Tin Woodsman In The Morning Riddle
Hint:
Hiding In The Woods
Hint:
Party Poison Riddle
In a party, two friends ordered single malt whiskey on the rocks. One of them drank five of the same in the time when his friend was able to drink only one. Immediately after, his friend died. However the other one was feeling completely normal.
Both the drinks were poisoned. How did the guy who drink five glasses survived?
Both the drinks were poisoned. How did the guy who drink five glasses survived?
Hint:
The guy who drank five glasses survived because the poison was in the middle of ice cubes. He drank rapidly and thus the ice had no chance to melt in his drink while the other one drank slowly and thus enough ice had melted in his drink to poison it heavily and he died. Did you answer this riddle correctly?
YES NO
YES NO
Love At A Funeral
A girl, at the funeral of her mother, met a guy whom she did not know. She fell for him and just kept looking at him. Sometime later she realized that the guy is gone and she forgot to take the number of the guy and now she can't find him. A few days later she killed her elder brother. What is her motive in killing her brother?
Hint:
She was hoping that the guy would appear at the funeral again Did you answer this riddle correctly?
YES NO
YES NO
Chittery Sweet Riddle
I make your teeth go chitter,
At the same time I am sweet,
Some of my friends are bitter,
But people them do eat.
My name constists of two words,
With a hyphen inbetween,
One part is food for owl-birds,
The other one is cold, if you know what I mean.
So be careful when you choose me,
For I am more than I seem,
But dont hesitate to take me,
I see it in your eyes, the gleam
What am I?
At the same time I am sweet,
Some of my friends are bitter,
But people them do eat.
My name constists of two words,
With a hyphen inbetween,
One part is food for owl-birds,
The other one is cold, if you know what I mean.
So be careful when you choose me,
For I am more than I seem,
But dont hesitate to take me,
I see it in your eyes, the gleam
What am I?
Hint:
Missing Dollar Riddle
Three guests check into a hotel room. The clerk says the bill is $30, so each guest pays $10. Later the clerk realizes the bill should only be $25. To rectify this, he gives the bellhop $5 to return to the guests. On the way to the room, the bellhop realizes that he cannot divide the money equally. As the guests didn't know the total of the revised bill, the bellhop decides to just give each guest $1 and keep $2 for himself. Each guest got $1 back: so now each guest only paid $9; bringing the total paid to $27. The bellhop has $2. And $27 + $2 = $29 so, if the guests originally handed over $30, what happened to the remaining $1?
Hint: Make a list of all of the people involved and how much money they ended up with/spent.
The $9 paid by each guest accounts for the $2 that went to the bellhop. So rather than adding $27 to the $2 kept by the bellhop, the $27 accounts for the bellhops money. The $27 plus the $3 kept by the guests does add up to $30. Did you answer this riddle correctly?
YES NO
YES NO
On The Deck Of A Ship
Imagine you are on the deck of a ship in the middle of the ocean and a lady walks by you, stops, and pushes you overboard. SPLASH! By the time you realized where you were, the ship was out of sight. You struggle to keep your head above water, but when you look around you see a shark coming straight towards you. What do you do?
Hint:
A Round House
The police are called to a round house where a man is found dead with a knife wound to the chest. The police investigate and narrow down the suspects to three people: The maid, the wife, and the butcher. When questioned for alibis, the wife said, "I was out buying a dress with my friends, and I found my husband dead upon my return." The butcher said, "I was searching the cupboards for some vegetables to serve for lunch." The maid said, "I was in the other room, dusting the corners." The maid was then arrested. How did the police know it was her?
Hint:
Nothing More Than Sand
You think you can fly right out of me. Yet when you try, you realize you can't, and that the air in front of you is nothing more than sand. What am I?
Hint:
99 Points Riddle
While out bowling with his friends, a man managed to throw eight strikes (all ten pins knocked down in a single throw) and not a single gutter ball during the entire game. To his amazement, his final score was only 99 points! Assuming there were no penalties or fouls, can you come up with a ten frame scorecard with eight strikes and a final score of only 99 points?
Hint: If you knock down a single pin, for example at the far left of the back row, then repeat the same identical shot on your second throw, you'll score 0 points for your second throw (because there's no pin there anymore), but it's not a gutter ball as the s
Just to reiterate the hint, if you knock down a single pin, for example at the far left of the back row, then repeat the same identical shot on your second throw, you'll score 0 points for your second throw (because there's no pin there anymore), but it's not a gutter ball as the shot did not enter the gutter. Did you answer this riddle correctly?
YES NO
YES NO
Three Hunters Riddle
Three hunters just finished hunting for the night and went down to a motel. They couldn't afford three separate rooms so they decided to get one room, and split the price. The room costed $30. (It was a run-down motel, but that's not the point.) So, they each paid their $10 and went to their room. The employee running the check-in/ check-out desk realized that she overcharged them, so she sent a bell-boy to return the extra cash. On the way the bell-boy wondered how to equally split the money... he wasnt the smart type so he just slid $2 into his pocket as a tip. That way the hunters would get $1 each. Well... they got their $1 each right? So in the end they all payed $9 each, which makes $27. Plus the $2 in the bell-boy's pocket makes $29...
What happened to the last dollar?
What happened to the last dollar?
Hint:
They didn't really pay $9 each, remember? The bell-boy was too lazy to add up the actual sum that they would pay. They reeeally payed about a $8.66 each. So $8.66 times the three of them equals about $25, plus the $5 in the bell-boys equals $30 Did you answer this riddle correctly?
YES NO
YES NO
The Youngest Level Of Girl Scouts
I am the youngest level of Girl Scouts
Im a flower and a females name
Im a railcar in Thomas And Friends
And a Princess in a Mario game
What am I?
Im a flower and a females name
Im a railcar in Thomas And Friends
And a Princess in a Mario game
What am I?
Hint:
Under The Cup Riddle
You decide to play a game with your friend where your friend places a coin under one of three cups. Your friend would then switch the positions of two of the cups several times so that the coin under one of the cups moves with the cup it is under. You would then select the cup that you think the coin is under. If you won, you would receive the coin, but if you lost, you would have to pay.
As the game starts, you realise that you are really tired, and you don't focus very well on the moving of the cups. When your friend stops moving the cups and asks you where the coin is, you only remember a few things:
He put the coin in the rightmost cup at the start.
He switched two of the cups 3 times.
The first time he switched two of the cups, the rightmost one was switched with another.
The second time he switched two of the cups, the rightmost one was not touched.
The third and last time he switched two of the cups, the rightmost one was switched with another.
You don't want to end up paying your friend, so, using your head, you try to work out which cup is most likely to hold the coin, using the information you remember.
Which cup is most likely to hold the coin?
As the game starts, you realise that you are really tired, and you don't focus very well on the moving of the cups. When your friend stops moving the cups and asks you where the coin is, you only remember a few things:
He put the coin in the rightmost cup at the start.
He switched two of the cups 3 times.
The first time he switched two of the cups, the rightmost one was switched with another.
The second time he switched two of the cups, the rightmost one was not touched.
The third and last time he switched two of the cups, the rightmost one was switched with another.
You don't want to end up paying your friend, so, using your head, you try to work out which cup is most likely to hold the coin, using the information you remember.
Which cup is most likely to hold the coin?
Hint: Write down the possibilities. Remember that there are only three cups, so if the rightmost cup wasn't touched...
The rightmost cup.
The rightmost cup has a half chance of holding the coin, and the other cups have a quarter chance.
Pretend that Os represent cups, and Q represents the cup with the coin.
The game starts like this:
OOQ
Then your friend switches the rightmost cup with another, giving two possibilities, with equal chance:
OQO
QOO
Your friend then moves the cups again, but doesn't touch the rightmost cup. The only switch possible is with the leftmost cup and the middle cup. This gives two possibilities with equal chance:
QOO
OQO
Lastly, your friend switches the rightmost cup with another cup. If the first possibility shown above was true, there would be two possibilities, with equal chance:
OOQ
QOO
If the second possibility shown above (In the second switch) was true, there would be two possibilities with equal chance:
OOQ
OQO
This means there are four possibilities altogether, with equal chance:
OOQ
QOO
OOQ
OQO
This means each possibility equals to a quarter chance, and because there are two possibilities with the rightmost cup having the coin, there is a half chance that the coin is there. Did you answer this riddle correctly?
YES NO
The rightmost cup has a half chance of holding the coin, and the other cups have a quarter chance.
Pretend that Os represent cups, and Q represents the cup with the coin.
The game starts like this:
OOQ
Then your friend switches the rightmost cup with another, giving two possibilities, with equal chance:
OQO
QOO
Your friend then moves the cups again, but doesn't touch the rightmost cup. The only switch possible is with the leftmost cup and the middle cup. This gives two possibilities with equal chance:
QOO
OQO
Lastly, your friend switches the rightmost cup with another cup. If the first possibility shown above was true, there would be two possibilities, with equal chance:
OOQ
QOO
If the second possibility shown above (In the second switch) was true, there would be two possibilities with equal chance:
OOQ
OQO
This means there are four possibilities altogether, with equal chance:
OOQ
QOO
OOQ
OQO
This means each possibility equals to a quarter chance, and because there are two possibilities with the rightmost cup having the coin, there is a half chance that the coin is there. Did you answer this riddle correctly?
YES NO
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
Making Calls With Skeletons
Hint:
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