I AM A POSIT RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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I Am A Posit Riddles To Solve

Solving I Am A Posit Riddles

Here we've provide a compiled a list of the best i am a posit puzzles and riddles to solve we could find.

Our team works hard to help you piece fun ideas together to develop riddles based on different topics. Whether it's a class activity for school, event, scavenger hunt, puzzle assignment, your personal project or just fun in general our database serve as a tool to help you get started.

Here's a list of related tags to browse: Number Riddles Math Riddles Picture Riddles Running Riddles Tricky Riddles Short Riddles Ghost Riddles

The results compiled are acquired by taking your search "i am a posit" and breaking it down to search through our database for relevant content.

Browse the list below:

Positive Numbers

Hint:
1, 2, and 3.
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Participating In A Race

Hint: It's not first place.
If you answer that you are first, then you are absolutely wrong! If you overtake the second person and you take his place, you are second!
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Soccer Ghosts Riddle

Hint:
Ghoulie!
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It Was Murder Riddle

Hint:
At each floor, he did the same task of opening the window and flipping the coin. If it was a suicide, then at least the window at any of the floors must have been left open by the person who jumped off. The situation only suggests that someone pushed him off and then closed the window again.
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Bruce's Little League Team

Hint:
He was the bat-boy.
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A Walk In The Desert Riddle

Hint:
The third man. This is because he knows there are only two of each color cap. If the man behind him (the fourth man) saw two caps that were the same color in front of him, he would know that his own must be the opposite. However, because the caps alternate in color. The fourth man has only a 50% chance of getting his hat color correct, so therefore he stays quiet. The third man realizes that the fourth man is quiet because he must not see two caps of the same color in front of him, otherwise the fourth man would say the opposite of the caps in front of him. Therefore, the third man presumes his own cap must be the opposite of the mans in front of him, and his presumption is correct. Under this same logic, after the third man speaks his color hat, the second man, even though he sees only wall, would be the next to go free, because he knows his cap must be the opposite of whichever color the third mans cap was.
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The Card Trick Riddle

Hint:
The answer is very simple. All she had to do is take the fifteen cards from the top and reverse them. This would make another pile out of that and there will be two piles - one of 15 cards and one of 37 cards. Also both of them will have the same number of inverted cards.

Just think about it and if the mathematical explanation will help you understand better, here it is.

Assume that there were p inverted cards initially in the top 15 cards. Then the remaining 37 cards will hold 15-p inverted cards.
Now when she reverses the 15 cards on the top, the number of inverted cards will become 15-p and thus the number of inverted cards in both of the piles will become same.
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The Liar's Village Riddle

Hint:
The man asks the stranger the path back to his own village. If the stranger was from village of truths, he takes him there. If he was from the village of liars, he will still take him to the village of truths as he would be compelled to lie.
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The Baseball Cat Riddle

Hint:
Cat-cher!
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Mad Mick Riddle

Hint:
Mick knew Howard was lying about being at the football game because in American football it's impossible to score just 1 point. A score of 2 is the lowest possible score (awarded for a safety). In fact, 1 is the only impossible score in football. You can score 2 points for a safety, 3 points for a field goal and 6 points for a touchdown, with an extra point for the field goal. You also have the option to go for another touchdown for a 2-point conversion. With 2, 3, 6 and 7 you can generate any other number except for 1.

For example, here are ways a team could score from 2 to 10 points.
2 = safety
3 = field goal
4 = 2 + 2
5 = 3 + 2
6 = touchdown
7 = touchdown and extra point attempt
8 = touchdown and two point conversion
9 = touchdown and field goal
10 = touchdown, extra point attempt and field goal
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Under The Cup Riddle

Hint: Write down the possibilities. Remember that there are only three cups, so if the rightmost cup wasn't touched...
The rightmost cup.

The rightmost cup has a half chance of holding the coin, and the other cups have a quarter chance.

Pretend that Os represent cups, and Q represents the cup with the coin.

The game starts like this:

OOQ

Then your friend switches the rightmost cup with another, giving two possibilities, with equal chance:

OQO
QOO

Your friend then moves the cups again, but doesn't touch the rightmost cup. The only switch possible is with the leftmost cup and the middle cup. This gives two possibilities with equal chance:

QOO
OQO

Lastly, your friend switches the rightmost cup with another cup. If the first possibility shown above was true, there would be two possibilities, with equal chance:

OOQ
QOO

If the second possibility shown above (In the second switch) was true, there would be two possibilities with equal chance:

OOQ
OQO

This means there are four possibilities altogether, with equal chance:

OOQ
QOO
OOQ
OQO

This means each possibility equals to a quarter chance, and because there are two possibilities with the rightmost cup having the coin, there is a half chance that the coin is there.
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100 Blank Cards Riddle

Hint: Perhaps thinking in terms of one deck is the wrong approach.
Yes!

A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."

Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).

This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.

Obviously, you have to have at least $40 to start in order to apply this strategy effectively.
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