Representing Letters Riddle
Hint:
The Special Numbers Riddle
Hint:
It is the numbers from 1 to 9 in alphabetical order.
Eight
Five
Four
Nine
One
Seven
Six
Three
Two Did you answer this riddle correctly?
YES NO
Eight
Five
Four
Nine
One
Seven
Six
Three
Two Did you answer this riddle correctly?
YES NO
Match The Number Of Letters
This can be a little tricky if you misread the riddle. There's a little known fact in this once you've found the answer. Also being that the answers are limited, it's recommended to challenge yourself and begin the timer to solve this in under 30 seconds.
Spell me out and I am the number of a month in which I also match the number of letters exactly of this month. What am I?
Hint: There are only 12 months
Two Relative Words Riddle
Name two different words using following words only:
1. Without me 60% of living beings can't survive.
2. Without me nothing ( living or non-living things) can survive.
3. Both have five letters each but both r anagrams of each other.
1. Without me 60% of living beings can't survive.
2. Without me nothing ( living or non-living things) can survive.
3. Both have five letters each but both r anagrams of each other.
Hint:
The Black White Orange Waddle
Hint:
Prince Age Riddle
What are their ages?
Hint:
Current Future Past
Princess x 2z (x+y)/2
Prince y x z
I then created three equations, since the difference in their age will always be the same.
d = the difference in ages
x y = d
2z x = d
x/2 + y/2 z = d
I then created a matrix and solved it using row reduction.
x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d
It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
This means that you can pick any difference you want (an even one presumably because you want integer ages).
Princess age: 4d
Prince age: 3d
Ages that work
Princess:
4
8
16
24
32
40
48
56
64
72
80
Prince:
3
6
12
18
24
30
36
42
48
54
60 Did you answer this riddle correctly?
YES NO
Princess x 2z (x+y)/2
Prince y x z
I then created three equations, since the difference in their age will always be the same.
d = the difference in ages
x y = d
2z x = d
x/2 + y/2 z = d
I then created a matrix and solved it using row reduction.
x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d
It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
This means that you can pick any difference you want (an even one presumably because you want integer ages).
Princess age: 4d
Prince age: 3d
Ages that work
Princess:
4
8
16
24
32
40
48
56
64
72
80
Prince:
3
6
12
18
24
30
36
42
48
54
60 Did you answer this riddle correctly?
YES NO
Pete And Repeat
Hint:
Repeat...Pete and repeat went fishing. Pete fell of the boat. Who was left? (keeps continuing because you are saying repeat) Did you answer this riddle correctly?
YES NO
YES NO
White Land Black Seed
Hint:
Black White With A Cherry
Hint:
Played All Around The World
Hint:
The Walls Of Jericho
When tasked with what seemed impossible
He didnt just refuse and frown
He marched the people round Jericho
And the walls came tumbling down
He is?
He didnt just refuse and frown
He marched the people round Jericho
And the walls came tumbling down
He is?
Hint:
Black, White And Laughing Riddle
Hint:
The zebra that pushed the other zebra into the swimming pool! Did you answer this riddle correctly?
YES NO
YES NO
Age Of Three Daughters Riddles
I was visiting a friend one evening and remembered that he had three daughters. I asked him how old they were. The product of their ages is 72, he answered. Quizzically, I asked, Is there anything else you can tell me? Yes, he replied, the sum of their ages is equal to the number of my house. I stepped outside to see what the house number was. Upon returning inside, I said to my host, Im sorry, but I still cant figure out their ages. He responded apologetically, Im sorry, I forgot to mention that my oldest daughter likes strawberry shortcake. With this information, I was able to determine all three of their ages. How old is each daughter?
Hint:
3, 3, and 8. The only groups of 3 factors of 72 to have non-unique sums are 2 6 6 and 3 3 8 (with a sum of 14). The rest have unique sums:
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
I Have Black And White Teeth
Hint:
Just One Word Riddle
Hint:
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