## How Many Presents Can Santa Fit In An Empty Sack Riddles To Solve

## Solving How Many Presents Can Santa Fit In An Empty Sack Riddles

Here we've provide a compiled a list of the best how many presents can santa fit in an empty sack puzzles and riddles to solve we could find.Our team works hard to help you piece fun ideas together to develop riddles based on different topics. Whether it's a class activity for school, event, scavenger hunt, puzzle assignment, your personal project or just fun in general our database serve as a tool to help you get started.

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## The Secret Santa Exchange

A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.

When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.

What is the probability that the 10 friends holding hands form a single continuous circle?

When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.

What is the probability that the 10 friends holding hands form a single continuous circle?

Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.

1/10

For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is

(n-1)! / n!

Since n! = (n-1)! * n (for n > 1), this can be rewritten as

(n-1)! / (n*(n-1)!)

Factoring out the (n-1)! from the numerator and denominator leaves

1/n

as the probability.

YES NO

For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is

(n-1)! / n!

Since n! = (n-1)! * n (for n > 1), this can be rewritten as

(n-1)! / (n*(n-1)!)

Factoring out the (n-1)! from the numerator and denominator leaves

1/n

as the probability.

*Did you answer this riddle correctly?*YES NO

## An Empty Stomach Riddle

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## Santa And A Space Ship

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## Santa's Helpers Riddle

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## Santa's Coal Riddle

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## The Fitness Center Riddle

Two pro athletes decided to work out. At 6:00 pm, the athletes began the workout at their fitness center. One ran 10 miles at 10 miles per hour, and one cycled 6 miles at 6 miles per hour. Then they both ran at 2.5 miles an hour for 15 minutes. The athletes never took any breaks, and they started at the same time and place. How is it possible that they ended at the same place?

Hint:

They were at the fitness center the whole time. They ran and cycled on exercise equipment.

YES NO

*Did you answer this riddle correctly?*YES NO

## Standstill Santa Riddle

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## Santa's Slay Riddle

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## Santa's Gardens Riddle

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## Deep Fried Santa Riddle

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## Emptying A Backpack

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## Easter Bunny Fitness Riddle

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## Detective Santa Riddle

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## The Ghost And Santa Riddle

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## Santa's Birthday Riddle

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## Add Your Riddle Here

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