# A MAN WEIGHING 14 STONE AND HIS TWO SONS WEIGHING 7 STONE EACH WERE STRANDED ON AN ISLAND ALL THEY HAD RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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## Solving A Man Weighing 14 Stone And His Two Sons Weighing 7 Stone Each Were Stranded On An Island All They Had Riddles

Here we've provide a compiled a list of the best a man weighing 14 stone and his two sons weighing 7 stone each were stranded on an island all they had puzzles and riddles to solve we could find.

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## Fake Ireland Stones Riddle

Hint:
A sham-rock!
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Solved: 56%

## Farmer Stones Riddle

Hint:
The stones weight 1 pound, 3 pounds, 9 pounds and 27 pounds. These can be used in combination with each other on both sides of the scale to come up with any counterweight from 1 to 40 pounds.
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Solved: 50%

## Stones In The Sea Riddle

Hint:
Dry stones
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Solved: 40%

## Rolling Stones And Borimir Riddle

Hint:
Have you not heard? One does not simply rock into Mordor!
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## As Hard As Stone Riddle

Hint:
Ice
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Solved: 80%

## Two Tablets Of Stone

Hint:
Moses
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Solved: 88%

## Red Stone In The Sea

Hint:
It will become Wet.
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Solved: 67%

## As A Stone Inside A Tree Riddle

Hint:
A pencil
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Solved: 60%

## Having More But Weighing Less

Hint:
Cheese with holes.
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Solved: 50%

## 12 Islanders Teeter Totter Riddle

Hint:
Six on one side - six on the other = one side is heavier.

Take the heavier six men, divide them into three and three (random).

Three on one side - three on the other = one side will one heavier.

Divide that three men from the heavier side side, have one on one side - one on the other.

Two results can determine which of the last three men weight is a different weight than each other.

With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.

Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.

You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."

Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less.
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Solved: 53%