The Blood Symbol
Hint:
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
Yahtzee Riddle
The game of Yahtzee is played with five dice. On the first turn, a player rolls all five dice, and then may decide to keep any, all, or none of the dice aside before rolling again. Each player has a maximum of three rolls to try to get a favorable combination of dice "kept" on the side.
If a player rolls two 2s and two 4s on his/her first roll, and keeps all four of these dice aside, what is the probability of getting a full house (three of one value and two of another) in one of his/her next two rolls? (ie what is the probability of getting either a 2 or a 4 in one of the next two rolls?)
If a player rolls two 2s and two 4s on his/her first roll, and keeps all four of these dice aside, what is the probability of getting a full house (three of one value and two of another) in one of his/her next two rolls? (ie what is the probability of getting either a 2 or a 4 in one of the next two rolls?)
Hint: Think of the probability of NOT getting a full house.
5/9
The answer is NOT 2/3 because you cannot add probabilities. On each roll, the probability of getting a 2 or a 4 is 1/3, so therefore, the probability of not getting a 2 or a 4 is 2/3. Since the die is being rolled twice, square 2/3 to get a 4/9 probability of NOT getting a full house in two rolls. The probability of getting a full house is therefore 1 - 4/9, or 5/9. Did you answer this riddle correctly?
YES NO
The answer is NOT 2/3 because you cannot add probabilities. On each roll, the probability of getting a 2 or a 4 is 1/3, so therefore, the probability of not getting a 2 or a 4 is 2/3. Since the die is being rolled twice, square 2/3 to get a 4/9 probability of NOT getting a full house in two rolls. The probability of getting a full house is therefore 1 - 4/9, or 5/9. Did you answer this riddle correctly?
YES NO
A Town With No Houses
Hint:
The Safest Room
Hint:
They'd both be safe because the lions that havent eaten in 3 months would be dead. Did you answer this riddle correctly?
YES NO
YES NO
A 10 Foot Rope Ladder
A 10 foot rope ladder hangs over the side of a boat with the bottom rung on the surface of the water. The rungs are one foot apart, and the tide goes up at the rate of 6 inches per hour. How long will it be until three rungs are covered?
Hint:
Two Brothers Riddle
Two brothers we are, great burdens we bear,
All day we are bitterly pressed;
Yet this we will say, we are full all the day
And empty when we go to rest.
What are we?
All day we are bitterly pressed;
Yet this we will say, we are full all the day
And empty when we go to rest.
What are we?
Hint: Your burdens are also our burdens, but greater by the measure of you.
A 7 Foot Clown Riddle
A 7 foot clown stood up and held a water glass over his head. He accidentally dropped the glass, but nothing spilled. How is this possible?
Hint:
Cities But No Houses Riddle
It has cities but no houses, it has oceans but no water, it has forests but no trees, it has deserts but no sand. What is it?
Hint:
A Ship Drops This To Stay Still
A ship drops this to stay still
Even if the waters calm
It is also a tattoo
You can see on Popeyes arm
It has to be a?
Even if the waters calm
It is also a tattoo
You can see on Popeyes arm
It has to be a?
Hint:
Strive With Wind And Wave Riddle
Off I must strive with wind and wave, battle them both
when under the sea.
I feel out the bottom, a foreign land. In lying still, I am
Strong in the strife;
If I fail in that, they are stronger than I, and
Wrenching me loose, soon put me to rout.
They wish to capture what I must keep. I can master
Them both if my grip holds out,
If the rocks bring succor and lend support, strength
In the struggle. Ask my name
when under the sea.
I feel out the bottom, a foreign land. In lying still, I am
Strong in the strife;
If I fail in that, they are stronger than I, and
Wrenching me loose, soon put me to rout.
They wish to capture what I must keep. I can master
Them both if my grip holds out,
If the rocks bring succor and lend support, strength
In the struggle. Ask my name
Hint:
I'm A Country But Im Not Russia Riddle
Im a country but Im not Russia
Im in the southern hemisphere but Im not Argentina
Im popular with surfers but Im not South Africa
Im surrounded by water but Im not Madagascar
Im sometimes called Oz but I dont have anything to do with wizards
What am I?
Im in the southern hemisphere but Im not Argentina
Im popular with surfers but Im not South Africa
Im surrounded by water but Im not Madagascar
Im sometimes called Oz but I dont have anything to do with wizards
What am I?
Hint:
7 Ice Cubes Riddle
Hint:
The Biggest Alphabet Riddle
Hint:
1 Rabbit Saw 6 Elephants Riddle
Every elephant saw 2 monkeys going towards the river.
Every monkey holds 1 parrot in their hands.
How many Animals are going towards the river?
Hint:
5 Animals.
Lets go through the question again.
1 rabbit saw 6 elephants while going to the river. Hence, 1 animal (rabbit) is going towards the river.
Every elephant saw 2 monkeys going towards the river. This is the tricky part, from the sentence it seems to imply each of the 6 elephants saw 2 monkeys going towards the river, hence logically will be 6 x 2 = 12 animals (monkeys) going towards the river.
However, the statement does not explicitly mention that Every elephant saw 2 DIFFERENT monkeys, hence implicit rules apply and infer that the 2 monkeys are the same.
Hence, correct answer is that every elephant saw 2 monkeys, and by inference, the 2 monkeys are the same, hence there exists only 2 monkeys which are going towards the river !!
Finally, every monkey holds 1 parrot in their hands. Hence, 2 parrots are going towards the river.
So in total, 1 rabbit, 2 monkeys and 2 parrots (5 animals) are going towards the river. Did you answer this riddle correctly?
YES NO
Lets go through the question again.
1 rabbit saw 6 elephants while going to the river. Hence, 1 animal (rabbit) is going towards the river.
Every elephant saw 2 monkeys going towards the river. This is the tricky part, from the sentence it seems to imply each of the 6 elephants saw 2 monkeys going towards the river, hence logically will be 6 x 2 = 12 animals (monkeys) going towards the river.
However, the statement does not explicitly mention that Every elephant saw 2 DIFFERENT monkeys, hence implicit rules apply and infer that the 2 monkeys are the same.
Hence, correct answer is that every elephant saw 2 monkeys, and by inference, the 2 monkeys are the same, hence there exists only 2 monkeys which are going towards the river !!
Finally, every monkey holds 1 parrot in their hands. Hence, 2 parrots are going towards the river.
So in total, 1 rabbit, 2 monkeys and 2 parrots (5 animals) are going towards the river. Did you answer this riddle correctly?
YES NO
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