HOW MANY HAVE GUESSED 3 GIFTS CORRECTLY AND HOW MANY 4 GIFTS CORRECTLY RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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This Does Reflect Riddle

Hint:
Mirror
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Always Tells The Truth Riddle

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Mirror
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Look In My Face Riddle

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Mirror
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Open Me Up Riddle

Hint:
Refrigerator
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I Can Be Tuned Riddle

Hint:
Piano
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Baseball And Piano Riddle

Hint:
Because his player had the perfect pitch!
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Eight Hands Riddle

Hint:
Spider
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Something With A Palm Riddle

Hint:
Hand
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Two Have Ten

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Hand
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Put It In A Glove

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Hand
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Three People In A Room

Hint:
Simple strategy: Elect one person to be the guesser, the other two pass. The guesser chooses randomly 'green' or 'blue'. This gives them a 50% chance of winning.


Better strategy: If you see two blue or two green hats, then write down the opposite color, otherwise write down 'pass'.

It works like this ('-' means 'pass'):

Hats: GGG, Guess: BBB, Result: Lose
Hats: GGB, Guess: --B, Result: Win
Hats: GBG, Guess: -B-, Result: Win
Hats: GBB, Guess: G--, Result: Win
Hats: BGG, Guess: B--, Result: Win
Hats: BGB, Guess: -G-, Result: Win
Hats: BBG, Guess: --G, Result: Win
Hats: BBB, Guess: GGG, Result: Lose

Result: 75% chance of winning!
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The Secret Santa Exchange

Hint: It's not as difficult as it seems. It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10

For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is

(n-1)! / n!

Since n! = (n-1)! * n (for n > 1), this can be rewritten as

(n-1)! / (n*(n-1)!)

Factoring out the (n-1)! from the numerator and denominator leaves

1/n

as the probability.
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Kindness And Cruelty

Hint:
Fate
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Counting Time Riddle

Hint:
Four-ever!
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Taking You To School

Hint:
School Bus
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