IF YOU PUT THREE FINGERS IN THESE HOL RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Riddles and Answers © 2024

Hanukkah Dragons Riddle

Hint:
One lasts for eight nights, the other simply ate knights!
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Festive Faucets

Hint:
I have a little dribble! (Dreidel)
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Granny's Gifts Riddle

Hint:
A latke hugs and kisses!
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Doughy Greetings Riddle

Hint:
Happy Challah-days!
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I Light Them All

Hint:
Shamash
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Given Each Night Riddle

Hint:
I am a gift.
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Santa's Helpers Riddle

Hint:
Elves
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Adorning Doors Riddle

Hint:
Wreath
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Keeping Things Cold

Hint:
Refrigerator
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Labor Day Events Riddle

Hint:
As little as possible, just like every day!
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Hearing Santas Sleigh

Hint:
Bells!
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Good Friday Riddle

Hint:
The cross
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Under The Cup Riddle

Hint: Write down the possibilities. Remember that there are only three cups, so if the rightmost cup wasn't touched...
The rightmost cup.

The rightmost cup has a half chance of holding the coin, and the other cups have a quarter chance.

Pretend that Os represent cups, and Q represents the cup with the coin.

The game starts like this:

OOQ

Then your friend switches the rightmost cup with another, giving two possibilities, with equal chance:

OQO
QOO

Your friend then moves the cups again, but doesn't touch the rightmost cup. The only switch possible is with the leftmost cup and the middle cup. This gives two possibilities with equal chance:

QOO
OQO

Lastly, your friend switches the rightmost cup with another cup. If the first possibility shown above was true, there would be two possibilities, with equal chance:

OOQ
QOO

If the second possibility shown above (In the second switch) was true, there would be two possibilities with equal chance:

OOQ
OQO

This means there are four possibilities altogether, with equal chance:

OOQ
QOO
OOQ
OQO

This means each possibility equals to a quarter chance, and because there are two possibilities with the rightmost cup having the coin, there is a half chance that the coin is there.
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The Secret Santa Exchange

Hint: It's not as difficult as it seems. It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10

For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is

(n-1)! / n!

Since n! = (n-1)! * n (for n > 1), this can be rewritten as

(n-1)! / (n*(n-1)!)

Factoring out the (n-1)! from the numerator and denominator leaves

1/n

as the probability.
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Blue Christmas Riddle

Hint:
Elfis!
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