WHY IS SANTA SO GOOD A R RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Saying Hello Riddle

You can use me to say hello,

And to say goodbye.

I'm no good when I'm too dry,

I can be quick or I can be slow.

What am I?

Hint:

A kiss

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Good Riddles Riddles For Teens

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I Can Fly Riddle

Im colorful but Im not a rainbow
Im sometimes found on a shoulder but Im not a bag strap
I have two legs but Im not an ostrich
I can talk but Im not a person
I can fly but Im not an airplane

I'm a...

Hint:

Parrot!

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Good Riddles Top 100 Riddles

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Rising Above The Din

My voice rises above the din, sometimes catching all unaware. I never ask questions, yet get many answers.

What am I?

Hint:

A bell

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List Of Riddles And Answers Good Riddles

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Knights Of The Round Table Riddle

King Arthur, Merlin, Sir Lancelot, Sir Gawain, and Guinevere decide to go to their favorite restaurant to share some mead and grilled meats. They sit down at a round table for five, and as soon as they do, Lancelot notes, "We sat down around the table in age order! What are the odds of that?"

Merlin smiles broadly. "This is easily solved without any magic." He then shared the answer. What did he say the odds were?

Hint: Does it matter if they are sitting clockwise or counterclockwise? Or where the oldest sits?

The odds are 11:1. (The probability is 1/12.)

Imagine they sat down in age order, with each person randomly picking a seat. The first person is guaranteed to pick a seat that "works". The second oldest can sit to his right or left, since these five can sit either clockwise or counterclockwise. The probability of picking a seat that works is thus 2/4, or 1/2. The third oldest now has three chairs to choose from, one of which continues the progression in the order determined by the second person, for a probability of 1/3. This leaves two seats for the fourth oldest, or a 1/2 chance. The youngest would thus be guaranteed to sit in the right seat, since there is only one seat left. This gives 1 * 1/2 * 1/3 * 1/2 * 1 = 1/12, or 11:1 odds against.

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Yahtzee Riddle

The game of Yahtzee is played with five dice. On the first turn, a player rolls all five dice, and then may decide to keep any, all, or none of the dice aside before rolling again. Each player has a maximum of three rolls to try to get a favorable combination of dice "kept" on the side.

If a player rolls two 2s and two 4s on his/her first roll, and keeps all four of these dice aside, what is the probability of getting a full house (three of one value and two of another) in one of his/her next two rolls? (ie what is the probability of getting either a 2 or a 4 in one of the next two rolls?)

Hint: Think of the probability of NOT getting a full house.

5/9

The answer is NOT 2/3 because you cannot add probabilities. On each roll, the probability of getting a 2 or a 4 is 1/3, so therefore, the probability of not getting a 2 or a 4 is 2/3. Since the die is being rolled twice, square 2/3 to get a 4/9 probability of NOT getting a full house in two rolls. The probability of getting a full house is therefore 1 - 4/9, or 5/9.

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