MATH BRA RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

Find the value of one clock using the first equation. According to first equation, 9’o clock + 9’o clock + 3'o clock = 9 + 9 + 3 = 21.

Therefore; 1 Clock = 1

Using equation two, three calculators are equal to 30. Therefore, one calculator is equal to 10.

Also, the sum of numbers inside the calculator is 1 + 2 + 3 + 4 = 10.

Therefore, the value of the calculator depends on the sum of the numbers inside it.

According to equation three, 1 Bulb + 1 Bulb - 1 Bulb = 15.

Cancelling out the + and -; we get 1 Bulb with five lights = 15
.
Therefore, one bulb with one light = 3.

Bulb with four lights = 4 x 3 = 12.

The final equation is - 9’o clock + Calculator (1+2+2+4) x 3 bulbs (with four light rays each)

Translating the final equation into numbers - 9 + (1+2+2+4) x 3(12)

9 + 9 x 36 = 9 + 324 = 333.

Answer to 'Watch Calculator bulb' puzzle is 333. Did you answer this riddle correctly?
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25 Did you answer this riddle correctly?
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1 Chicken = 20 - So, 20 + 20 + 20 = 60
1 Egg Basket = 3 - So, 20 + 3 + 3 = 26
1 Bunch of Bananas = 6 - So, 3 + 6 + 6 = 15
Finally, Chicken = 20 ; Egg Basket = 3 ; Bananas = 6 - So, 20 + 3 x 5 = 35

The final answer is 35 Did you answer this riddle correctly?
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Answer: 73 ...Broom - 3 (2nd picture compose of 2 brooms) that gives you 3+3+3+3 = 12 ...Wand - 7 (3 wands equal 21) ...Witch - 5 (15 each while carrying broom and wand giving you 45, so remove them in the last picture ...So 3 + (5x14) = 73 Did you answer this riddle correctly?
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Use the number 5 three times, 55 + 5 = 60 Did you answer this riddle correctly?
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Six on one side - six on the other = one side is heavier.

Take the heavier six men, divide them into three and three (random).

Three on one side - three on the other = one side will one heavier.

Divide that three men from the heavier side side, have one on one side - one on the other.

Two results can determine which of the last three men weight is a different weight than each other.

With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.

Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.

You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."

Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
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If you said 5000 you're wrong! The answer is 4100, how?

1000 + 40 = 1040
1040 + 1000 + 30 = 2070
2070 + 1000 + 20 = 3090
3090 + 1000 = 4090
4090 + 10 = 4100 Did you answer this riddle correctly?
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The neighbour borrowed an extra cow, to make the total number of cows 18. Then the oldest son got 1/2 of 18 is 9 cows, the middle son got 1/3 of 18 is 6 cows, and the youngest son got 1/9 of 18 is 2 cows. Since 9+6+2 = 17, the cows could be divided among the three brothers in such a way that the borrowed cow was left over, and could be returned to its owner. Did you answer this riddle correctly?
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12 (Twelve) has 6 letters,

6 (Six) has 3

Therefore,

10 (Ten) will be equal to 3 Did you answer this riddle correctly?
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Total Money taken = $100($50+$50)

Now,

Bag's Price = $ 97

Remaining Amount = $100 - $97

= $ 3

Returned = $ 1 + $ 1

=$2

In pocket = $1

Total money owed = $100- ( Returned amount)

= $98( Bag's amount and reserved amount)

So, it was a calculation mistake. Did you answer this riddle correctly?
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121

Explanation
Tables consist of squares of the number from 4 to 12.
11^2 = 121. Did you answer this riddle correctly?
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The loss is $100. Did you answer this riddle correctly?
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The third equation has a term with a pair of whistles. The last line involves a single whistle.

Furthermore, the man in the second and third lines are wearing a whistle, but the man in the last line is not wearing a whistle. Presumably the value of the whistle should be accounted for to get the correct answer.

The pictures can be translated into the following equations:

shoes + shoes + shoes = 30
shoes + (man + whistle) + (man + whistle) = 20
(man + whistle) + 2(whistles) + 2(whistles) = 13
shoes + (man) x (whistle) = ?

From the first equation we can solve for the shoes value:

shoes + shoes + shoes = 30
3(shoes) = 30
shoes = 10

We can then solve the second equation for the (man + whistle) value:

shoes + (man + whistle) + (man + whistle) = 20
10 + 2(man + whistle) = 20
2(man + whistle) = 10
man + whistle = 5

Then we solve the third equation for the whistle:

(man + whistle) + 2(whistles) + 2(whistles) = 13
5 + 4(whistles) = 13
4(whistles) = 8
whistle = 2

We also need to solve for the value of the man:

man + whistle = 5
man + 2 = 5
man = 3

Now we can evaluate the final expression, remembering the order of operations that multiplication should be evaluated before addition:

shoes + (man) x (whistle) = ?

10 + 3 x 2
= 10 + 3 x 2
= 10 + 6
= 16 Did you answer this riddle correctly?
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The best answer from the choices is the owner lost $100. The $100 bill that was stolen was then given back to the owner. What the owner loses is the $70 worth of goods and the $30 in change, which makes for a total of $70 + $30 = $100. The owner has lost $100.

Technically, the owner lost $30 plus the value, V, of the $70 of goods. Since stores typically sell goods at a markup, the value may be less than $70. But in the case of a loss leader, the owner may have lost more than $70. Did you answer this riddle correctly?
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38

Logic :
From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38. Did you answer this riddle correctly?
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