The Wild Wild West
In the Wild West, you challenge two cowboys - Hunter Jack and Sharp Shooter Leo into a death match. They being better shooter than you readily accept your challenge. But they don't want to waste bullets and thus lay down a certain rules that are accepted by you as well. Here are the rules:
1) Everyone shoot in a given order till only one is left.
2) Everyone shoot only once when his turn arrive.
3) If any one of you is injured, the other two will finish him off together.
4) The worst shooter gets to shoot first (which is you) and the best one shoots at the last.
Now, what tactics will you use if you know that you hit every third shot of yours, Jack hits every second shot and Leo hits every shot?
1) Everyone shoot in a given order till only one is left.
2) Everyone shoot only once when his turn arrive.
3) If any one of you is injured, the other two will finish him off together.
4) The worst shooter gets to shoot first (which is you) and the best one shoots at the last.
Now, what tactics will you use if you know that you hit every third shot of yours, Jack hits every second shot and Leo hits every shot?
Hint:
The best thing for you will be to shoot your first shot in air.
If you try to shoot at Jack and hits him by chance, Leo always hits on the target and you are dead.
If you choose to shoot at Leo and hits him by chance, then there is a fifty percent chance that Jack will hit you.
If you shoot in air, the next turn is of Jack and he knows that Leo is a better shooter which means that he will shoot at him. If he misses, he is definitely dead as Leo will shoot on him coz he shot at him. The next turn will be yours and you stand a 1/3rd chance of hitting him. Also if, he is able to hit Leo. The next chance is yours again and you can try the 1/3rd probability of hitting over Jack.
This is the best situation that you can face. At every other possible way, you will face a worse situation for sure. Did you answer this riddle correctly?
YES NO
If you try to shoot at Jack and hits him by chance, Leo always hits on the target and you are dead.
If you choose to shoot at Leo and hits him by chance, then there is a fifty percent chance that Jack will hit you.
If you shoot in air, the next turn is of Jack and he knows that Leo is a better shooter which means that he will shoot at him. If he misses, he is definitely dead as Leo will shoot on him coz he shot at him. The next turn will be yours and you stand a 1/3rd chance of hitting him. Also if, he is able to hit Leo. The next chance is yours again and you can try the 1/3rd probability of hitting over Jack.
This is the best situation that you can face. At every other possible way, you will face a worse situation for sure. Did you answer this riddle correctly?
YES NO
The Murder Of Ray Whitcombe
Ray Whitcombe is found dead in his office at his desk. The police have narrowed the suspects down to three people: Mrs. Barbara Whitcombe, Ray's wife; Mr. Jason McCubbins, Ray's business partner; and Mr. Harold Nichols, Ray's best friend. All three visited Mr. Whitcombe the day of his murder, but all three provide the police with stories of explanation as to the reason for their visit. Police found Mr. Whitcombe with his wrist watch still on his right arm, a torn up picture of his wife laying on the floor beside the trash can, and an ink pen in his right hand. On the desk, the police found a name plate, a telephone that was off the hook, and a personal calendar turned to the July 5th page with 7B91011 written on it. After examining this evidence, the police knew their suspect. Who was it?
Hint:
Jason McCubbins, Ray's business partner. The calendar is the clue to solving this murder. The police realized that since Mr. Whitcombe was wearing his watch on his right arm, he must be left handed. But the pen was found in his right hand. Realizing that the number on the calendar was written in a hurry and with his opposite hand, police matched the written number with the months of the year. So the B was an 8, thereby giving us 7-8-9-10-11: July, August, September, October, November. Use the first letter of each month and it spells J-A-S-O-N. Did you answer this riddle correctly?
YES NO
YES NO
The Three Children Riddle
A guy and his wife went to the store and left their three children at home. When they returned, all of his children where dead. The au pair said she was reading the newspaper. The maid said she was making the beds, and the butler said he was putting away the groceries. Who did it?
Hint:
The butler because the parents went to the store to get the groceries. Therefore, they were out of groceries and there was none to put away. Did you answer this riddle correctly?
YES NO
YES NO
Five Best Friends
There are five best friends. They all go to a salon. One gets a touch up, one gets there hair done, one gets a manicure, one gets a pedicure, one got her eyebrows done. When they go back to there hotel they fall asleep. 10 minutes later they here a scream. When they turned on the light there was a dead man on the floor with a knife beside him. They called the police and the police arrested the murderer. Who did it and how did they know?
Hint:
It was the girl who got her hair done because before the other girls got there makeover they had to wash there hands! Did you answer this riddle correctly?
YES NO
YES NO
A Round Hotel
There is a round hotel. A famous person walks in. The lights go off. When the lights turn back on the famous person is dead. Who did it, the waiter dusting the corner, the chef holding cleavers, or the crazy customer?
Hint:
The Round House Riddle
A lady is unlocking the door to her round house when she hears a scream. She goes in and finds her husband dead. The Butcher says, "I was chopping meat." The Cook says, "I was cooking fish." The maid says, "I was sweeping the corners." Who killed the husband?
Hint:
Sherlock Holmes And The Case Of Ganpat
Ganpat is found dead in his office at his desk.
Sherlock Holmes was working on this case and have narrowed the suspects down to three people:
1. His Friend Mr Rakesh Gupta
2. Ganpat's wife "Bhawna"
3. His Secretary "Jason Kumar"
All three suspects visited ganpat on the day of his murder for various reason as they told to sherlock.
As we know where police failed , sherlock comes.
He was able to find a note at the corner of the wall. "7B91011" was written on it.
Sherlock waste no time in announcing the killer. Who was the killer ?
Sherlock Holmes was working on this case and have narrowed the suspects down to three people:
1. His Friend Mr Rakesh Gupta
2. Ganpat's wife "Bhawna"
3. His Secretary "Jason Kumar"
All three suspects visited ganpat on the day of his murder for various reason as they told to sherlock.
As we know where police failed , sherlock comes.
He was able to find a note at the corner of the wall. "7B91011" was written on it.
Sherlock waste no time in announcing the killer. Who was the killer ?
Hint:
Jason Kumar
The number on the calendar was written in a hurry.Sherlock matched the written number with the months of the year.
So the B was an 8, thereby giving us 7-8-9-10-11: July, August, September, October, November.
Use the first letter of each month and it spells J-A-S-O-N. Did you answer this riddle correctly?
YES NO
The number on the calendar was written in a hurry.Sherlock matched the written number with the months of the year.
So the B was an 8, thereby giving us 7-8-9-10-11: July, August, September, October, November.
Use the first letter of each month and it spells J-A-S-O-N. Did you answer this riddle correctly?
YES NO
3 Men Hunting
A girl and a boy were out one night. They were in the woods, and they saw 3 men hunting. Next day the girl and boy were found dead. Why is this?
Hint:
It was Halloween night and they were dressed up as deer. Did you answer this riddle correctly?
YES NO
YES NO
If You Lose It You Die
Hint:
Protect And Destroy
I am called white. My duty is to protect and destroy. All it takes is a sneeze and I will destroy... at the sign of a cut, I will come to protect. I will fight to my death... no matter how insignificant it may be. I am very helpful yet you can't see me. What am i?
Hint:
Dying Of Thirst
You are dying of thirst walking through me. You starve to death over night. You find nothing in my path. Ambiguous and furious in my sight. Kill and threatened by my people. I am?
Hint:
Sand
Desert is the answer to this riddle. Kill and threatened by my people are talking about animals that live in the desert. Did you answer this riddle correctly?
YES NO
Desert is the answer to this riddle. Kill and threatened by my people are talking about animals that live in the desert. Did you answer this riddle correctly?
YES NO
Hundreds Of These In A Graveyard
There are hundreds of these in a graveyard
But dead bodies it is not
Its what contains all the info as to
Whos in each burial plot
What is it?
But dead bodies it is not
Its what contains all the info as to
Whos in each burial plot
What is it?
Hint:
Roll The Dice
A gambler goes to bet. The dealer has 3 dice, which are fair, meaning that the chance that each face shows up is exactly 1/6.
The dealer says: "You can choose your bet on a number, any number from 1 to 6. Then I'll roll the 3 dice. If none show the number you bet, you'll lose $1. If one shows the number you bet, you'll win $1. If two or three dice show the number you bet, you'll win $3 or $5, respectively."
Is it a fair game?
The dealer says: "You can choose your bet on a number, any number from 1 to 6. Then I'll roll the 3 dice. If none show the number you bet, you'll lose $1. If one shows the number you bet, you'll win $1. If two or three dice show the number you bet, you'll win $3 or $5, respectively."
Is it a fair game?
Hint: What will happen if there are 6 gamblers, each of whom bet on a different number?
It's a fair game. If there are 6 gamblers, each of whom bet on a different number, the dealer will neither win nor lose on each deal.
If he rolls 3 different numbers, e.g. 1, 2, 3, the three gamblers who bet 1, 2, 3 each wins $1 while the three gamblers who bet 4, 5, 6 each loses $1.
If two of the dice he rolls show the same number, e.g. 1, 1, 2, the gambler who bet 1 wins $3, the gambler who bet 2 wins $1, and the other 4 gamblers each loses $1.
If all 3 dice show the same number, e.g. 1, 1, 1, the gambler who bet 1 wins $5, and the other 5 gamblers each loses $1.
In each case, the dealer neither wins nor loses. Hence it's a fair game. Did you answer this riddle correctly?
YES NO
If he rolls 3 different numbers, e.g. 1, 2, 3, the three gamblers who bet 1, 2, 3 each wins $1 while the three gamblers who bet 4, 5, 6 each loses $1.
If two of the dice he rolls show the same number, e.g. 1, 1, 2, the gambler who bet 1 wins $3, the gambler who bet 2 wins $1, and the other 4 gamblers each loses $1.
If all 3 dice show the same number, e.g. 1, 1, 1, the gambler who bet 1 wins $5, and the other 5 gamblers each loses $1.
In each case, the dealer neither wins nor loses. Hence it's a fair game. Did you answer this riddle correctly?
YES NO
Four Balls In A Bowl
This is a famous paradox probability riddle which has caused a great deal of argument and disbelief from many who cannot accept the correct answer.
Four balls are placed in a bowl. One is Green, one is Black and the other two are Yellow. The bowl is shaken and someone draws two balls from the bowl. He looks at the two balls and announces that at least one of them is Yellow. What are the chances that the other ball he has drawn out is also Yellow?
Four balls are placed in a bowl. One is Green, one is Black and the other two are Yellow. The bowl is shaken and someone draws two balls from the bowl. He looks at the two balls and announces that at least one of them is Yellow. What are the chances that the other ball he has drawn out is also Yellow?
Hint:
1/5
There are six possible pairings of the two balls withdrawn,
Yellow+Yellow
Yellow+Green
Green+Yellow
Yellow+Black
Black+Yellow
Green+Black.
We know the Green + Black combination has not been drawn.
This leaves five possible combinations remaining. Therefore the chances tbowl the Yellow + Yellow pairing has been drawn are 1 in 5.
Many people cannot accept tbowl the solution is not 1 in 3, and of course it would be, if the balls had been drawn out separately and the color of the first ball announced as Yellow before the second had been drawn out. However, as both balls had been drawn together, and then the color of one of the balls announced, then the above solution, 1 in 5, must be the correct one. Did you answer this riddle correctly?
YES NO
There are six possible pairings of the two balls withdrawn,
Yellow+Yellow
Yellow+Green
Green+Yellow
Yellow+Black
Black+Yellow
Green+Black.
We know the Green + Black combination has not been drawn.
This leaves five possible combinations remaining. Therefore the chances tbowl the Yellow + Yellow pairing has been drawn are 1 in 5.
Many people cannot accept tbowl the solution is not 1 in 3, and of course it would be, if the balls had been drawn out separately and the color of the first ball announced as Yellow before the second had been drawn out. However, as both balls had been drawn together, and then the color of one of the balls announced, then the above solution, 1 in 5, must be the correct one. Did you answer this riddle correctly?
YES NO
100 Blank Cards Riddle
Someone offers you the following deal:
There is a deck of 100 initially blank cards. The dealer is allowed to write ANY positive integer, one per card, leaving none blank. You are then asked to turn over as many cards as you wish. If the last card you turn over is the highest in the deck, you win; otherwise, you lose.
Winning grants you $50, and losing costs you only the $10 you paid to play.
Would you accept this challenge?
There is a deck of 100 initially blank cards. The dealer is allowed to write ANY positive integer, one per card, leaving none blank. You are then asked to turn over as many cards as you wish. If the last card you turn over is the highest in the deck, you win; otherwise, you lose.
Winning grants you $50, and losing costs you only the $10 you paid to play.
Would you accept this challenge?
Hint: Perhaps thinking in terms of one deck is the wrong approach.
Yes!
A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."
Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).
This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.
Obviously, you have to have at least $40 to start in order to apply this strategy effectively. Did you answer this riddle correctly?
YES NO
A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."
Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).
This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.
Obviously, you have to have at least $40 to start in order to apply this strategy effectively. Did you answer this riddle correctly?
YES NO
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