12 Numbers Riddle
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Two Trees Riddle
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The Arrested Belt Riddle
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Catching A Fish Riddle
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Shocked Into Silence Riddle
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Carrying Children Riddle
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Sitting On Me Riddle
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Playing With String Riddle
I can be many different colors. I live in your home. I like to play with string. I have four legs and say miaow I know! What could I be?
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Work And Games Riddle
I am in the school or home. I have a mouse. You can use me for work or games. You can use me for email I know! What am I?
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A Small Shop Riddle
I am all over Hong Kong. I am a small shop. My name is two numbers. I sell snacks and newspapers. Where could this place be?
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A Bird That Can't Fly
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Talking Tornadoes Riddle
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The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
Participating In A Race
Hint: It's not first place.
If you answer that you are first, then you are absolutely wrong! If you overtake the second person and you take his place, you are second! Did you answer this riddle correctly?
YES NO
YES NO
2 Fathers And 2 Sons Riddle
Hint:
One of the 'fathers' is also a grandfather. Therefore the other father is both a son and a father to the grandson.
In other words, the one father is both a son and a father. Did you answer this riddle correctly?
YES NO
In other words, the one father is both a son and a father. Did you answer this riddle correctly?
YES NO
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