Five Bridesmaids Riddle
Five bridesmaids threw a shower for their bride. Each brought a gift and made a favorite food of the bride. They all arrived at different times, and during the wedding each was wearing a different color of her choice. Determine the gift and food each bridesmaid brought, the time she arrived, and what color she chose for her dress.
1. The bridesmaid with the painting had trouble getting it in her car, and the bridesmaid with the potato salad got lost on the way, so they were the last two to arrive.
2. Amanda hated the color green and potato salad.
3. Kourtney and Selena did not wear the blue dress and did not bring the turkey sandwiches.
4. Stacie arrived before the bridesmaid with the painting, but after the bridesmaid who brought the sheets, and the bridesmaid who made the cheese dip.
5. The bridesmaid with a blue dress arrived 10 minutes before the bridesmaid who brought the sandwiches.
6. The bridesmaid with the veggie tray arrived 25 minutes after the bridesmaid who brought flatware, but before the bridesmaid who would be wearing a blue dress.
7. The five bridesmaids arrived in the following order: The one who baked the cake, Amanda, the one who would be wearing a yellow dress, the one with a toaster for a gift, and the one who arrived last.
8. Selena brought a cake with green frosting, the same color as her dress.
9. Amanda brought pink sheets as a gift to the bride, but she did not like pink for herself.
1. The bridesmaid with the painting had trouble getting it in her car, and the bridesmaid with the potato salad got lost on the way, so they were the last two to arrive.
2. Amanda hated the color green and potato salad.
3. Kourtney and Selena did not wear the blue dress and did not bring the turkey sandwiches.
4. Stacie arrived before the bridesmaid with the painting, but after the bridesmaid who brought the sheets, and the bridesmaid who made the cheese dip.
5. The bridesmaid with a blue dress arrived 10 minutes before the bridesmaid who brought the sandwiches.
6. The bridesmaid with the veggie tray arrived 25 minutes after the bridesmaid who brought flatware, but before the bridesmaid who would be wearing a blue dress.
7. The five bridesmaids arrived in the following order: The one who baked the cake, Amanda, the one who would be wearing a yellow dress, the one with a toaster for a gift, and the one who arrived last.
8. Selena brought a cake with green frosting, the same color as her dress.
9. Amanda brought pink sheets as a gift to the bride, but she did not like pink for herself.
Hint:
Selena; green; flatware; cake; 2:50
Amanda; purple; sheets; veggie tray; 3:15
Kourtney; yellow; towels; cheese dip; 3:20
Stacie; blue; toaster; potato salad; 3:35
Stephanie; pink; painting; turkey sandwiches; 3:45 Did you answer this riddle correctly?
YES NO
Amanda; purple; sheets; veggie tray; 3:15
Kourtney; yellow; towels; cheese dip; 3:20
Stacie; blue; toaster; potato salad; 3:35
Stephanie; pink; painting; turkey sandwiches; 3:45 Did you answer this riddle correctly?
YES NO
Carried In A Box Riddle
Before you get engaged
In a small box it is carried
It is what gets exchanged
On the day that you get married
In a small box it is carried
It is what gets exchanged
On the day that you get married
Hint:
Beginning And End Riddle
Hint:
Prince Age Riddle
What are their ages?
Hint:
Current Future Past
Princess x 2z (x+y)/2
Prince y x z
I then created three equations, since the difference in their age will always be the same.
d = the difference in ages
x y = d
2z x = d
x/2 + y/2 z = d
I then created a matrix and solved it using row reduction.
x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d
It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
This means that you can pick any difference you want (an even one presumably because you want integer ages).
Princess age: 4d
Prince age: 3d
Ages that work
Princess:
4
8
16
24
32
40
48
56
64
72
80
Prince:
3
6
12
18
24
30
36
42
48
54
60 Did you answer this riddle correctly?
YES NO
Princess x 2z (x+y)/2
Prince y x z
I then created three equations, since the difference in their age will always be the same.
d = the difference in ages
x y = d
2z x = d
x/2 + y/2 z = d
I then created a matrix and solved it using row reduction.
x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d
It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
This means that you can pick any difference you want (an even one presumably because you want integer ages).
Princess age: 4d
Prince age: 3d
Ages that work
Princess:
4
8
16
24
32
40
48
56
64
72
80
Prince:
3
6
12
18
24
30
36
42
48
54
60 Did you answer this riddle correctly?
YES NO
Pulled Over Blonde
Hint:
Her headlights weren't working, so she was flashing people. Did you answer this riddle correctly?
YES NO
YES NO
100 Blank Cards Riddle
Someone offers you the following deal:
There is a deck of 100 initially blank cards. The dealer is allowed to write ANY positive integer, one per card, leaving none blank. You are then asked to turn over as many cards as you wish. If the last card you turn over is the highest in the deck, you win; otherwise, you lose.
Winning grants you $50, and losing costs you only the $10 you paid to play.
Would you accept this challenge?
There is a deck of 100 initially blank cards. The dealer is allowed to write ANY positive integer, one per card, leaving none blank. You are then asked to turn over as many cards as you wish. If the last card you turn over is the highest in the deck, you win; otherwise, you lose.
Winning grants you $50, and losing costs you only the $10 you paid to play.
Would you accept this challenge?
Hint: Perhaps thinking in terms of one deck is the wrong approach.
Yes!
A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."
Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).
This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.
Obviously, you have to have at least $40 to start in order to apply this strategy effectively. Did you answer this riddle correctly?
YES NO
A sample strategy:
Divide the deck in half and turn over all lower 50 cards, setting aside the highest number you find. Then turn over the other 50 cards, one by one, until you reach a number that is higher than the card you set aside: this is your chosen "high card."
Now, there is a 50% chance that the highest card is contained in the top 50 cards (it is or it isn't), and a 50% chance that the second-highest card is contained in the lower 50. Combining the probabilities, you have a 25% chance of constructing the above situation (in which you win every time).
This means that you'll lose three out of four games, but for every four games played, you pay $40 while you win one game and $50. Your net profit every four games is $10.
Obviously, you have to have at least $40 to start in order to apply this strategy effectively. Did you answer this riddle correctly?
YES NO
Age Of Three Daughters Riddles
I was visiting a friend one evening and remembered that he had three daughters. I asked him how old they were. The product of their ages is 72, he answered. Quizzically, I asked, Is there anything else you can tell me? Yes, he replied, the sum of their ages is equal to the number of my house. I stepped outside to see what the house number was. Upon returning inside, I said to my host, Im sorry, but I still cant figure out their ages. He responded apologetically, Im sorry, I forgot to mention that my oldest daughter likes strawberry shortcake. With this information, I was able to determine all three of their ages. How old is each daughter?
Hint:
3, 3, and 8. The only groups of 3 factors of 72 to have non-unique sums are 2 6 6 and 3 3 8 (with a sum of 14). The rest have unique sums:
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
What Begins With T, Ends With T And Has T In It?
Hint:
Tweety Birds Wife Riddle
Hint:
If In The End Is D Then What Was In The Beginning Riddle
Hint:
E ( in word end d is in the end and e in the beginning ) Did you answer this riddle correctly?
YES NO
YES NO
What Begins With T Ends With T And Has T In It Riddle
Hint:
1 Year Of Chickens
There are five hen and rooster pairs. Each pair has one baby every month.
How many chickens will there be in one year?
How many chickens will there be in one year?
Hint:
It is impossible to know because the chicken's babies could also have babies during this time.
Did you answer this riddle correctly?
YES NO
Did you answer this riddle correctly?
YES NO
Burns Fat But Saves You Money
Hint:
Shot In The Car Riddle
A man was shot to death while in his car. There were no powder marks on his clothing, which indicated that the gunman was outside the car. However, all the windows were up and the doors locked. After a close inspection was made, the only bullet-holes discovered were on the mans body. How was he murdered?
Hint:
The victim was in a convertible. He was shot when the top was down. Did you answer this riddle correctly?
YES NO
YES NO
Almost Hit By A Car Riddle
A man walked home after having been out drinking. He walked down the middle of a deserted country road. There were no streetlights to illuminate the road and there was no moonlight. He was dressed all in black. Suddenly a car that did not have its headlights on came racing down the road. At the last moment, the driver of the car saw the man and swerved to avoid him.
How did he manage to see him?
How did he manage to see him?
Hint:
He was returning home in the middle of the day, so anyone could have seen him. Did you answer this riddle correctly?
YES NO
YES NO
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