THE FIRST MAN IS IN THE HOUSE HE IS WEARING A MA RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Riddles and Answers © 2024

Shiny And Metallic

Hint:
A bell
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The Start Of Church And The End Of School

Hint:
They are bells
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Found In Tall Buildings

Hint:
A elevator
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Found Beneath A Chimney

Hint:
A fireplace
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Born In Mourning

Hint:
A tombstone
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Found In A Graveyard Riddle

Hint:
Tombstone
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Mortal Privation Riddle

Hint:
A tombstone
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Webbed Wings That Can Fly

Hint:
Its a bat
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The Youngest Level Of Girl Scouts

Hint:
A daisy
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A Character In Thomas And Friends

Hint:
Im a daisy
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The Walls Of Jericho

Hint:
Joshua
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Adams Rib Riddle

Hint:
Eve
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The Loaded Revolver Riddle

Hint:
Henry should have Gretchen pull the trigger again without spinning.

We know that the first chamber Gretchen fired was one of the four empty chambers. Since the bullets were placed in consecutive order, one of the empty chambers is followed by a bullet, and the other three empty chambers are followed by another empty chamber. So if Henry has Gretchen pull the trigger again, the probability that a bullet will be fired is 1/4.

If Gretchen spins the chamber again, the probability that she shoots Henry would be 2/6, or 1/3, since there are two possible bullets that would be in firing position out of the six possible chambers that would be in position.
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Two In A Row Riddle

Hint: Who does he need to beat to win?
Father-mother-father

To beat two games in a row, it is necessary to win the second game. This means that it would be to his advantage to play the second game against the weaker player. Though he plays his father twice, he has a higher chance of winning by playing his mother second.
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Knights Of The Round Table Riddle

Hint: Does it matter if they are sitting clockwise or counterclockwise? Or where the oldest sits?
The odds are 11:1. (The probability is 1/12.)

Imagine they sat down in age order, with each person randomly picking a seat. The first person is guaranteed to pick a seat that "works". The second oldest can sit to his right or left, since these five can sit either clockwise or counterclockwise. The probability of picking a seat that works is thus 2/4, or 1/2. The third oldest now has three chairs to choose from, one of which continues the progression in the order determined by the second person, for a probability of 1/3. This leaves two seats for the fourth oldest, or a 1/2 chance. The youngest would thus be guaranteed to sit in the right seat, since there is only one seat left. This gives 1 * 1/2 * 1/3 * 1/2 * 1 = 1/12, or 11:1 odds against.
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