Held Above Your Head
If it is raining outside
Youd use one of these I bet
As its held above your head
To keep you from getting wet
What are you using?
Youd use one of these I bet
As its held above your head
To keep you from getting wet
What are you using?
Hint:
Used In The Rain
I go up when Im used but Im not a balloon
I have a handle but Im not a car door
I get wet but Im not a washcloth
I go above your head but Im not mistletoe
Im used in the rain but Im not windshield wipers
What am I?
I have a handle but Im not a car door
I get wet but Im not a washcloth
I go above your head but Im not mistletoe
Im used in the rain but Im not windshield wipers
What am I?
Hint:
The 5,000 Dollar Bank Account
A guy has 5,000 in his bank on Monday.
On Tuesday, they guy had 4,000 dollars in his bank, but he didn't spend or take out any money.
By Sunday, his mortgage strangely went up and he had no money left in his bank. and he kept on getting his mortgage up every Sunday. On the Saturday before that Sunday, he threw out a working computer because he got a new one. The only way to make his mortgage go up and his money go down is through the computer. The guy goes to visit his friend every day and doesn't come home until 5:00. By the next week his mortgage went up higher. He was getting suspicious and narrowed down three victims.
The mailman
His arch enemy that killed his wife.
And his computer hacking friend that lived in another state.
What happened and how? Who did it?
On Tuesday, they guy had 4,000 dollars in his bank, but he didn't spend or take out any money.
By Sunday, his mortgage strangely went up and he had no money left in his bank. and he kept on getting his mortgage up every Sunday. On the Saturday before that Sunday, he threw out a working computer because he got a new one. The only way to make his mortgage go up and his money go down is through the computer. The guy goes to visit his friend every day and doesn't come home until 5:00. By the next week his mortgage went up higher. He was getting suspicious and narrowed down three victims.
The mailman
His arch enemy that killed his wife.
And his computer hacking friend that lived in another state.
What happened and how? Who did it?
Hint:
The mailman did it. There is no mail on Sunday and the mailman fruaded the guys info. every Sunday the mailman would come at 4:00 and mess with his money and mortgage. After plunging the computer into his truck and turning it on. Did you answer this riddle correctly?
YES NO
YES NO
99 Points Riddle
While out bowling with his friends, a man managed to throw eight strikes (all ten pins knocked down in a single throw) and not a single gutter ball during the entire game. To his amazement, his final score was only 99 points! Assuming there were no penalties or fouls, can you come up with a ten frame scorecard with eight strikes and a final score of only 99 points?
Hint: If you knock down a single pin, for example at the far left of the back row, then repeat the same identical shot on your second throw, you'll score 0 points for your second throw (because there's no pin there anymore), but it's not a gutter ball as the s
Just to reiterate the hint, if you knock down a single pin, for example at the far left of the back row, then repeat the same identical shot on your second throw, you'll score 0 points for your second throw (because there's no pin there anymore), but it's not a gutter ball as the shot did not enter the gutter. Did you answer this riddle correctly?
YES NO
YES NO
Going To Disneyland
Two blondes were going to Disneyland and came to a fork in the road. One way said highway 93 right and the other said Disneyland left.
Why did the blondes go home?
Why did the blondes go home?
Hint:
Three Hunters Riddle
Three hunters just finished hunting for the night and went down to a motel. They couldn't afford three separate rooms so they decided to get one room, and split the price. The room costed $30. (It was a run-down motel, but that's not the point.) So, they each paid their $10 and went to their room. The employee running the check-in/ check-out desk realized that she overcharged them, so she sent a bell-boy to return the extra cash. On the way the bell-boy wondered how to equally split the money... he wasnt the smart type so he just slid $2 into his pocket as a tip. That way the hunters would get $1 each. Well... they got their $1 each right? So in the end they all payed $9 each, which makes $27. Plus the $2 in the bell-boy's pocket makes $29...
What happened to the last dollar?
What happened to the last dollar?
Hint:
They didn't really pay $9 each, remember? The bell-boy was too lazy to add up the actual sum that they would pay. They reeeally payed about a $8.66 each. So $8.66 times the three of them equals about $25, plus the $5 in the bell-boys equals $30 Did you answer this riddle correctly?
YES NO
YES NO
Five Prom Couples Riddle
Five couples went to the prom as a group. The boys' names were Mark, Quintin, Jim, Bob, and James. The girls' names were Amanda, Betty, Susan, Jessica, and Jasmin. Each couple wore matching colors of either blue, yellow, red, green, or pink. Match the dates and the color they are wearing.
1) Two couples have the same first letter in their name. One of those letters is "B".
2) Susan wore red and Jessica wore blue.
3) Susan has more letters in her name than her date does.
4) Neither Mark nor Quintin went with Jasmin, who was wearing yellow.
5) Amanda went with Jim and they did not wear green.
1) Two couples have the same first letter in their name. One of those letters is "B".
2) Susan wore red and Jessica wore blue.
3) Susan has more letters in her name than her date does.
4) Neither Mark nor Quintin went with Jasmin, who was wearing yellow.
5) Amanda went with Jim and they did not wear green.
Hint:
Mark and Susan wore red.
Quintin and Jessica wore blue.
Jim and Amanda wore pink.
Bob and Betty wore green.
James and Jasmin wore yellow. Did you answer this riddle correctly?
YES NO
Quintin and Jessica wore blue.
Jim and Amanda wore pink.
Bob and Betty wore green.
James and Jasmin wore yellow. Did you answer this riddle correctly?
YES NO
Throwing A Basketball Riddle
A man takes a basketball and throws it as hard as he can. There is nothing in front, behind, or on either side of him, and yet, the ball comes back and hits him square in the face. How can this be?
Hint:
2000 Degrees Celsius
Hint:
The Blind Mammals Riddle
The fact this mammal has webbed wings
Makes it a one of a kind
And contrary to the saying
None of these creatures are blind
What are these mammals?
Makes it a one of a kind
And contrary to the saying
None of these creatures are blind
What are these mammals?
Hint:
Roll The Dice
A gambler goes to bet. The dealer has 3 dice, which are fair, meaning that the chance that each face shows up is exactly 1/6.
The dealer says: "You can choose your bet on a number, any number from 1 to 6. Then I'll roll the 3 dice. If none show the number you bet, you'll lose $1. If one shows the number you bet, you'll win $1. If two or three dice show the number you bet, you'll win $3 or $5, respectively."
Is it a fair game?
The dealer says: "You can choose your bet on a number, any number from 1 to 6. Then I'll roll the 3 dice. If none show the number you bet, you'll lose $1. If one shows the number you bet, you'll win $1. If two or three dice show the number you bet, you'll win $3 or $5, respectively."
Is it a fair game?
Hint: What will happen if there are 6 gamblers, each of whom bet on a different number?
It's a fair game. If there are 6 gamblers, each of whom bet on a different number, the dealer will neither win nor lose on each deal.
If he rolls 3 different numbers, e.g. 1, 2, 3, the three gamblers who bet 1, 2, 3 each wins $1 while the three gamblers who bet 4, 5, 6 each loses $1.
If two of the dice he rolls show the same number, e.g. 1, 1, 2, the gambler who bet 1 wins $3, the gambler who bet 2 wins $1, and the other 4 gamblers each loses $1.
If all 3 dice show the same number, e.g. 1, 1, 1, the gambler who bet 1 wins $5, and the other 5 gamblers each loses $1.
In each case, the dealer neither wins nor loses. Hence it's a fair game. Did you answer this riddle correctly?
YES NO
If he rolls 3 different numbers, e.g. 1, 2, 3, the three gamblers who bet 1, 2, 3 each wins $1 while the three gamblers who bet 4, 5, 6 each loses $1.
If two of the dice he rolls show the same number, e.g. 1, 1, 2, the gambler who bet 1 wins $3, the gambler who bet 2 wins $1, and the other 4 gamblers each loses $1.
If all 3 dice show the same number, e.g. 1, 1, 1, the gambler who bet 1 wins $5, and the other 5 gamblers each loses $1.
In each case, the dealer neither wins nor loses. Hence it's a fair game. Did you answer this riddle correctly?
YES NO
Fighting In A Truel
Mr. Black, Mr. Gray, and Mr. White are fighting in a truel. They each get a gun and take turns shooting at each other until only one person is left. Mr. Black, who hits his shot 1/3 of the time, gets to shoot first. Mr. Gray, who hits his shot 2/3 of the time, gets to shoot next, assuming he is still alive. Mr. White, who hits his shot all the time, shoots next, assuming he is also alive. The cycle repeats. All three competitors know one another's shooting odds. If you are Mr. Black, where should you shoot first for the highest chance of survival?
Hint: Think from the points of view of Mr. Gray and Mr. White, not just Mr. Black.
He should shoot at the ground.
If Mr. Black shoots the ground, it is Mr. Gray's turn. Mr. Gray would rather shoot at Mr. White than Mr. Black, because he is better. If Mr. Gray kills Mr. White, it is just Mr. Black and Mr. Gray left, giving Mr. Black a fair chance of winning. If Mr. Gray does not kill Mr. White, it is Mr. White's turn. He would rather shoot at Mr. Gray and will definitely kill him. Even though it is now Mr. Black against Mr. White, Mr. Black has a better chance of winning than before. Did you answer this riddle correctly?
YES NO
If Mr. Black shoots the ground, it is Mr. Gray's turn. Mr. Gray would rather shoot at Mr. White than Mr. Black, because he is better. If Mr. Gray kills Mr. White, it is just Mr. Black and Mr. Gray left, giving Mr. Black a fair chance of winning. If Mr. Gray does not kill Mr. White, it is Mr. White's turn. He would rather shoot at Mr. Gray and will definitely kill him. Even though it is now Mr. Black against Mr. White, Mr. Black has a better chance of winning than before. Did you answer this riddle correctly?
YES NO
Gun Fighting Riddle
Kangwa, Rafael and Ferdinand plans for gun fighting.
They each get a gun and take turns shooting at each other until only one person is left.
History suggests:
Kangwa hits his shot 1/3 of the time, gets to shoot first.
Rafael, hits his shot 2/3 of the time, gets to shoot next if still living.
Ferdinand having perfect record at shooting(100% accuracy) shoots last , if alive.
The cycle repeats. If you are Kangwa, where should you shoot first for the highest chance of survival?
They each get a gun and take turns shooting at each other until only one person is left.
History suggests:
Kangwa hits his shot 1/3 of the time, gets to shoot first.
Rafael, hits his shot 2/3 of the time, gets to shoot next if still living.
Ferdinand having perfect record at shooting(100% accuracy) shoots last , if alive.
The cycle repeats. If you are Kangwa, where should you shoot first for the highest chance of survival?
Hint:
He should shoot at the ground.
If Kangwa shoots the ground, it is Rafael's turn. Rafael would rather shoot at Ferdinand than Kangwa, because he is better.
If Rafael kills Ferdinand, it is just Kangwa and Rafael left, giving Kangwa a fair chance of winning.
If Rafael does not kill Ferdinand, it is Ferdinand's turn. He would rather shoot at Rafael and will definitely kill him. Even though it is now Kangwa against Ferdinand, Kangwa has a better chance of winning than before. Did you answer this riddle correctly?
YES NO
If Kangwa shoots the ground, it is Rafael's turn. Rafael would rather shoot at Ferdinand than Kangwa, because he is better.
If Rafael kills Ferdinand, it is just Kangwa and Rafael left, giving Kangwa a fair chance of winning.
If Rafael does not kill Ferdinand, it is Ferdinand's turn. He would rather shoot at Rafael and will definitely kill him. Even though it is now Kangwa against Ferdinand, Kangwa has a better chance of winning than before. Did you answer this riddle correctly?
YES NO
100 Blank Cards Riddle
Someone offers you the following deal:
There is a deck of 100 initially blank cards. The dealer is allowed to write ANY positive integer, one per card, leaving none blank. You are then asked to turn over as many cards as you wish. If the last card you turn over is the highest in the deck, you win; otherwise, you lose.
Winning grants you $50, and losing costs you only the $10 you paid to play.
Would you accept this challenge?
There is a deck of 100 initially blank cards. The dealer is allowed to write ANY positive integer, one per card, leaving none blank. You are then asked to turn over as many cards as you wish. If the last card you turn over is the highest in the deck, you win; otherwise, you lose.
Winning grants you $50, and losing costs you only the $10 you paid to play.
Would you accept this challenge?
Hint: Perhaps thinking in terms of one deck is the wrong approach.
Yes!
A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."
Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).
This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.
Obviously, you have to have at least $40 to start in order to apply this strategy effectively. Did you answer this riddle correctly?
YES NO
A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."
Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).
This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.
Obviously, you have to have at least $40 to start in order to apply this strategy effectively. Did you answer this riddle correctly?
YES NO
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
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