Wanted In December Riddle
Hint: Top forward incisors
My Life Can Last Some Hours Riddle
My life can last some hours. The thing I produce consumes me. I am immune to grey light - the only thing that can kill me. Who am I?
Hint:
Facebook Llama Riddle Challenge
Its 3am, the doorbell rings and you wake up. Unexpected visitors!!
Its your parents and they are here for breakfast.
You have strawberry jam, honey, wine, bread and cheese.
What is the first thing you open?
Its your parents and they are here for breakfast.
You have strawberry jam, honey, wine, bread and cheese.
What is the first thing you open?
Hint:
You will Open your Eyes first, then you will Open the door. Did you answer this riddle correctly?
YES NO
YES NO
Sleeping In Your Bedroom Riddle
You stay alone and you are sleeping in your bedroom. Your parents ring your doorbell as they have come to have breakfast with you. You have milk, bread, honey, jam and cornflakes in your house. What is the first thing you will open?
Hint:
You will open your eyes first, then you will open the door! Did you answer this riddle correctly?
YES NO
YES NO
12 Islanders Teeter Totter Riddle
There is an island with 12 islanders. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11.
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
Hint:
Six on one side - six on the other = one side is heavier.
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Flat As A Leaf Riddle
Hint:
You Come To A Fork In The Road Riddle
You stand at a fork in the road. Next to each of the two forks, there stands a guard. You know the following things: First that one path leads to paradise, the other leads to Death. You cannot distinguish between the two paths. You also know that one of the two guards always tells the truth and the other always lies. You have permission to ask one guard one question to discover which path leads to paradise. What one question would you ask to guarantee you take the path to paradise?
Hint:
Ask one of the gaurds 'Which door would the other guard say leads to paradise?' If you ask the truthful one he will say the lying guard would say the wrong door. If you ask the lying guard he would say the truthful gaurd would pick the wrong door as well (since he is lying). So no matter what you could choose the door opposite of what they say and end up in paradise. Did you answer this riddle correctly?
YES NO
YES NO
12 Pills Riddle
You have 12 pills and they all got the same weight, except for one, which hasn't got the same weight. You don't know if it is heavier or easier. You have one scale to weight the pills. You now have to find out, which pill is the right one (the one with a different weight), but you can use the scale only three times. How do you know, which one is the right one?You have 12 pills and they all got the same weight, except for one, which hasn't got the same weight. You don't know if it is heavier or easier. You have one scale to weight the pills. You now have to find out, which pill is the right one (the one with a different weight), but you can use the scale only three times. How do you know, which one is the right one?
Hint:
E = easier in "1", H = heavier in "1". 1: Weight 4:4. If they balance go to "2", if they don't balance, go to "3". 2: Balance 1:1 of the pills you didn't weight yet. Then weight one you didn't weight and one you did weight. If they balanced in the first weighing, and balanced in the second weighing, the last pill is the right one. If they balanced in the first weighing and didn't balance in the second, the one you didn't use before is the right pill. If they didn't balance at all, it's the pill you weighed twice. If they didn't balance in the first weighing, but balanced in the second, it is the first pill. 3: Weight EHH : EHH. If they balance, weight one you already weighed, with an unweighed and go to "4". If they don't balance go to "5". 4: If they balance, the one you didn't weight at all is the right pill. If they don't balance, the one you only weighed once is the right one. 5: Give away every pill that was once easier AND once heavier. You should only have EHH left. Weight H:H. If they balance, E is the right one. If the don't balance, the one which was only heavier the whole time, is the right pill. Did you answer this riddle correctly?
YES NO
YES NO
Eight Pills Riddle
There are 8 pills. They are all the same size and color. One pill weighs slightly more and is poisonous. You have a balanced scale and you can only use it twice. How can you find the poisonous Pill?
Hint:
Take any six pills and divide them into two groups of three each. Weigh putting the 3 pills on each side. If one side weigh's heavier than another, the heavier side consists of the poisonous pill. From the three pill in heavier side, weigh two pills. If one pill is heavier than another, the heavy one is poisonous pill. If both pill weigh same, the remaining third pill is poisonous. If all the 6 pill weigh the same, weigh the remaining two pill and heavy one is poisonous. Did you answer this riddle correctly?
YES NO
YES NO
With Eyes That See I Cant Be Found Riddle
With eyes that see I can't be found, But rest assured I'm all around. The thing you need is just my name. Discover that and beat this game?
Hint:
Her Pretty Wings As Still As Stone Riddle
Her pretty wings, as still as stone, as she waits on the wall, Once bright with vibrant summer hues, are now brown as fall. The word you seek, the former tint of her and her sisters' wings, On Orchid Island can be found, at the beginning of all things.
What is it?
What is it?
Hint:
Prisoner Hat Riddle
Four inmates are cleaning up a littered beach as part of a prisoner work program. The warden, who happens to be overseeing the work, decides to play a little game with the prisoners. He tells them that if they win the game he will let them go free! He then proceeds to bury each prisoner up to his neck in sand as shown.
There is a wall between prisoners C and D (which cannot be seen through or around). Prisoner A can see prisoners B and C (by moving his head to the side). Prisoner B can see prisoner C. Prisoners C and D see only the wall.
The prisoners are immobilized in the ground and can't twist their body to see the person behind them. The warden shows them two black hats and two white hats and then puts the hats in a bag to conceal them. He then stands behind each prisoner, chooses a hat from the bag, and puts it on their head. The color of each prisoner's hat is shown in the image above.
The rules are simple. If any prisoner can figure out the color of the hat on his head, all four prisoners will be set free. But they must be sure, if one of them simply guesses and is wrong, they will all be shot dead! The prisoners are not allowed to talk to each other and they have 10 seconds.
The warden counts down "ten, nine, eight, seven". All four prisoners are silent. The warden smiles, knowing that he put the hats on in such a way that no prisoner could possibly know the color of the hat they had on. He continues "six, five, four, thr.."
"I know the color of my hat!" one of the prisoners finally blurts out.
Which prisoner called out and why is he 100% certain of the color of his hat?
There is a wall between prisoners C and D (which cannot be seen through or around). Prisoner A can see prisoners B and C (by moving his head to the side). Prisoner B can see prisoner C. Prisoners C and D see only the wall.
The prisoners are immobilized in the ground and can't twist their body to see the person behind them. The warden shows them two black hats and two white hats and then puts the hats in a bag to conceal them. He then stands behind each prisoner, chooses a hat from the bag, and puts it on their head. The color of each prisoner's hat is shown in the image above.
The rules are simple. If any prisoner can figure out the color of the hat on his head, all four prisoners will be set free. But they must be sure, if one of them simply guesses and is wrong, they will all be shot dead! The prisoners are not allowed to talk to each other and they have 10 seconds.
The warden counts down "ten, nine, eight, seven". All four prisoners are silent. The warden smiles, knowing that he put the hats on in such a way that no prisoner could possibly know the color of the hat they had on. He continues "six, five, four, thr.."
"I know the color of my hat!" one of the prisoners finally blurts out.
Which prisoner called out and why is he 100% certain of the color of his hat?
Hint:
Prisoner B.
If prisoners B and C had the same color hat on, prisoner A would have know immediately that his hat was the other color (there are only two hats of each color). Since prisoner A was silent, prisoners B and C must have different colored hats. Prisoner B realized this and knew that his hat was not the same color as prisoner C, therefore his hat must be black! Did you answer this riddle correctly?
YES NO
If prisoners B and C had the same color hat on, prisoner A would have know immediately that his hat was the other color (there are only two hats of each color). Since prisoner A was silent, prisoners B and C must have different colored hats. Prisoner B realized this and knew that his hat was not the same color as prisoner C, therefore his hat must be black! Did you answer this riddle correctly?
YES NO
You Are In A Cement Room Riddle
You're in a cement room with no windows or doors. The only thing you have is a mirror and a piece of wood. How do you get out?
Hint:
In the mirror, you will notice the dark patch and using the table wood, you can break the wall and escape.
A cement wall doesn't mean that the wall is wet or dry. You happen to notice the dark patch on the wall where the cement was wet, and thus if you push the wall using the table wood, it would break easily. Thus you can escape easily from the room. Did you answer this riddle correctly?
YES NO
A cement wall doesn't mean that the wall is wet or dry. You happen to notice the dark patch on the wall where the cement was wet, and thus if you push the wall using the table wood, it would break easily. Thus you can escape easily from the room. Did you answer this riddle correctly?
YES NO
Two Ships Riddle
Two ships leave the port of San Diego, both sailing for the distant shores of Japan. Each ship plans to travel the same route, spending a two-week stopover in Tokyo before returning to California. The first ship churns through the sea at 35 miles per hour throughout the entire journey. The second ship moves slower, at just 30 mph. After two weeks in Tokyo, the captain of the second ship decides to run at a faster pace, moving at 40 mph for the entire return trip. Which ship arrives in San Diego first?
Hint:
The first ship!
First ship = d/35 + d/35 = 2d/35 = 0.0571d
Second ship = d/30 = d/40 = 70d/1200 = 0.058 Did you answer this riddle correctly?
YES NO
First ship = d/35 + d/35 = 2d/35 = 0.0571d
Second ship = d/30 = d/40 = 70d/1200 = 0.058 Did you answer this riddle correctly?
YES NO
Two Ships Riddle
Two ships leave the port of San Diego, both sailing for the distant shores of Japan. Each ship plans to travel the same route, spending a two-week stopover in Tokyo before returning to California. The first ship churns through the sea at 35 miles per hour throughout the entire journey. The second ship moves slower, at just 30 mph. After two weeks in Tokyo, the captain of the second ship decides to run at a faster pace, moving at 40 mph for the entire return trip. Which ship arrives in San Diego first?
Hint:
The first ship!
First ship = d/35 + d/35 = 2d/35 = 0.0571d
Second ship = d/30 = d/40 = 70d/1200 = 0.058 Did you answer this riddle correctly?
YES NO
First ship = d/35 + d/35 = 2d/35 = 0.0571d
Second ship = d/30 = d/40 = 70d/1200 = 0.058 Did you answer this riddle correctly?
YES NO
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