Polar Bear Dice Riddle
Polar bears around an ice hole, like petals around a rose. The game is in the name, and the name is in the game. How many polar bears are there?" Johnny asked as he rolled the five dice. The first roll produced 4, 6, 1, 3, 2. "Six," said Billy. "No, two," Johnny replied. The next roll was 5, 1, 5, 2, 4. "Four?" said Billy. "No, eight," Johnny said. The next rolls were 3, 5, 3, 1, 2. There were 8 polar bears. The next rolls were 6, 2, 1, 2, 4. There were no polar bears. How does Johnny figure out the number of polar bears?
Hint: A rose by any other name...could be a die?
Dice all look the same. On a die, the 1, 3, and 5 all have a dot in the center. The 3 has 2 dots on either side of the center dot, and the 5 has 4 dots around the center dot. Johnny simply counted the number of dots around the outside. A "3" has 2 "petals around the rose, or polar bears around an ice hole." The "5" has 4 "petals" or "polar bears." Roll some dice and it will become clear!! Did you answer this riddle correctly?
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This Lady Is All In Riddle
Black's 100, blue's 10, red's 5. This lady is all in. If to pass this door you strive, Find the total the dame's holdin.'
Hint: There are 3 colors. Blue, red and black.
From these, we must find at the correct answer. What about the poker chips were on the table?
What Goes Up And Never Comes Down Riddle
Hint:
The Mooing Dog Riddle
Hint:
The Jacksons Wedding Day Riddle
When the Jacksons married 18 years ago, Mr. Jackson was three times as old as his wife, and today he is just twice as old as she?
How old was Mrs. Jackson on the wedding day?
How old was Mrs. Jackson on the wedding day?
Hint:
Mr. Jackson was 54 and his wife was 18. Now hes 72 and his wife 36. Did you answer this riddle correctly?
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YES NO
Saturday And Sunday I Am Big
Saturday and Sunday, I am big. Tuesday through Thursday, I am small. Monday and Friday, I am non-existent. What am I?
Hint: The answer lies within the riddle
Making Ten Riddle
Hint:
Yes it is possible in Roman Numerals. In Roman Numerals,
9 = IX
10 = X
11 = XI
Thus by removing one from 9, you are getting 10 and by removing one from 11, you are getting 10 again. Did you answer this riddle correctly?
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9 = IX
10 = X
11 = XI
Thus by removing one from 9, you are getting 10 and by removing one from 11, you are getting 10 again. Did you answer this riddle correctly?
YES NO
Combination Value Riddle
The letters A through H can be assigned the following values to make all the equations true. Find the right combination of letter values.
Values: 1, 4, 5, 7, 9, 14, 16, 21
C + F = G
A + C = F
B + G = D
B + E = H
D + F = H
Values: 1, 4, 5, 7, 9, 14, 16, 21
C + F = G
A + C = F
B + G = D
B + E = H
D + F = H
Hint:
You Start With 1000 Riddle
You start with 1000 then add 40 add another 1000 then add 30 add another 1000 then add 20 add one more 1000 then add 10 what is your answer?
Hint:
If you said 5000 you're wrong! The answer is 4100, how?
1000 + 40 = 1040
1040 + 1000 + 30 = 2070
2070 + 1000 + 20 = 3090
3090 + 1000 = 4090
4090 + 10 = 4100 Did you answer this riddle correctly?
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1000 + 40 = 1040
1040 + 1000 + 30 = 2070
2070 + 1000 + 20 = 3090
3090 + 1000 = 4090
4090 + 10 = 4100 Did you answer this riddle correctly?
YES NO
A Dash At 20 And A Dot At 60
Hint: It's not a clock.
Eye Test How Many 3s Riddle
Hint:
The answers for 'eye test how many 3s' puzzle ranges from 15 to 21. At first glance, most people only notice 15 threes in the image. First, you might notice that there are two threes on the number pad, as the number eight has also been replaced by a three. Then there are eight threes in the phone number. Many also notice that the battery charge is at 33% and the time is 3:33 PM.
However, if one looks closer at the name underneath the phone number, they will find three more 3s. This gives a total of 18 3s in the image. But there is one more hidden three that even observant people fail to notice. Underneath the number four on the keypad, the letter 'I' has been replaced with three as well. So, the total number of 3s in the image is 19.
However, depending on your interpretation of the puzzle, the number of 3s can also rise to 21. At the top left of the image, the bar signal and wifi signal also have three bars. Some people also consider the two signals to be a part of the riddle and raise the number of 3s to 21. So, the correct answer can be 19 or 21, depending on your interpretation of the question. Did you answer this riddle correctly?
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However, if one looks closer at the name underneath the phone number, they will find three more 3s. This gives a total of 18 3s in the image. But there is one more hidden three that even observant people fail to notice. Underneath the number four on the keypad, the letter 'I' has been replaced with three as well. So, the total number of 3s in the image is 19.
However, depending on your interpretation of the puzzle, the number of 3s can also rise to 21. At the top left of the image, the bar signal and wifi signal also have three bars. Some people also consider the two signals to be a part of the riddle and raise the number of 3s to 21. So, the correct answer can be 19 or 21, depending on your interpretation of the question. Did you answer this riddle correctly?
YES NO
Circle With 5 In The Middle Riddle
Hint:
If Eleven Plus Two Equals One Riddle
Hint:
11 o'clock plus 2 hours = 1 o'clock
9 o'clock plus 5 hours = 2 o'clock Did you answer this riddle correctly?
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9 o'clock plus 5 hours = 2 o'clock Did you answer this riddle correctly?
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I Have 50 Rs Riddle
Hint:
50 - 20 = 30
30 - 15 = 15
15 -9 = 6
6 - 6 = 0
20 + 15 +9 + 6 = 50 Did you answer this riddle correctly?
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30 - 15 = 15
15 -9 = 6
6 - 6 = 0
20 + 15 +9 + 6 = 50 Did you answer this riddle correctly?
YES NO
How Many Batteries?
You have a flashlight that takes 2 working batteries. You have 8 batteries but only 4 of them work.
What is the fewest number of pairs you need to test to guarantee you can get the flashlight on?
What is the fewest number of pairs you need to test to guarantee you can get the flashlight on?
Hint:
7. If you break the batteries into 3 groups: Two groups of 3 and one group of 2. By doing this you guarantee that one of the groups has 2 working batteries. Both of the groups of 3 have 3 possible combinations of 2 batteries and the group of 2 only has 1 combination. So, 3 + 3 + 1 = 7 tries at most to find two working batteries. Did you answer this riddle correctly?
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