her dress.
9. Amanda brought pink sheets as a gift to the bride, but she did not like pink for herself.
Hint:
Selena; green; flatware; cake; 2:50
Amanda; purple; sheets; veggie tray; 3:15
Kourtney; yellow; towels; cheese dip; 3:20
Stacie; blue; toaster; potato salad; 3:35
Stephanie; pink; painting; turkey sandwiches; 3:45 Did you answer this riddle correctly?
YES NO
Amanda; purple; sheets; veggie tray; 3:15
Kourtney; yellow; towels; cheese dip; 3:20
Stacie; blue; toaster; potato salad; 3:35
Stephanie; pink; painting; turkey sandwiches; 3:45 Did you answer this riddle correctly?
YES NO
Three Switches Riddle
Three switches outside a windowless room are connected to three light bulbs inside the room. How can you determine which switch is connected to which bulb if you are only allowed to enter the room once?
Hint:
Switch on the first switch, leave it for a minute, and then switch it off again. Then switch on the second switch and enter the room. The second switch will be connected to the light that is on, the first switch will be connected to the light with the warm bulb, and the third switch will be connected to the light with the cold bulb. Did you answer this riddle correctly?
YES NO
YES NO
The Barrel With No Lid
There is a barrel with no lid and some beer in it. "This barrel is more than half full," said Chuck. "No it's not," say Joe. "It's less than half full." Without any measuring implements and without removing any beer from the barrel, how can they easily determine who is correct?
Hint:
They must tilt the barrel until the beer reaches the rim of the barrel. If they can see the bottom of the barrel then it is less than half full. Did you answer this riddle correctly?
YES NO
YES NO
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