Harry Potter And The Jobs
Hint: 1. Hermione was not interested in becoming an Auror.
2. Harry and the person who is in the Ministry both loved the color blue.
3. The teaching job came at the latest age.
4. The boys got the jobs at the youngest and oldest age.
5. Hermione wan
Ron: Auror, 19
Hermione: Ministry, 20
Harry: Teacher, 21 Did you answer this riddle correctly?
YES NO
Hermione: Ministry, 20
Harry: Teacher, 21 Did you answer this riddle correctly?
YES NO
Which Did They See Riddle
There were 2 children, the son and the daughter. The daughter was born on January 20th and the son was born on March 12th. Both of them were born in the morning. Which one did their parents see first?
Hint:
Equals Eight Riddle
Hint:
Mirror one of the threes and put it and the other three together to get an eight. Did you answer this riddle correctly?
YES NO
YES NO
5+5+5=550 Riddle
Hint:
Pronounced As One Letter
Pronounced as one letter, And written with three, Two letters there are, And two only in me. I'm double, I'm single, I'm black, blue, and gray, I'm read from both ends, And the same either way. What am I?
Hint:
Who Killed Them?
There was a very rich family, they lived in a big circular house. They had a maid, a butler, and a gardener. The parents were going to a party, so they tucked the younger kids into bed and kissed them goodnight and said goodbye and kissed the older kids goodnight. While the parents were gone the butler was feeding the older kids, the maid was dusting was dusting the corners, and the gardener was watering the plants. When the parents came home all of the kids were dead. Who killed the kids?
Hint:
The maid did because she said she was dusting the corners, but it's a circular house , so she had to be doing something else, which was killing the kids. Did you answer this riddle correctly?
YES NO
YES NO
Walking In The Rain
Samuel was out for a walk when it started to rain. He did not have an umbrella and he wasn't wearing a hat. His clothes were soaked, yet not a single hair on his head got wet. How could this happen?
Hint:
99 Points Riddle
While out bowling with his friends, a man managed to throw eight strikes (all ten pins knocked down in a single throw) and not a single gutter ball during the entire game. To his amazement, his final score was only 99 points! Assuming there were no penalties or fouls, can you come up with a ten frame scorecard with eight strikes and a final score of only 99 points?
Hint: If you knock down a single pin, for example at the far left of the back row, then repeat the same identical shot on your second throw, you'll score 0 points for your second throw (because there's no pin there anymore), but it's not a gutter ball as the s
Just to reiterate the hint, if you knock down a single pin, for example at the far left of the back row, then repeat the same identical shot on your second throw, you'll score 0 points for your second throw (because there's no pin there anymore), but it's not a gutter ball as the shot did not enter the gutter. Did you answer this riddle correctly?
YES NO
YES NO
Black As Night Riddle
With three eyes and a black as night, I frequently knock down ten men with a single strike! What am I?
Hint:
Miss Millie's Parrot
When Miss Millie purchased her new parrot, the salesman assured her that it would repeat any word it heard. About a week later, Miss Millie returned the parrot complaining it hadn't uttered a single word. Given that the salesman had spoken the truth about the parrot's abilities, why wouldn't the bird talk?
Hint:
Made Of Metal
These things are made of metal
You might have lots or just a single
If you give them a good shake
The noise that they make is a jingle
Its a?
You might have lots or just a single
If you give them a good shake
The noise that they make is a jingle
Its a?
Hint:
Three People Holding Gifts Riddle
This has three people holding gifts
And a few animals maybe
Plus shepherds, parents and angels
And in the center, a baby
What is this?
And a few animals maybe
Plus shepherds, parents and angels
And in the center, a baby
What is this?
Hint:
Displayed In December
I have a baby boy but Im not a parent
I have animals but Im not a zoo
I have a star but Im not a solar system
I have angels but Im not heaven
I have shepherds but no fields
Im displayed in December but Im not a Christmas tree
What am I?
I have animals but Im not a zoo
I have a star but Im not a solar system
I have angels but Im not heaven
I have shepherds but no fields
Im displayed in December but Im not a Christmas tree
What am I?
Hint:
Little Billy's Calculator
Little Billy has a calculator with 15 buttons. He has 10 keys for 0-9, a key for addition, multiplication, division, and subtraction. Finally, he has an = sign. However, Mark the Meanie messed up the programming on Billy's calculator. Now, whenever Billy presses any of the number keys, it comes up with a random single-digit number. The same goes for the four operations keys (+,-,x, /). So whenever Billy tries to press the + button, the calculator chooses randomly between addition, multiplication, subtraction, and division. The only key left untouched was the = sign.
Now, if Billy were to press one number key, one operation key, then another number key, then the = button, what are the chances the answer comes out to 6?
Now, if Billy were to press one number key, one operation key, then another number key, then the = button, what are the chances the answer comes out to 6?
Hint: Think about how many ways he could possibly get 6.
There is a 4% chance.
There are 16 possible ways to get 6.
0+6
1+5
2+4
3+3
6+0
5+1
4+2
9-3
8-2
7-1
6-0
1x6
2x3
6x1
3x2
6/1
There are 400 possible button combinations.
When Billy presses any number key, there are 10 possibilities; when he presses any operation key, there are 4 possibilities.
10(1st#)x4(Operation)x10(2nd#)=400
16 working combinations/400 possible combinations= .04 or 4% Did you answer this riddle correctly?
YES NO
There are 16 possible ways to get 6.
0+6
1+5
2+4
3+3
6+0
5+1
4+2
9-3
8-2
7-1
6-0
1x6
2x3
6x1
3x2
6/1
There are 400 possible button combinations.
When Billy presses any number key, there are 10 possibilities; when he presses any operation key, there are 4 possibilities.
10(1st#)x4(Operation)x10(2nd#)=400
16 working combinations/400 possible combinations= .04 or 4% Did you answer this riddle correctly?
YES NO
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
Add Your Riddle Here
Have some tricky riddles of your own? Leave them below for our users to try and solve.