IF I HAD 5 APPLES IN ONE HAND AND 6 APPLES IN THE OTHER WHAT WOULD I RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Meeting In The Office

Hint:
A clock
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Used In The Rain

Hint:
An umbrella
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Chess Cowboy Riddle

Hint:
He didn't want to lose his horse.
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Play Me With A Ball

Hint:
Basketball
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Found In A Kitchen Riddle

Hint:
I am a knife
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Miss Millie's Parrot

Hint:
The parrot was DEAF.
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Made Of Metal Riddle

Hint:
Bells
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Coming Down The Chimney

Hint:
The fireplace
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The 1000km Layer

Hint:
The Exosphere
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Adams Rib Riddle

Hint:
Eve
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Pearl Problems Riddle

Hint: If you took out 2 pearls, you would have about a 50% chance of getting 2 gold bars. However, you can take even more pearls and still retain the 50% chance.
Take out 5000 pearls. If the remaining pearl is white, then you've won 5000 gold bars!
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The Secret Santa Exchange

Hint: It's not as difficult as it seems. It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10

For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is

(n-1)! / n!

Since n! = (n-1)! * n (for n > 1), this can be rewritten as

(n-1)! / (n*(n-1)!)

Factoring out the (n-1)! from the numerator and denominator leaves

1/n

as the probability.
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Prints In The Sand

Hint:
A foot
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I Come As A Pair

Hint:
I am feet!
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The Quietest Whimper

Hint:
An actor
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