7 Men Have 7 Wives Riddle
Hint:
If 7 men have 7 wives that simply means there are 7 coupled, so that is 7 +7 = 14.
Then, if each couple has a child, that's 14 + 7 = 21.
So the total number of people is 21. Did you answer this riddle correctly?
YES NO
Then, if each couple has a child, that's 14 + 7 = 21.
So the total number of people is 21. Did you answer this riddle correctly?
YES NO
If Eleven Plus Two Equals One Riddle
Hint:
11 o'clock plus 2 hours = 1 o'clock
9 o'clock plus 5 hours = 2 o'clock Did you answer this riddle correctly?
YES NO
9 o'clock plus 5 hours = 2 o'clock Did you answer this riddle correctly?
YES NO
What Remains When The Roads Are Gone Riddle
A race car driver has completed 12 1/2 laps of a 50-lap race. What fractional part of the race remains?
Hint:
Let's take a look at the explanation of the riddle.
As per the total laps in the race are 50 and the driver has completed 12 1/2 laps. This means, we have to subtract 12 1/2 from the total 50 laps. This equal to 37 1/2 or 37.5
50 - 12 1/2 = 37 1/2 or 37.5
Now, we need to calculate the fractional part of the race remains. For this, we need to divide the remaining laps by total laps, that is, 37 1/2 divide by 50 or 37.5 divided by 50 which will be equal to 0.74 or 3/4.
37 1/2 / 50 = 0.74 or 3/4
Hence, the right answer to the riddle is 3/4 Did you answer this riddle correctly?
YES NO
As per the total laps in the race are 50 and the driver has completed 12 1/2 laps. This means, we have to subtract 12 1/2 from the total 50 laps. This equal to 37 1/2 or 37.5
50 - 12 1/2 = 37 1/2 or 37.5
Now, we need to calculate the fractional part of the race remains. For this, we need to divide the remaining laps by total laps, that is, 37 1/2 divide by 50 or 37.5 divided by 50 which will be equal to 0.74 or 3/4.
37 1/2 / 50 = 0.74 or 3/4
Hence, the right answer to the riddle is 3/4 Did you answer this riddle correctly?
YES NO
McDonalds Riddle
A brainteaser involving what looks like some simple math with McDonald's burgers and fries has left people starving for the correct answer. Can you solve this McDonalds riddle?
Hint: The key is to first determine how much each item is worth. The drink is clearly worth 10, and it's apparent from the second line that the burgers are worth five.
Pictures of the fries are each worth two, but you have to keep in mind that each individual packet of fries is worth one when you get to the next line. That has baited people into thinking, incorrectly, that the last line is 5 + 2 x 10.
The fourth line has also thrown many people off because it involves order of operations after already including the tricky single packet of fries.
Multiplication comes before addition, so you have to multiply one packet of fries by one drink and then add that to one burger. Thus, 5 + (1x10) = 15. Did you answer this riddle correctly?
YES NO
The fourth line has also thrown many people off because it involves order of operations after already including the tricky single packet of fries.
Multiplication comes before addition, so you have to multiply one packet of fries by one drink and then add that to one burger. Thus, 5 + (1x10) = 15. Did you answer this riddle correctly?
YES NO
I Had 3.00 Riddle
I had $3.00. My mom gave me $10.00 while my dad gave me $30.00. My aunt and uncle gave me $100.00. I had another $5.00. How much did I have?
Hint:
The correct answer is 8 dollars. If you read the question carefully, the question asked about your first money with "how much money Did I really have?"
The money you had is 10 dollars. That is before your parents and relatives gave you additional money.
However, given that the logic and time of the tense is in the past, it is safe to assume that the question pertains to the money you had originally before you received external money from someone else. Did you answer this riddle correctly?
YES NO
The money you had is 10 dollars. That is before your parents and relatives gave you additional money.
However, given that the logic and time of the tense is in the past, it is safe to assume that the question pertains to the money you had originally before you received external money from someone else. Did you answer this riddle correctly?
YES NO
Clock Calculator Bulb Riddle
Hint:
Find the value of one clock using the first equation. According to first equation, 9’o clock + 9’o clock + 3'o clock = 9 + 9 + 3 = 21.
Therefore; 1 Clock = 1
Using equation two, three calculators are equal to 30. Therefore, one calculator is equal to 10.
Also, the sum of numbers inside the calculator is 1 + 2 + 3 + 4 = 10.
Therefore, the value of the calculator depends on the sum of the numbers inside it.
According to equation three, 1 Bulb + 1 Bulb - 1 Bulb = 15.
Cancelling out the + and -; we get 1 Bulb with five lights = 15
.
Therefore, one bulb with one light = 3.
Bulb with four lights = 4 x 3 = 12.
The final equation is - 9’o clock + Calculator (1+2+2+4) x 3 bulbs (with four light rays each)
Translating the final equation into numbers - 9 + (1+2+2+4) x 3(12)
9 + 9 x 36 = 9 + 324 = 333.
Answer to 'Watch Calculator bulb' puzzle is 333. Did you answer this riddle correctly?
YES NO
Therefore; 1 Clock = 1
Using equation two, three calculators are equal to 30. Therefore, one calculator is equal to 10.
Also, the sum of numbers inside the calculator is 1 + 2 + 3 + 4 = 10.
Therefore, the value of the calculator depends on the sum of the numbers inside it.
According to equation three, 1 Bulb + 1 Bulb - 1 Bulb = 15.
Cancelling out the + and -; we get 1 Bulb with five lights = 15
.
Therefore, one bulb with one light = 3.
Bulb with four lights = 4 x 3 = 12.
The final equation is - 9’o clock + Calculator (1+2+2+4) x 3 bulbs (with four light rays each)
Translating the final equation into numbers - 9 + (1+2+2+4) x 3(12)
9 + 9 x 36 = 9 + 324 = 333.
Answer to 'Watch Calculator bulb' puzzle is 333. Did you answer this riddle correctly?
YES NO
Circle With 5 In The Middle Riddle
Hint:
How Many 9 In 100 Riddle
Hint:
There are total 20 nine's between 1 and 100. 9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99. you can count total 9 in these series. Did you answer this riddle correctly?
YES NO
YES NO
Chicken Egg Banana Riddle
Hint:
1 Chicken = 20 - So, 20 + 20 + 20 = 60
1 Egg Basket = 3 - So, 20 + 3 + 3 = 26
1 Bunch of Bananas = 6 - So, 3 + 6 + 6 = 15
Finally, Chicken = 20 ; Egg Basket = 3 ; Bananas = 6 - So, 20 + 3 x 5 = 35
The final answer is 35 Did you answer this riddle correctly?
YES NO
1 Egg Basket = 3 - So, 20 + 3 + 3 = 26
1 Bunch of Bananas = 6 - So, 3 + 6 + 6 = 15
Finally, Chicken = 20 ; Egg Basket = 3 ; Bananas = 6 - So, 20 + 3 x 5 = 35
The final answer is 35 Did you answer this riddle correctly?
YES NO
Witch Broom Wand Riddle
Hint:
Answer: 73 ...Broom - 3 (2nd picture compose of 2 brooms) that gives you 3+3+3+3 = 12 ...Wand - 7 (3 wands equal 21) ...Witch - 5 (15 each while carrying broom and wand giving you 45, so remove them in the last picture ...So 3 + (5x14) = 73 Did you answer this riddle correctly?
YES NO
YES NO
Shoe Guy Scarf Riddle
Hint:
43. Shoe (5) + Man, two scarves and two shoes (19) times scarf (2).
19 x 2 is 38. 38 + 5 is 43. Did you answer this riddle correctly?
YES NO
19 x 2 is 38. 38 + 5 is 43. Did you answer this riddle correctly?
YES NO
When My Father Was 31 I Was 8 Riddle
Hint:
20 Plus 20 Plus 20 Riddle
Hint:
Turn Me On My Side And I Am Everything Riddle
Hint:
The number 8. On its side, the number 8 looks like an infinity symbol. Cut in half, the number 8 becomes two zeros. Did you answer this riddle correctly?
YES NO
YES NO
12 Islanders Teeter Totter Riddle
There is an island with 12 islanders. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11.
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
Hint:
Six on one side - six on the other = one side is heavier.
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Add Your Riddle Here
Have some tricky riddles of your own? Leave them below for our users to try and solve.