I HAVE A LARGE MONEY BOX 48 CENTEMETERS SQUARE AND 42 CENTEMETERS TALL ROUGHLY HOW M RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Riddles and Answers © 2024

Made But Unwanted Riddle

Hint:
Fake/ counterfeit money
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Bigger Than A Match Box Riddle

Hint:
A coffin
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Making Dirty Money

Hint:
Racket
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Sailing The Seas For Money

Hint:
A pirate
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Monkey Cake Riddle

Hint:
Pound Cake
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Where Do Frogs Keep Their Money

Hint:
In a River Bank
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Matthew Has 20 Dollars Riddle

Hint:
A red bull
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What Makes Up A Square With Edges Like A Knife Riddle

Hint: Just remember, always look on the bright side of life.
A stamp.
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Borrow $50 From Mom And $50 From Dad Riddle

Hint:
Total Money taken = $100($50+$50)

Now,

Bag's Price = $ 97

Remaining Amount = $100 - $97

= $ 3

Returned = $ 1 + $ 1

=$2

In pocket = $1

Total money owed = $100- ( Returned amount)

= $98( Bag's amount and reserved amount)

So, it was a calculation mistake.
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A Man Gave One Son 10 Cents Riddle

Hint:
1:45. The man gave away a total of 25 cents. He divided it between two people. Therefore, he gave a quarter to two.
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A Man Buys A Goat For $60 Riddle

Hint:
He made $20. $10 the first time, $70 - $60 = $10, and $10 the second time, $90 - $80 = $10, for a total of $20.
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A Man Steals 1000 From A Shop Riddle

Hint:
We can easily solve this mathematical problem by using the following mathematical process.

Initial loss amount = Rs. 1000

Now, we have to calculate the recovered amount,

As the man spends Rs. 700 in the shop, the shop owner will surely provide the man goods/services of Rs. 700. So, nothing will be recovered in this case.

Now, the man gave Rs. 1000 against the goods/services of Rs. 700 and got Rs. 300 change, so there will be no recovering of money for the shopkeeper.

Final loss = Initial loss - Recovered amount = 1000-0 = Rs. 1000
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Four Jolly Men Riddle

Hint:
Four men in a dance band
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Three Mountain Climbers

Hint:
They found a cabin of an airplane that had crashed there with 3 bodies in it.
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10 Boxes Riddle

Hint:
Let us simplify boxes by naming them from 1 to 10.
Now the trick here is to pick different number of balls from different boxes. So to simplify things, we will pick balls corresponding to box number.

Thus, pick 1 ball from Box 1, 2 balls from box 2, 3 balls from box 3 and so on. You will have 55 balls altogether. Now, put them all in the balance.

If all balls were weighing accurate 10 grams, the total weight of the 55 balls would have been 550 grams. But one of the box must have had the defective balls.

Suppose if the defective balls were in box number 2, then the total weight will be 2 grams less than 550. If the defective balls were in box 8, the total weight will be less than 8 grams from 550. In this way, you will be able to identify which box has the defective balls.
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