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Riddles and Answers © 2024

The Walls Of Jericho

Hint:
Joshua
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Two Tablets Of Stone

Hint:
Moses
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The Holy Trinity

Hint:
Jesus
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Hung Around Peoples Necks

Hint:
A cross
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A Symbol Of Christianity

Hint:
Its a cross
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Parents, Shepherds And Kings

Hint:
A Nativity Scene
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Displayed In December

Hint:
A nativity scene
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Dimples And A Nose

Hint:
A new baby!
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Full Of Holes

Hint:
A sponge
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Fastening Two People

Hint:
A wedding ring
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Filling Empty Hands

Hint:
Gloves
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A Bath Without Water

Hint:
A sun bath
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Roll The Dice

Hint: What will happen if there are 6 gamblers, each of whom bet on a different number?
It's a fair game. If there are 6 gamblers, each of whom bet on a different number, the dealer will neither win nor lose on each deal.

If he rolls 3 different numbers, e.g. 1, 2, 3, the three gamblers who bet 1, 2, 3 each wins $1 while the three gamblers who bet 4, 5, 6 each loses $1.

If two of the dice he rolls show the same number, e.g. 1, 1, 2, the gambler who bet 1 wins $3, the gambler who bet 2 wins $1, and the other 4 gamblers each loses $1.

If all 3 dice show the same number, e.g. 1, 1, 1, the gambler who bet 1 wins $5, and the other 5 gamblers each loses $1.

In each case, the dealer neither wins nor loses. Hence it's a fair game.
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The Secret Santa Exchange

Hint: It's not as difficult as it seems. It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10

For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is

(n-1)! / n!

Since n! = (n-1)! * n (for n > 1), this can be rewritten as

(n-1)! / (n*(n-1)!)

Factoring out the (n-1)! from the numerator and denominator leaves

1/n

as the probability.
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A Thought In Your Mind

Hint:
Memory
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