Wookiee Meat Riddle
Hint:
Wrapped Up In Cloth Strips Riddle
The next answer that
Should escape your lips
Should be the creature
Wrapped up in cloth strips
What am I?
Should escape your lips
Should be the creature
Wrapped up in cloth strips
What am I?
Hint:
The Actions Of Pericles
Pericles must answer Antiochus' riddle to win the hand of his daughter. If he fails he will face death. The riddle is:
"I am no viper, yet I feed
On mother's flesh which did me breed.
I sought a husband, in which labour
I found that kindness in a father:
He's father, son, and husband mild;
I mother, wife, and yet his child.
How they may be, and yet in two,
As you will live, resolve it you."
What does Pericles do?
"I am no viper, yet I feed
On mother's flesh which did me breed.
I sought a husband, in which labour
I found that kindness in a father:
He's father, son, and husband mild;
I mother, wife, and yet his child.
How they may be, and yet in two,
As you will live, resolve it you."
What does Pericles do?
Hint:
Understands the riddle to mean incest and hints to Antiochus his understanding.
Antiochus realises from Pericles' hints that Pericles has understood the riddle and determines to have him killed. I am not aware of any other reference to incest in Shakespeare. Incest seems to retain its rightful shock value much more in Shakespeare and the classics. Did you answer this riddle correctly?
YES NO
Antiochus realises from Pericles' hints that Pericles has understood the riddle and determines to have him killed. I am not aware of any other reference to incest in Shakespeare. Incest seems to retain its rightful shock value much more in Shakespeare and the classics. Did you answer this riddle correctly?
YES NO
Equals Eight Riddle
Hint:
Mirror one of the threes and put it and the other three together to get an eight. Did you answer this riddle correctly?
YES NO
YES NO
The Wild Wild West
In the Wild West, you challenge two cowboys - Hunter Jack and Sharp Shooter Leo into a death match. They being better shooter than you readily accept your challenge. But they don't want to waste bullets and thus lay down a certain rules that are accepted by you as well. Here are the rules:
1) Everyone shoot in a given order till only one is left.
2) Everyone shoot only once when his turn arrive.
3) If any one of you is injured, the other two will finish him off together.
4) The worst shooter gets to shoot first (which is you) and the best one shoots at the last.
Now, what tactics will you use if you know that you hit every third shot of yours, Jack hits every second shot and Leo hits every shot?
1) Everyone shoot in a given order till only one is left.
2) Everyone shoot only once when his turn arrive.
3) If any one of you is injured, the other two will finish him off together.
4) The worst shooter gets to shoot first (which is you) and the best one shoots at the last.
Now, what tactics will you use if you know that you hit every third shot of yours, Jack hits every second shot and Leo hits every shot?
Hint:
The best thing for you will be to shoot your first shot in air.
If you try to shoot at Jack and hits him by chance, Leo always hits on the target and you are dead.
If you choose to shoot at Leo and hits him by chance, then there is a fifty percent chance that Jack will hit you.
If you shoot in air, the next turn is of Jack and he knows that Leo is a better shooter which means that he will shoot at him. If he misses, he is definitely dead as Leo will shoot on him coz he shot at him. The next turn will be yours and you stand a 1/3rd chance of hitting him. Also if, he is able to hit Leo. The next chance is yours again and you can try the 1/3rd probability of hitting over Jack.
This is the best situation that you can face. At every other possible way, you will face a worse situation for sure. Did you answer this riddle correctly?
YES NO
If you try to shoot at Jack and hits him by chance, Leo always hits on the target and you are dead.
If you choose to shoot at Leo and hits him by chance, then there is a fifty percent chance that Jack will hit you.
If you shoot in air, the next turn is of Jack and he knows that Leo is a better shooter which means that he will shoot at him. If he misses, he is definitely dead as Leo will shoot on him coz he shot at him. The next turn will be yours and you stand a 1/3rd chance of hitting him. Also if, he is able to hit Leo. The next chance is yours again and you can try the 1/3rd probability of hitting over Jack.
This is the best situation that you can face. At every other possible way, you will face a worse situation for sure. Did you answer this riddle correctly?
YES NO
The Ship Thief Riddle
A Japanese ship is on route back to the shore from the Atlantic Ocean. Seeking the silent waves, the captain decides to take a shower. He keeps his Rolex and diamond studded gold bracelet on the shelf and goes for a shower. When he returns back, he finds both the watch and bracelet missing. He immediately calls the four crew members and asks them what they were doing during that duration. Following are the answers:
1. French Guy, the Cook: I was in the kitchen, making bacon sandwiches for everybody.
2. Russian Guy, the engineer: I was in the generator room, checking the generator.
3. Pakistani Guy, the housekeeper: I saw that the flag hoisted on the ship was upside down, so I went to correct it.
4. Srilankan Guy, the second housekeeper: I was tired and taking a quick nap.
The captain immediately knew who the thief was. Can you tell?
1. French Guy, the Cook: I was in the kitchen, making bacon sandwiches for everybody.
2. Russian Guy, the engineer: I was in the generator room, checking the generator.
3. Pakistani Guy, the housekeeper: I saw that the flag hoisted on the ship was upside down, so I went to correct it.
4. Srilankan Guy, the second housekeeper: I was tired and taking a quick nap.
The captain immediately knew who the thief was. Can you tell?
Hint:
The thief is the Pakistani guy. It is because the flag of Japan looks same when upside down and no one can tell if it is upside down. So, he was telling a lie. Did you answer this riddle correctly?
YES NO
YES NO
Stockings Hung Over Me
Whats the answer to this rhyme?
I am found beneath a chimney
And when it is Christmas time
I have stockings hung over me
What am I?
I am found beneath a chimney
And when it is Christmas time
I have stockings hung over me
What am I?
Hint:
Four Balls In A Bowl
This is a famous paradox probability riddle which has caused a great deal of argument and disbelief from many who cannot accept the correct answer.
Four balls are placed in a bowl. One is Green, one is Black and the other two are Yellow. The bowl is shaken and someone draws two balls from the bowl. He looks at the two balls and announces that at least one of them is Yellow. What are the chances that the other ball he has drawn out is also Yellow?
Four balls are placed in a bowl. One is Green, one is Black and the other two are Yellow. The bowl is shaken and someone draws two balls from the bowl. He looks at the two balls and announces that at least one of them is Yellow. What are the chances that the other ball he has drawn out is also Yellow?
Hint:
1/5
There are six possible pairings of the two balls withdrawn,
Yellow+Yellow
Yellow+Green
Green+Yellow
Yellow+Black
Black+Yellow
Green+Black.
We know the Green + Black combination has not been drawn.
This leaves five possible combinations remaining. Therefore the chances tbowl the Yellow + Yellow pairing has been drawn are 1 in 5.
Many people cannot accept tbowl the solution is not 1 in 3, and of course it would be, if the balls had been drawn out separately and the color of the first ball announced as Yellow before the second had been drawn out. However, as both balls had been drawn together, and then the color of one of the balls announced, then the above solution, 1 in 5, must be the correct one. Did you answer this riddle correctly?
YES NO
There are six possible pairings of the two balls withdrawn,
Yellow+Yellow
Yellow+Green
Green+Yellow
Yellow+Black
Black+Yellow
Green+Black.
We know the Green + Black combination has not been drawn.
This leaves five possible combinations remaining. Therefore the chances tbowl the Yellow + Yellow pairing has been drawn are 1 in 5.
Many people cannot accept tbowl the solution is not 1 in 3, and of course it would be, if the balls had been drawn out separately and the color of the first ball announced as Yellow before the second had been drawn out. However, as both balls had been drawn together, and then the color of one of the balls announced, then the above solution, 1 in 5, must be the correct one. Did you answer this riddle correctly?
YES NO
Knights Of The Round Table Riddle
King Arthur, Merlin, Sir Lancelot, Sir Gawain, and Guinevere decide to go to their favorite restaurant to share some mead and grilled meats. They sit down at a round table for five, and as soon as they do, Lancelot notes, "We sat down around the table in age order! What are the odds of that?"
Merlin smiles broadly. "This is easily solved without any magic." He then shared the answer. What did he say the odds were?
Merlin smiles broadly. "This is easily solved without any magic." He then shared the answer. What did he say the odds were?
Hint: Does it matter if they are sitting clockwise or counterclockwise? Or where the oldest sits?
The odds are 11:1. (The probability is 1/12.)
Imagine they sat down in age order, with each person randomly picking a seat. The first person is guaranteed to pick a seat that "works". The second oldest can sit to his right or left, since these five can sit either clockwise or counterclockwise. The probability of picking a seat that works is thus 2/4, or 1/2. The third oldest now has three chairs to choose from, one of which continues the progression in the order determined by the second person, for a probability of 1/3. This leaves two seats for the fourth oldest, or a 1/2 chance. The youngest would thus be guaranteed to sit in the right seat, since there is only one seat left. This gives 1 * 1/2 * 1/3 * 1/2 * 1 = 1/12, or 11:1 odds against. Did you answer this riddle correctly?
YES NO
Imagine they sat down in age order, with each person randomly picking a seat. The first person is guaranteed to pick a seat that "works". The second oldest can sit to his right or left, since these five can sit either clockwise or counterclockwise. The probability of picking a seat that works is thus 2/4, or 1/2. The third oldest now has three chairs to choose from, one of which continues the progression in the order determined by the second person, for a probability of 1/3. This leaves two seats for the fourth oldest, or a 1/2 chance. The youngest would thus be guaranteed to sit in the right seat, since there is only one seat left. This gives 1 * 1/2 * 1/3 * 1/2 * 1 = 1/12, or 11:1 odds against. Did you answer this riddle correctly?
YES NO
Little Billy's Calculator
Little Billy has a calculator with 15 buttons. He has 10 keys for 0-9, a key for addition, multiplication, division, and subtraction. Finally, he has an = sign. However, Mark the Meanie messed up the programming on Billy's calculator. Now, whenever Billy presses any of the number keys, it comes up with a random single-digit number. The same goes for the four operations keys (+,-,x, /). So whenever Billy tries to press the + button, the calculator chooses randomly between addition, multiplication, subtraction, and division. The only key left untouched was the = sign.
Now, if Billy were to press one number key, one operation key, then another number key, then the = button, what are the chances the answer comes out to 6?
Now, if Billy were to press one number key, one operation key, then another number key, then the = button, what are the chances the answer comes out to 6?
Hint: Think about how many ways he could possibly get 6.
There is a 4% chance.
There are 16 possible ways to get 6.
0+6
1+5
2+4
3+3
6+0
5+1
4+2
9-3
8-2
7-1
6-0
1x6
2x3
6x1
3x2
6/1
There are 400 possible button combinations.
When Billy presses any number key, there are 10 possibilities; when he presses any operation key, there are 4 possibilities.
10(1st#)x4(Operation)x10(2nd#)=400
16 working combinations/400 possible combinations= .04 or 4% Did you answer this riddle correctly?
YES NO
There are 16 possible ways to get 6.
0+6
1+5
2+4
3+3
6+0
5+1
4+2
9-3
8-2
7-1
6-0
1x6
2x3
6x1
3x2
6/1
There are 400 possible button combinations.
When Billy presses any number key, there are 10 possibilities; when he presses any operation key, there are 4 possibilities.
10(1st#)x4(Operation)x10(2nd#)=400
16 working combinations/400 possible combinations= .04 or 4% Did you answer this riddle correctly?
YES NO
Crossing Safety Riddle
Two boys and a man need to cross a river. They can only use the canoe. It will hold only the man OR the two boys' weight. How can they all get across safely?
Answer:
Answer:
Hint:
The two boys go across. One of them get out. The other one goes back. He gets out and the man gets in. He goes across. Then the man gets out and the other boy gets in and goes across. Then the boy that was left gets in and now they both go across together. Did you answer this riddle correctly?
YES NO
YES NO
An Island That Has 3 Gods
There is an Island that has 3 gods. One god always tells a lie, and the other always tells the truth. The third god has a random behavior. To top it off, these three gods, being jerks, answer in their own languages such that you are unable to tell which word, between "ja" or "da", means "no" or "yes". You have 3 questions to work out the True god, the false god, and the Random god.
Hint:
Question 1: (To any of the three gods) If I were to ask you "Is that the random god," would your answer be "ja?" (This questions, no matter the answer, will enable you to tell which god is not random i.e. the god who is either False or True)
Question 2: (To either the True or False god) If I asked you "are you false," would your answer be "ja?"
Question 3: (To the same god you asked the second question) If I asked you "whether the first god I spoke to is random," would your answer be "ja?" Did you answer this riddle correctly?
YES NO
Question 2: (To either the True or False god) If I asked you "are you false," would your answer be "ja?"
Question 3: (To the same god you asked the second question) If I asked you "whether the first god I spoke to is random," would your answer be "ja?" Did you answer this riddle correctly?
YES NO
Unwilling To Kiss
First think of the person who lives in disguise,
Who deals in secrets and tells naught but lies.
Next, tell me whats always the last thing to mend,
The middle of middle and end of the end?
And finally give me the sound often heard
During the search for a hard-to-find word.
Now string them together, and answer me this,
Which creature would you be unwilling to kiss?
Who deals in secrets and tells naught but lies.
Next, tell me whats always the last thing to mend,
The middle of middle and end of the end?
And finally give me the sound often heard
During the search for a hard-to-find word.
Now string them together, and answer me this,
Which creature would you be unwilling to kiss?
Hint:
Never Asks Questions Riddle
Hint:
Age Of Three Daughters Riddles
I was visiting a friend one evening and remembered that he had three daughters. I asked him how old they were. The product of their ages is 72, he answered. Quizzically, I asked, Is there anything else you can tell me? Yes, he replied, the sum of their ages is equal to the number of my house. I stepped outside to see what the house number was. Upon returning inside, I said to my host, Im sorry, but I still cant figure out their ages. He responded apologetically, Im sorry, I forgot to mention that my oldest daughter likes strawberry shortcake. With this information, I was able to determine all three of their ages. How old is each daughter?
Hint:
3, 3, and 8. The only groups of 3 factors of 72 to have non-unique sums are 2 6 6 and 3 3 8 (with a sum of 14). The rest have unique sums:
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
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