THERE A FIVE PEOPLE IN A ROOM I ARRIVE AND KILL O RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Riddles and Answers © 2024

Great As Chips And Fries

Hint:
Potatoes
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Something Very Shiny

Hint:
Gold
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A Yellow Precious Metal

Hint:
Gold
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I Exist Where There Is Light Riddle

Hint:
A shadow
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Cities But No Houses Riddle

Hint:
A map
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How Many Triangles Are There?

Hint: Don't forget to count the outside :)
13
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Evacuating From A Hurricane Riddle

Hint:
You give the car to your best friend. He takes the lady to the hospital in your car. You wait with the woman of your dreams until your friend comes back in his van which can carry 5 people. Then you leave before the hurricane comes.
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Age Of Three Daughters Riddles

Hint:
3, 3, and 8. The only groups of 3 factors of 72 to have non-unique sums are 2 6 6 and 3 3 8 (with a sum of 14). The rest have unique sums:

2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13

The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer.
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Visit This Very Large Country

Hint:
Australia
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I Never Was But Always Will Be Riddle

Hint:
Tomorrow
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Difficult Pianos

Hint:
Because the keys are inside!
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My First Half Means Container

Hint:
Binary
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One Light And Three Switches

This riddle is a favorite among many. No diversions into logical theory or mathematics, just a fun puzzle with a satisfying answer.
Hint:
Flip switch number 1 and wait a few minutes. Flip switch number 1 back to its original position, and then immediately flip switch number 2.

Open the door. If the light is on, then switch number 2 controls it. If the light is off, then go and feel the bulb with your hand. If the bulb is hot, the switch number 1 controls it, and if the bulb is cold, then switch number 3, the one you did not touch, controls it.
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Banana Clock Riddle

Hint: 1. Look closely at the clock. 2. Number of Bananas. 3. Some thing regarding the sides of the Shapes figure.
38

Logic :
From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38.
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Three Gods Riddle

Hint:
A possible solution is:

Q1: Ask god B, "If I asked you 'Is A Random?', would you say ja?". If B answers ja, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is indeed Random. Either way, C is not Random. If B answers da, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is not Random. Either way, you know the identity of a god who is not Random.

Q2: Go to the god who was identified as not being Random by the previous question (either A or C), and ask him: "If I asked you 'Are you False?', would you say ja?". Since he is not Random, an answer of da indicates that he is True and an answer of ja indicates that he is False.

Q3: Ask the same god the question: "If I asked you 'Is B Random?', would you say ja?". If the answer is ja, B is Random; if the answer is da, the god you have not yet spoken to is Random. The remaining god can be identified by elimination.
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