### Fun Facts (Hints)

Hard riddles are universal, and continue to leave a lasting impression on many different cultures across the globe. Here are some interesting facts:
The mere definition of what a riddle is, is something that has drawn a large amount of debate between scholars for centuries.
Complex riddles have been used since ancient times, and extensively in ancient/medieval literature.
There is only one riddle in the Bible appearing in the book of Judges. It is known as "Samson's riddle."
Charades is a popular contemporary game created with the use of riddle.
In author J. R. R. Tolkien's 'The Hobbit' Bilbo Baggins is given a challenging riddle by Gollum, and his life was dependent upon getting the correct answer.

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## Really Hard & Short Complex Riddles To Challenge You

While some hard riddles are meant for mastering instantly, these are the best of the best and more than likely will not be able to be answered promptly.

Whether you are an exceptional thinker who is ready to take on one of the greatest advanced riddles collections known to man or whether you're a teacher that is just looking for some really hard riddles with answers to give out to students, at Riddles and Answers we find the most complex riddles known to man, daily.

Remember before starting that these brain teasers are very

**tough riddles**with answers readily available. If you find yourself stuck on one problem for too long, it's ok to move on to the next one. Just be sure to attempt these challenging riddles every day to help keep your brain functioning at a high level.

## A Boy Was 15 In 1990 Riddle

Hint:

The boy lived before Christ. Therefore, in 1995 B.C. he was 10 years old, and in 1990 he turned 15.

YES NO

*Did you answer this riddle correctly?*YES NO

## Clock Calculator Bulb Riddle

Hint:

Find the value of one clock using the first equation. According to first equation, 9’o clock + 9’o clock + 3'o clock = 9 + 9 + 3 = 21.

Therefore; 1 Clock = 1

Using equation two, three calculators are equal to 30. Therefore, one calculator is equal to 10.

Also, the sum of numbers inside the calculator is 1 + 2 + 3 + 4 = 10.

Therefore, the value of the calculator depends on the sum of the numbers inside it.

According to equation three, 1 Bulb + 1 Bulb - 1 Bulb = 15.

Cancelling out the + and -; we get 1 Bulb with five lights = 15

.

Therefore, one bulb with one light = 3.

Bulb with four lights = 4 x 3 = 12.

The final equation is - 9’o clock + Calculator (1+2+2+4) x 3 bulbs (with four light rays each)

Translating the final equation into numbers - 9 + (1+2+2+4) x 3(12)

9 + 9 x 36 = 9 + 324 = 333.

Answer to 'Watch Calculator bulb' puzzle is 333.

YES NO

Therefore; 1 Clock = 1

Using equation two, three calculators are equal to 30. Therefore, one calculator is equal to 10.

Also, the sum of numbers inside the calculator is 1 + 2 + 3 + 4 = 10.

Therefore, the value of the calculator depends on the sum of the numbers inside it.

According to equation three, 1 Bulb + 1 Bulb - 1 Bulb = 15.

Cancelling out the + and -; we get 1 Bulb with five lights = 15

.

Therefore, one bulb with one light = 3.

Bulb with four lights = 4 x 3 = 12.

The final equation is - 9’o clock + Calculator (1+2+2+4) x 3 bulbs (with four light rays each)

Translating the final equation into numbers - 9 + (1+2+2+4) x 3(12)

9 + 9 x 36 = 9 + 324 = 333.

Answer to 'Watch Calculator bulb' puzzle is 333.

*Did you answer this riddle correctly?*YES NO

## I May Be Simple I May Be Complex Riddle

I may be simple, I may be complex; I may have a name, but no gender or sex; I am often a question, or statements as a setup; I tend to have an answer, 'til you find it I won't let up. What am I?

Hint:

## 12 Pills Riddle

You have 12 pills and they all got the same weight, except for one, which hasn't got the same weight. You don't know if it is heavier or easier. You have one scale to weight the pills. You now have to find out, which pill is the right one (the one with a different weight), but you can use the scale only three times. How do you know, which one is the right one?You have 12 pills and they all got the same weight, except for one, which hasn't got the same weight. You don't know if it is heavier or easier. You have one scale to weight the pills. You now have to find out, which pill is the right one (the one with a different weight), but you can use the scale only three times. How do you know, which one is the right one?

Hint:

E = easier in "1", H = heavier in "1". 1: Weight 4:4. If they balance go to "2", if they don't balance, go to "3". 2: Balance 1:1 of the pills you didn't weight yet. Then weight one you didn't weight and one you did weight. If they balanced in the first weighing, and balanced in the second weighing, the last pill is the right one. If they balanced in the first weighing and didn't balance in the second, the one you didn't use before is the right pill. If they didn't balance at all, it's the pill you weighed twice. If they didn't balance in the first weighing, but balanced in the second, it is the first pill. 3: Weight EHH : EHH. If they balance, weight one you already weighed, with an unweighed and go to "4". If they don't balance go to "5". 4: If they balance, the one you didn't weight at all is the right pill. If they don't balance, the one you only weighed once is the right one. 5: Give away every pill that was once easier AND once heavier. You should only have EHH left. Weight H:H. If they balance, E is the right one. If the don't balance, the one which was only heavier the whole time, is the right pill.

YES NO

*Did you answer this riddle correctly?*YES NO

## I Am A 8 Letter Word Riddle

I am a 8 Letter Word.

I am kept Secret from Everyone.

My 2nd, 3rd, 4th Letter Spell an Animal.

My 4th, 5th, 6th, 7th, 8th Letter is a Weapon.

My 1st, 2nd, 8th Letter is used for Writing an Exam.

My 3rd, 4th Letters are the Same.

Who am I?

I am kept Secret from Everyone.

My 2nd, 3rd, 4th Letter Spell an Animal.

My 4th, 5th, 6th, 7th, 8th Letter is a Weapon.

My 1st, 2nd, 8th Letter is used for Writing an Exam.

My 3rd, 4th Letters are the Same.

Who am I?

Hint:

## A Woman Was In Court For Killing Her Husband Riddle

A woman was in court for killing her husband. She said she wasn't guilty and that she dearly missed him. In the closing statement, the woman's lawyer stands up and says, "Her husband was just missing. Everyone look at the doors. He's going to walk through them in about 30 seconds."

The entire jury stares at the doors waiting for waiting for this woman's husband to walk through the doors. The lawyer and the woman stare at the jury.

The lawyer concludes by saying, "See! If you were so sure she killed her husband, you wouldn't be watching that door!"

The jury immediately gave a guilty verdict. Why?

The entire jury stares at the doors waiting for waiting for this woman's husband to walk through the doors. The lawyer and the woman stare at the jury.

The lawyer concludes by saying, "See! If you were so sure she killed her husband, you wouldn't be watching that door!"

The jury immediately gave a guilty verdict. Why?

Hint:

The woman was watching the jury and not the doors because she knew that her husband wouldn't walk through them because she had killed him. If she has really missed him like she said, she would have been watching the doors.

YES NO

*Did you answer this riddle correctly?*YES NO

## 12 Islanders Teeter Totter Riddle

There is an island with 12 islanders. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11.

You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.

How can you find out which islander is the one that has a different weight?

You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.

How can you find out which islander is the one that has a different weight?

Hint:

Six on one side - six on the other = one side is heavier.

Take the heavier six men, divide them into three and three (random).

Three on one side - three on the other = one side will one heavier.

Divide that three men from the heavier side side, have one on one side - one on the other.

Two results can determine which of the last three men weight is a different weight than each other.

With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.

Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.

You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."

Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less.

YES NO

Take the heavier six men, divide them into three and three (random).

Three on one side - three on the other = one side will one heavier.

Divide that three men from the heavier side side, have one on one side - one on the other.

Two results can determine which of the last three men weight is a different weight than each other.

With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.

Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.

You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."

Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less.

*Did you answer this riddle correctly?*YES NO

## I Can Be The Sun Sand And A Bird Riddle

Hint:

## Pierce Ones Ears Riddle

Hint:

## Shoe Man Whistle

Hint:

The third equation has a term with a pair of whistles. The last line involves a single whistle.

Furthermore, the man in the second and third lines are wearing a whistle, but the man in the last line is not wearing a whistle. Presumably the value of the whistle should be accounted for to get the correct answer.

The pictures can be translated into the following equations:

shoes + shoes + shoes = 30

shoes + (man + whistle) + (man + whistle) = 20

(man + whistle) + 2(whistles) + 2(whistles) = 13

shoes + (man) x (whistle) = ?

From the first equation we can solve for the shoes value:

shoes + shoes + shoes = 30

3(shoes) = 30

shoes = 10

We can then solve the second equation for the (man + whistle) value:

shoes + (man + whistle) + (man + whistle) = 20

10 + 2(man + whistle) = 20

2(man + whistle) = 10

man + whistle = 5

Then we solve the third equation for the whistle:

(man + whistle) + 2(whistles) + 2(whistles) = 13

5 + 4(whistles) = 13

4(whistles) = 8

whistle = 2

We also need to solve for the value of the man:

man + whistle = 5

man + 2 = 5

man = 3

Now we can evaluate the final expression, remembering the order of operations that multiplication should be evaluated before addition:

shoes + (man) x (whistle) = ?

10 + 3 x 2

= 10 + 3 x 2

= 10 + 6

= 16

YES NO

Furthermore, the man in the second and third lines are wearing a whistle, but the man in the last line is not wearing a whistle. Presumably the value of the whistle should be accounted for to get the correct answer.

The pictures can be translated into the following equations:

shoes + shoes + shoes = 30

shoes + (man + whistle) + (man + whistle) = 20

(man + whistle) + 2(whistles) + 2(whistles) = 13

shoes + (man) x (whistle) = ?

From the first equation we can solve for the shoes value:

shoes + shoes + shoes = 30

3(shoes) = 30

shoes = 10

We can then solve the second equation for the (man + whistle) value:

shoes + (man + whistle) + (man + whistle) = 20

10 + 2(man + whistle) = 20

2(man + whistle) = 10

man + whistle = 5

Then we solve the third equation for the whistle:

(man + whistle) + 2(whistles) + 2(whistles) = 13

5 + 4(whistles) = 13

4(whistles) = 8

whistle = 2

We also need to solve for the value of the man:

man + whistle = 5

man + 2 = 5

man = 3

Now we can evaluate the final expression, remembering the order of operations that multiplication should be evaluated before addition:

shoes + (man) x (whistle) = ?

10 + 3 x 2

= 10 + 3 x 2

= 10 + 6

= 16

*Did you answer this riddle correctly?*YES NO

## A Single Candle On A Cake

Im a single candle on a cake

A solar trip without a break

Cheer me out and hear me ringing

52 days and a new beginning

What am I?

A solar trip without a break

Cheer me out and hear me ringing

52 days and a new beginning

What am I?

Hint:

1 of your 7 year cycles! You go through 7 cycles every year. The first cycle starts on your birthday, and each of the 7 cycles lasts 52 days. (7x52=364).

You only have to find your personal cycle numbers once, because it's always the same, year after year.

YES NO

You only have to find your personal cycle numbers once, because it's always the same, year after year.

*Did you answer this riddle correctly?*YES NO

## $100 Bill Grocery Store Thief

A guy walks into a store and steals a $100 bill from the register without the owners knowledge.

He then buys $70 worth of goods using the $100 bill and the owner gives $30 in change.

How much money did the owner lose?

$30, $70, $100, $130, $170, or $200?

He then buys $70 worth of goods using the $100 bill and the owner gives $30 in change.

How much money did the owner lose?

$30, $70, $100, $130, $170, or $200?

Hint:

The best answer from the choices is the owner lost $100. The $100 bill that was stolen was then given back to the owner. What the owner loses is the $70 worth of goods and the $30 in change, which makes for a total of $70 + $30 = $100. The owner has lost $100.

Technically, the owner lost $30 plus the value, V, of the $70 of goods. Since stores typically sell goods at a markup, the value may be less than $70. But in the case of a loss leader, the owner may have lost more than $70.

YES NO

Technically, the owner lost $30 plus the value, V, of the $70 of goods. Since stores typically sell goods at a markup, the value may be less than $70. But in the case of a loss leader, the owner may have lost more than $70.

*Did you answer this riddle correctly?*YES NO

## Five Rows Of Four Christmas Trees Riddle

"I planted five rows of four Christmas trees each." The man boasted to his boss. The boss looked at him and said, are you saying you planted 20 Christmas trees in one day? No, the man said, I only planted 10 trees. How did he do it?

Hint:

Just imagine a 5 pointed star, and then plant one tree at each point, and one tree where the sides intersect.

There are actually several distinct solutions. All of them can be constructed as follows:

Draw a nice long straight line.

Draw a second straight line that intersects the first.

Draw three more straight lines making sure each line intersects all the lines youve already drawn and avoiding any of the previous points of intersection. That is, no three lines should intersect at the same point.

With the first four lines, theres only one topologically distinct configuration, but by varying the position of the fifth line, several different distinct configurations can be created.

YES NO

There are actually several distinct solutions. All of them can be constructed as follows:

Draw a nice long straight line.

Draw a second straight line that intersects the first.

Draw three more straight lines making sure each line intersects all the lines youve already drawn and avoiding any of the previous points of intersection. That is, no three lines should intersect at the same point.

With the first four lines, theres only one topologically distinct configuration, but by varying the position of the fifth line, several different distinct configurations can be created.

*Did you answer this riddle correctly?*YES NO

## A Train Leaves From Halifax Riddle

A train leaves from Halifax, Nova Scotia heading towards Vancouver, British Columbia at 120 km/h. Three hours later, a train leaves Vancouver heading towards Halifax at 180 km/h. Assume theres exactly 6000 kilometers between Vancouver and Halifax. When they meet, which train is closer to Halifax?

Hint:

Both trains would be at the same spot when they meet therefore they are both equally close to Halifax.

YES NO

*Did you answer this riddle correctly?*YES NO

## An Island That Has 3 Gods

There is an Island that has 3 gods. One god always tells a lie, and the other always tells the truth. The third god has a random behavior. To top it off, these three gods, being jerks, answer in their own languages such that you are unable to tell which word, between "ja" or "da", means "no" or "yes". You have 3 questions to work out the True god, the false god, and the Random god.

Hint:

Question 1: (To any of the three gods) If I were to ask you "Is that the random god," would your answer be "ja?" (This questions, no matter the answer, will enable you to tell which god is not random i.e. the god who is either False or True)

Question 2: (To either the True or False god) If I asked you "are you false," would your answer be "ja?"

Question 3: (To the same god you asked the second question) If I asked you "whether the first god I spoke to is random," would your answer be "ja?"

YES NO

Question 2: (To either the True or False god) If I asked you "are you false," would your answer be "ja?"

Question 3: (To the same god you asked the second question) If I asked you "whether the first god I spoke to is random," would your answer be "ja?"

*Did you answer this riddle correctly?*YES NO

## Post Your Hard Riddles Below

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