30 Sacks Of Coconuts
An intelligent trader travels from one place to another with 3 sacks having 30 coconuts each. No sack can hold more than 30 coconuts. On the way, he passes 30 check points. At each check point, he has to give one coconut for every sack he is carrying. What is the maximum number of coconuts that he can have with him at the end of his journey?
Hint:
He will have 25 coconuts with him at the end. The trick is to reduce the number of sacks as you pass checkpoints.
The first 10 checkpoints require 3 coconuts each, which empties his first sack. The next 15 checkpoints require 2 coconuts each, which will empty his second stack. Now, he is left with 1 sack and 5 more checkpoints. So, the 5 checkpoints will take 1 coconut each. Therefore, he will be left with 25 coconuts. Did you answer this riddle correctly?
YES NO
The first 10 checkpoints require 3 coconuts each, which empties his first sack. The next 15 checkpoints require 2 coconuts each, which will empty his second stack. Now, he is left with 1 sack and 5 more checkpoints. So, the 5 checkpoints will take 1 coconut each. Therefore, he will be left with 25 coconuts. Did you answer this riddle correctly?
YES NO
Meeting In The Office
If you have a meeting in the office
Youll need to know the time and place
Something that can help with one of these things
Has two or three hands over its face
What is this?
Youll need to know the time and place
Something that can help with one of these things
Has two or three hands over its face
What is this?
Hint:
Leaving Innocent
There was a man named Luis accused of killing a women a few nights ago. A week later, he goes to court with his brother, Jhon. They know it was Luis who did it, but he leaves the court room innocent. How is this?
Hint:
Finding The Clues
Hercule Poirot Detective reviewed the information they had on the case so far.
A lady named 'monica' was found shot and Hercule already had a list of suspects: rooney, torres, dabid, messi, ronaldo
Killer is a fan of Hercule and chalenge him by leaving notes at various places.
# The first was found in a drawing room.
# The second was found in an art room.
# The third was in a bed room.
# the fourth in an ice-cream room.
# The fifth at the desk room
All of the notes read the same thing, 'The clues are where you find the notes.' Still, nothing was found anywhere.
Hercule Poirot pause for a moment and then arrested the killer. Who was the killer?
A lady named 'monica' was found shot and Hercule already had a list of suspects: rooney, torres, dabid, messi, ronaldo
Killer is a fan of Hercule and chalenge him by leaving notes at various places.
# The first was found in a drawing room.
# The second was found in an art room.
# The third was in a bed room.
# the fourth in an ice-cream room.
# The fifth at the desk room
All of the notes read the same thing, 'The clues are where you find the notes.' Still, nothing was found anywhere.
Hercule Poirot pause for a moment and then arrested the killer. Who was the killer?
Hint:
Dabid is the killer
drawing room(D) , art room(a) , bed room (b) , ice-cream room (i) , desk room (d) Did you answer this riddle correctly?
YES NO
drawing room(D) , art room(a) , bed room (b) , ice-cream room (i) , desk room (d) Did you answer this riddle correctly?
YES NO
Five Prom Couples Riddle
Five couples went to the prom as a group. The boys' names were Mark, Quintin, Jim, Bob, and James. The girls' names were Amanda, Betty, Susan, Jessica, and Jasmin. Each couple wore matching colors of either blue, yellow, red, green, or pink. Match the dates and the color they are wearing.
1) Two couples have the same first letter in their name. One of those letters is "B".
2) Susan wore red and Jessica wore blue.
3) Susan has more letters in her name than her date does.
4) Neither Mark nor Quintin went with Jasmin, who was wearing yellow.
5) Amanda went with Jim and they did not wear green.
1) Two couples have the same first letter in their name. One of those letters is "B".
2) Susan wore red and Jessica wore blue.
3) Susan has more letters in her name than her date does.
4) Neither Mark nor Quintin went with Jasmin, who was wearing yellow.
5) Amanda went with Jim and they did not wear green.
Hint:
Mark and Susan wore red.
Quintin and Jessica wore blue.
Jim and Amanda wore pink.
Bob and Betty wore green.
James and Jasmin wore yellow. Did you answer this riddle correctly?
YES NO
Quintin and Jessica wore blue.
Jim and Amanda wore pink.
Bob and Betty wore green.
James and Jasmin wore yellow. Did you answer this riddle correctly?
YES NO
Throwing A Basketball Riddle
A man takes a basketball and throws it as hard as he can. There is nothing in front, behind, or on either side of him, and yet, the ball comes back and hits him square in the face. How can this be?
Hint:
Crossing The Desert Riddle
A camel driver has to cross the desert and get to the Nile River to transport his merchandise. It takes six weeks to cross the desert and get to the Nile River. He can only carry four weeks of food for himself and his camel at any time because the camel also has to carry his merchandise. If he can not get help from anyone else or get anymore camels, and there is an unlimited supply of food where he is at, how can he cross the desert and get to the Nile River?
Hint:
He takes four weeks of food and leaves two weeks of food supplies in the one week mark and goes back with the one week of food supply left. Then he goes back with four weeks of food and picks up one week of food supplies from the one week mark giving him four again in total, then he leaves two weeks of supply in the two week mark and goes back to the one week mark and picks up the one week food supply to go back. Then he leaves with the four weeks of food supply and goes to the two week mark and picks up the two week food supplies that were there giving him four weeks of food again, then he goes to the Nile River with the four weeks supply of food. Did you answer this riddle correctly?
YES NO
YES NO
Born In Mourning
I have a name, but it isn't my name. My face shows signs of age. I always mean the same thing, no matter what I say. I'm born in mourning, and I last 'til the end of days. Men plant me, but I never grow. They run from me, but I never move. They look at me and see their future, rotting in the fields where I bloom. What am I?
Hint:
Found In A Graveyard Riddle
I have writing on me but Im not a newspaper
I mark a spot but Im not a treasure map
I have names and dates on me but Im not a birth certificate
Im not needed if youre alive but Im not a coffin
I can be found in a graveyard but Im not a bunch of flowers
I'm a...
I mark a spot but Im not a treasure map
I have names and dates on me but Im not a birth certificate
Im not needed if youre alive but Im not a coffin
I can be found in a graveyard but Im not a bunch of flowers
I'm a...
Hint:
Mortal Privation Riddle
Marking mortal privation, when firmly in place.
An enduring summation, inscribed in my face.
What am I?
An enduring summation, inscribed in my face.
What am I?
Hint:
A Character In Thomas And Friends
Shes a character in Thomas And Friends
But her names not Emily I should stress
She also has the name of a flower
And in Mario games shes a Princess
What could I be?
But her names not Emily I should stress
She also has the name of a flower
And in Mario games shes a Princess
What could I be?
Hint:
Lazily In The Sun
My head bobs lazily in the sun. You think I'm cute, For my face is yellow, My hair is white, and my body is green. What am I?
Hint:
Roll The Dice
A gambler goes to bet. The dealer has 3 dice, which are fair, meaning that the chance that each face shows up is exactly 1/6.
The dealer says: "You can choose your bet on a number, any number from 1 to 6. Then I'll roll the 3 dice. If none show the number you bet, you'll lose $1. If one shows the number you bet, you'll win $1. If two or three dice show the number you bet, you'll win $3 or $5, respectively."
Is it a fair game?
The dealer says: "You can choose your bet on a number, any number from 1 to 6. Then I'll roll the 3 dice. If none show the number you bet, you'll lose $1. If one shows the number you bet, you'll win $1. If two or three dice show the number you bet, you'll win $3 or $5, respectively."
Is it a fair game?
Hint: What will happen if there are 6 gamblers, each of whom bet on a different number?
It's a fair game. If there are 6 gamblers, each of whom bet on a different number, the dealer will neither win nor lose on each deal.
If he rolls 3 different numbers, e.g. 1, 2, 3, the three gamblers who bet 1, 2, 3 each wins $1 while the three gamblers who bet 4, 5, 6 each loses $1.
If two of the dice he rolls show the same number, e.g. 1, 1, 2, the gambler who bet 1 wins $3, the gambler who bet 2 wins $1, and the other 4 gamblers each loses $1.
If all 3 dice show the same number, e.g. 1, 1, 1, the gambler who bet 1 wins $5, and the other 5 gamblers each loses $1.
In each case, the dealer neither wins nor loses. Hence it's a fair game. Did you answer this riddle correctly?
YES NO
If he rolls 3 different numbers, e.g. 1, 2, 3, the three gamblers who bet 1, 2, 3 each wins $1 while the three gamblers who bet 4, 5, 6 each loses $1.
If two of the dice he rolls show the same number, e.g. 1, 1, 2, the gambler who bet 1 wins $3, the gambler who bet 2 wins $1, and the other 4 gamblers each loses $1.
If all 3 dice show the same number, e.g. 1, 1, 1, the gambler who bet 1 wins $5, and the other 5 gamblers each loses $1.
In each case, the dealer neither wins nor loses. Hence it's a fair game. Did you answer this riddle correctly?
YES NO
The Same Birthday Riddle
How many people must be gathered together in a room, before you can be certain that there is a greater than 50/50 chance that at least two of them have the same birthday?
Hint:
Only twenty-three people need be in the room, a surprisingly small number. The probability that there will not be two matching birthdays is then, ignoring leap years, 365x364x363x...x343/365 over 23 which is approximately 0.493. this is less than half, and therefore the probability that a pair occurs is greater than 50-50. With as few as fourteen people in the room the chances are better than 50-50 that a pair will have birthdays on the same day or on consecutive days. Did you answer this riddle correctly?
YES NO
YES NO
Four Balls In A Bowl
This is a famous paradox probability riddle which has caused a great deal of argument and disbelief from many who cannot accept the correct answer.
Four balls are placed in a bowl. One is Green, one is Black and the other two are Yellow. The bowl is shaken and someone draws two balls from the bowl. He looks at the two balls and announces that at least one of them is Yellow. What are the chances that the other ball he has drawn out is also Yellow?
Four balls are placed in a bowl. One is Green, one is Black and the other two are Yellow. The bowl is shaken and someone draws two balls from the bowl. He looks at the two balls and announces that at least one of them is Yellow. What are the chances that the other ball he has drawn out is also Yellow?
Hint:
1/5
There are six possible pairings of the two balls withdrawn,
Yellow+Yellow
Yellow+Green
Green+Yellow
Yellow+Black
Black+Yellow
Green+Black.
We know the Green + Black combination has not been drawn.
This leaves five possible combinations remaining. Therefore the chances tbowl the Yellow + Yellow pairing has been drawn are 1 in 5.
Many people cannot accept tbowl the solution is not 1 in 3, and of course it would be, if the balls had been drawn out separately and the color of the first ball announced as Yellow before the second had been drawn out. However, as both balls had been drawn together, and then the color of one of the balls announced, then the above solution, 1 in 5, must be the correct one. Did you answer this riddle correctly?
YES NO
There are six possible pairings of the two balls withdrawn,
Yellow+Yellow
Yellow+Green
Green+Yellow
Yellow+Black
Black+Yellow
Green+Black.
We know the Green + Black combination has not been drawn.
This leaves five possible combinations remaining. Therefore the chances tbowl the Yellow + Yellow pairing has been drawn are 1 in 5.
Many people cannot accept tbowl the solution is not 1 in 3, and of course it would be, if the balls had been drawn out separately and the color of the first ball announced as Yellow before the second had been drawn out. However, as both balls had been drawn together, and then the color of one of the balls announced, then the above solution, 1 in 5, must be the correct one. Did you answer this riddle correctly?
YES NO
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