IM ALWAYS 1 TO 6 IM ALWAYS 15 TO 20 IM ALWAYS 5 BUT IM NEVER 21 UNLESS IM FLYING RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Eye Test How Many 3s Riddle

Hint:
The answers for 'eye test how many 3s' puzzle ranges from 15 to 21. At first glance, most people only notice 15 threes in the image. First, you might notice that there are two threes on the number pad, as the number eight has also been replaced by a three. Then there are eight threes in the phone number. Many also notice that the battery charge is at 33% and the time is 3:33 PM.

However, if one looks closer at the name underneath the phone number, they will find three more 3s. This gives a total of 18 3s in the image. But there is one more hidden three that even observant people fail to notice. Underneath the number four on the keypad, the letter 'I' has been replaced with three as well. So, the total number of 3s in the image is 19.

However, depending on your interpretation of the puzzle, the number of 3s can also rise to 21. At the top left of the image, the bar signal and wifi signal also have three bars. Some people also consider the two signals to be a part of the riddle and raise the number of 3s to 21. So, the correct answer can be 19 or 21, depending on your interpretation of the question.
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How Many Ducks Do You See Riddle

Hint:
There are a total of 16 ducks in the picture. In the first row, there are 5 ducks in total. Speaking about the second row, it has 6 ducks in total. The last row has 5 ducks in total. If you see carefully there are some small ducks in the picture. It might be difficult to notice them at first glance. At first glance, you might notice around 10 ducks but there are more ducks hidden in the picture. There is also an image that will give you a clear idea of where are the hidden ducks.
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I Can Be Short And Sometimes Hot Riddle

Hint:
A temper
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Go To Where You Find News Of June Riddle

Hint:
The answer is Bird.
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Why Did The Woman Kill Her Sister Riddle

Hint:
The answer to the riddle is the woman killed her because she was hoping to see this man at her sister's funeral. She saw this man at her mother's funeral and fell in love. With the hope to meet the man, she killed her sister.
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A Man Was Born In 2003 Riddle

Hint:
He was born in hospital room 2003
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I'm Essential For Teams To Work Well

Hint: It's a five-letter word that starts with "T."
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Solved: 0%

The 100 Pound Watermelon

Hint:
50 pounds.

In the beginning it is 99 pounds water and 1 pound other stuff. At the end the 1 pound other stuff is 2 percent so the total weight is 50 pounds. 50 pounds - 1 pound other stuff = 49 pounds water. So 99 pounds - 49 pounds = 50 pounds water lost.
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A 100 Year Old Ant

Hint:
An antique!
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Halfway To 100

Hint:
50
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I Am Close To 100

Hint:
98.
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No Flying Saucers

Hint:
Earth
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500 Pound Canary Riddle

Hint:
Anywhere it wants!
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The 500 Pound Monster

Hint:
On a diet!
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The 100 Seat Airplane

Hint: You don't need to use complex math to solve this riddle. Consider these two questions: What happens if somebody sits in your seat? What happens if somebody sits in Steve's assigned seat?
The correct answer is 1/2.

The chase that the first person in line takes your seat is equal to the chance that he takes his own seat. If he takes his own seat initially then you have a 100% chance of sitting in your seat, if he takes your seat you have a 0 percent chance. Now after the first person has picked a seat, the second person will enter the plan and, if the first person has sat in his seat, he will pick randomly, and again, the chance that he picks your seat is equal to the chance he picks someone your seat. The motion will continue until someone sits in the first persons seat, at this point the remaining people standing in line which each be able to sit in their own seats. Well how does that probability look in equation form? (2/100) * 50% + (98/100) * ( (2/98) * 50% + (96/98) * ( (2/96) * (50%) +... (2/2) * (50%) ) ) This expansion reduces to 1/2.
An easy way to see this is trying the problem with a 3 or 4 person scenario (pretend its a car). Both scenarios have probabilities of 1/2.
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