WHAT DID THE VAMPIRE DO WHEN HE FAILED HIS MATH TEST RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

To stop his coffin. Did you answer this riddle correctly?
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At the casketeria. Did you answer this riddle correctly?
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On Lake Eerie. Did you answer this riddle correctly?
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A candlelight dinner. Did you answer this riddle correctly?
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An engagement proposal. Did you answer this riddle correctly?
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Because Jesus was a car-painter (carpenter)! Did you answer this riddle correctly?
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He worked it out with a pencil Did you answer this riddle correctly?
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In a cone Did you answer this riddle correctly?
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Grave-y. Did you answer this riddle correctly?
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Blood Did you answer this riddle correctly?
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Its love at first bite Did you answer this riddle correctly?
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Time Did you answer this riddle correctly?
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Dead ends Did you answer this riddle correctly?
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The answers for 'eye test how many 3s' puzzle ranges from 15 to 21. At first glance, most people only notice 15 threes in the image. First, you might notice that there are two threes on the number pad, as the number eight has also been replaced by a three. Then there are eight threes in the phone number. Many also notice that the battery charge is at 33% and the time is 3:33 PM.

However, if one looks closer at the name underneath the phone number, they will find three more 3s. This gives a total of 18 3s in the image. But there is one more hidden three that even observant people fail to notice. Underneath the number four on the keypad, the letter 'I' has been replaced with three as well. So, the total number of 3s in the image is 19.

However, depending on your interpretation of the puzzle, the number of 3s can also rise to 21. At the top left of the image, the bar signal and wifi signal also have three bars. Some people also consider the two signals to be a part of the riddle and raise the number of 3s to 21. So, the correct answer can be 19 or 21, depending on your interpretation of the question. Did you answer this riddle correctly?
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7. If you break the batteries into 3 groups: Two groups of 3 and one group of 2. By doing this you guarantee that one of the groups has 2 working batteries. Both of the groups of 3 have 3 possible combinations of 2 batteries and the group of 2 only has 1 combination. So, 3 + 3 + 1 = 7 tries at most to find two working batteries. Did you answer this riddle correctly?
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