The Tale Of Rumpelstiltskin
I'm in many types of jewelry
Like the chain of a necklace
In the tale of Rumpelstiltskin
He could spin straw into this?
Like the chain of a necklace
In the tale of Rumpelstiltskin
He could spin straw into this?
Hint:
Known To Cause A Rush
I'm sometimes found in a pot but I'm not stew
I can be a bar but Im not soap
I've been known to cause a rush but Im not a Black Friday sale
Im a type of metal but Im not tin
I can be a medal but Im not silver
I am?
I can be a bar but Im not soap
I've been known to cause a rush but Im not a Black Friday sale
Im a type of metal but Im not tin
I can be a medal but Im not silver
I am?
Hint:
From Planet To Planet To Planet Riddle
Hint:
Age Of Three Daughters Riddles
I was visiting a friend one evening and remembered that he had three daughters. I asked him how old they were. The product of their ages is 72, he answered. Quizzically, I asked, Is there anything else you can tell me? Yes, he replied, the sum of their ages is equal to the number of my house. I stepped outside to see what the house number was. Upon returning inside, I said to my host, Im sorry, but I still cant figure out their ages. He responded apologetically, Im sorry, I forgot to mention that my oldest daughter likes strawberry shortcake. With this information, I was able to determine all three of their ages. How old is each daughter?
Hint:
3, 3, and 8. The only groups of 3 factors of 72 to have non-unique sums are 2 6 6 and 3 3 8 (with a sum of 14). The rest have unique sums:
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
Strive With Wind And Wave Riddle
Off I must strive with wind and wave, battle them both
when under the sea.
I feel out the bottom, a foreign land. In lying still, I am
Strong in the strife;
If I fail in that, they are stronger than I, and
Wrenching me loose, soon put me to rout.
They wish to capture what I must keep. I can master
Them both if my grip holds out,
If the rocks bring succor and lend support, strength
In the struggle. Ask my name
when under the sea.
I feel out the bottom, a foreign land. In lying still, I am
Strong in the strife;
If I fail in that, they are stronger than I, and
Wrenching me loose, soon put me to rout.
They wish to capture what I must keep. I can master
Them both if my grip holds out,
If the rocks bring succor and lend support, strength
In the struggle. Ask my name
Hint:
Starbucks Baby Riddle
Hint:
Two Flies Are On The Porch
Hint:
A Cat Had Three Kittens
Hint: Consider the punctuation.
Three Gods Riddle
Three gods A, B, and C are called, in no particular order, True, False, and Random. True always speaks truly, False always speaks falsely, but whether Random speaks truly or falsely is a completely random matter. Your task is to determine the identities of A, B, and C by asking three yes-no questions; each question must be put to exactly one god. The gods understand English, but will answer all questions in their own language, in which the words for yes and no are da and ja, in some order. You do not know which word means which.
What three questions can you ask?
What three questions can you ask?
Hint:
A possible solution is:
Q1: Ask god B, "If I asked you 'Is A Random?', would you say ja?". If B answers ja, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is indeed Random. Either way, C is not Random. If B answers da, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is not Random. Either way, you know the identity of a god who is not Random.
Q2: Go to the god who was identified as not being Random by the previous question (either A or C), and ask him: "If I asked you 'Are you False?', would you say ja?". Since he is not Random, an answer of da indicates that he is True and an answer of ja indicates that he is False.
Q3: Ask the same god the question: "If I asked you 'Is B Random?', would you say ja?". If the answer is ja, B is Random; if the answer is da, the god you have not yet spoken to is Random. The remaining god can be identified by elimination. Did you answer this riddle correctly?
YES NO
Q1: Ask god B, "If I asked you 'Is A Random?', would you say ja?". If B answers ja, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is indeed Random. Either way, C is not Random. If B answers da, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is not Random. Either way, you know the identity of a god who is not Random.
Q2: Go to the god who was identified as not being Random by the previous question (either A or C), and ask him: "If I asked you 'Are you False?', would you say ja?". Since he is not Random, an answer of da indicates that he is True and an answer of ja indicates that he is False.
Q3: Ask the same god the question: "If I asked you 'Is B Random?', would you say ja?". If the answer is ja, B is Random; if the answer is da, the god you have not yet spoken to is Random. The remaining god can be identified by elimination. Did you answer this riddle correctly?
YES NO
Share The Same Name Riddle
We share the same name,
but mean two different things
one goes up and down
and the other spins
while one can make you sick
the other you cannot touch
you have heard of me before
whether you know it or not
you know our name
just give it a thought
One is a messenger
the other is not
One gives you a reading
The other helps the Oracle
What are we?
but mean two different things
one goes up and down
and the other spins
while one can make you sick
the other you cannot touch
you have heard of me before
whether you know it or not
you know our name
just give it a thought
One is a messenger
the other is not
One gives you a reading
The other helps the Oracle
What are we?
Hint:
Mercury (Messenger is Hermes, or in Latin it is Mercury) Did you answer this riddle correctly?
YES NO
YES NO
7B91011 Riddle
Ray Whitcombe was found dead in his office at his desk. The police have narrowed the suspects down to three people:
Mrs. Barbara Whitcombe, Ray's wife
Mr. Jason McCubbins, Ray's business partner
Mr. Harold Nichols, Ray's best friend
All three visited Mr. Whitcombe the day of his murder, but all three provided the police with stories of explanation as to the reason for their visit.
Police found Mr. Whitcombe with his wrist watch still on his right arm, a torn up picture of his wife laying on the floor beside the trash can, and an ink pen in his right hand. On the desk, the police found a name plate, a telephone that was off the hook, and a personal calendar turned to the July 5th page with 7B91011 written on it. After examining this evidence, the police knew their suspect.
Who was it?
Mrs. Barbara Whitcombe, Ray's wife
Mr. Jason McCubbins, Ray's business partner
Mr. Harold Nichols, Ray's best friend
All three visited Mr. Whitcombe the day of his murder, but all three provided the police with stories of explanation as to the reason for their visit.
Police found Mr. Whitcombe with his wrist watch still on his right arm, a torn up picture of his wife laying on the floor beside the trash can, and an ink pen in his right hand. On the desk, the police found a name plate, a telephone that was off the hook, and a personal calendar turned to the July 5th page with 7B91011 written on it. After examining this evidence, the police knew their suspect.
Who was it?
Hint:
Jason McCubbins, Ray's business partner.
The calendar was the clue to solving this murder. The police realized that since Mr. Whitcombe was wearing his watch on his right arm, he must have been left-handed. Realizing that the number on the calendar was written in a hurry and with his opposite hand, police matched the written number with the months of the year. So the B was an 8, thereby giving us 7-8-9-10-11: July, August, September, October, November. Use the first letter of each month and it spells J-A-S-O-N. Did you answer this riddle correctly?
YES NO
The calendar was the clue to solving this murder. The police realized that since Mr. Whitcombe was wearing his watch on his right arm, he must have been left-handed. Realizing that the number on the calendar was written in a hurry and with his opposite hand, police matched the written number with the months of the year. So the B was an 8, thereby giving us 7-8-9-10-11: July, August, September, October, November. Use the first letter of each month and it spells J-A-S-O-N. Did you answer this riddle correctly?
YES NO
Vegetable Necklace
Hint:
What's White, Gooey And Sticky
Hint:
Toothpaste. Dental hygiene is so important. You sick freak. Did you answer this riddle correctly?
YES NO
YES NO
Three Kittens Riddle
Hint: Consider the punctuation.
What Has Cities Forests And Water
Hint:
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