13 Letter Words
I'm a thing
The fishermen love me
The doctors hate me
Kids want to eat me
I'm a 13 letter word
What am I?
The fishermen love me
The doctors hate me
Kids want to eat me
I'm a 13 letter word
What am I?
Hint: _H_T_ _ _I_ _ME_
Cruise Ship Riddle
One night, the king and queen go on a cruise ship. The next day, 3 people get off the ship. Who's the 3rd person?
Hint:
Walking In The Rain
Samuel was out for a walk when it started to rain. He did not have an umbrella and he wasn't wearing a hat. His clothes were soaked, yet not a single hair on his head got wet. How could this happen?
Hint:
The Spit Jam Mystery
There was once a rich man who lived in a large circle house, one day he woke up and found that someone had spit jam all over his new shirt. When he asked who did it, the 1st servant said "it wasn't me I was cooking." The 2nd servant said " It wasn't me I was tiding up the books" the 3rd servant said "It wasn't me I was dusting the corners of the house" Who did it?
Hint:
The third servant because they said they were dusting the corners of the house, but the house has no corners since it's a circle! Did you answer this riddle correctly?
YES NO
YES NO
Running Bases Riddle
Hint:
Abhorred By All
I dont exist unless you cut me, but if you stab me I wont bleed. I hate no one yet am abhorred by all. What am I?
Hint:
Five Prom Couples Riddle
Five couples went to the prom as a group. The boys' names were Mark, Quintin, Jim, Bob, and James. The girls' names were Amanda, Betty, Susan, Jessica, and Jasmin. Each couple wore matching colors of either blue, yellow, red, green, or pink. Match the dates and the color they are wearing.
1) Two couples have the same first letter in their name. One of those letters is "B".
2) Susan wore red and Jessica wore blue.
3) Susan has more letters in her name than her date does.
4) Neither Mark nor Quintin went with Jasmin, who was wearing yellow.
5) Amanda went with Jim and they did not wear green.
1) Two couples have the same first letter in their name. One of those letters is "B".
2) Susan wore red and Jessica wore blue.
3) Susan has more letters in her name than her date does.
4) Neither Mark nor Quintin went with Jasmin, who was wearing yellow.
5) Amanda went with Jim and they did not wear green.
Hint:
Mark and Susan wore red.
Quintin and Jessica wore blue.
Jim and Amanda wore pink.
Bob and Betty wore green.
James and Jasmin wore yellow. Did you answer this riddle correctly?
YES NO
Quintin and Jessica wore blue.
Jim and Amanda wore pink.
Bob and Betty wore green.
James and Jasmin wore yellow. Did you answer this riddle correctly?
YES NO
The Tenth Floor Elevator Riddle
A man lives on the tenth floor of a building. Every day he takes the elevator to go down to the ground floor to go to work. When he returns he takes the same elevator to the seventh floor and walks up the stairs to reach his apartment on the tenth floor. He hates walking so why does he do it?
Note that there is nothing wrong with the elevator or the design of the building. It's a perfectly normal elevator in a perfectly normal building.
Note that there is nothing wrong with the elevator or the design of the building. It's a perfectly normal elevator in a perfectly normal building.
Hint: The elevator is perfectly normal and the design of the building is perfectly normal, but there is something different about the man.
The man is very short (i.e. a little person).
Because of his short stature, the man is unable to reach any higher than the button for the 7th floor (elevator floor number buttons are laid out in descending floor order from top to bottom). Did you answer this riddle correctly?
YES NO
Because of his short stature, the man is unable to reach any higher than the button for the 7th floor (elevator floor number buttons are laid out in descending floor order from top to bottom). Did you answer this riddle correctly?
YES NO
The Loaded Revolver Riddle
Henry has been caught stealing cattle, and is brought into town for justice. The judge is his ex-wife Gretchen, who wants to show him some sympathy, but the law clearly calls for two shots to be taken at Henry from close range. To make things a little better for Henry, Gretchen tells him she will place two bullets into a six-chambered revolver in successive order. She will spin the chamber, close it, and take one shot. If Henry is still alive, she will then either take another shot, or spin the chamber again before shooting.
Henry is a bit incredulous that his own ex-wife would carry out the punishment, and a bit sad that she was always such a rule follower. He steels himself as Gretchen loads the chambers, spins the revolver, and pulls the trigger. Whew! It was blank. Then Gretchen asks, "Do you want me to pull the trigger again, or should I spin the chamber a second time before pulling the trigger?"
What should Henry choose?
Henry is a bit incredulous that his own ex-wife would carry out the punishment, and a bit sad that she was always such a rule follower. He steels himself as Gretchen loads the chambers, spins the revolver, and pulls the trigger. Whew! It was blank. Then Gretchen asks, "Do you want me to pull the trigger again, or should I spin the chamber a second time before pulling the trigger?"
What should Henry choose?
Hint:
Henry should have Gretchen pull the trigger again without spinning.
We know that the first chamber Gretchen fired was one of the four empty chambers. Since the bullets were placed in consecutive order, one of the empty chambers is followed by a bullet, and the other three empty chambers are followed by another empty chamber. So if Henry has Gretchen pull the trigger again, the probability that a bullet will be fired is 1/4.
If Gretchen spins the chamber again, the probability that she shoots Henry would be 2/6, or 1/3, since there are two possible bullets that would be in firing position out of the six possible chambers that would be in position. Did you answer this riddle correctly?
YES NO
We know that the first chamber Gretchen fired was one of the four empty chambers. Since the bullets were placed in consecutive order, one of the empty chambers is followed by a bullet, and the other three empty chambers are followed by another empty chamber. So if Henry has Gretchen pull the trigger again, the probability that a bullet will be fired is 1/4.
If Gretchen spins the chamber again, the probability that she shoots Henry would be 2/6, or 1/3, since there are two possible bullets that would be in firing position out of the six possible chambers that would be in position. Did you answer this riddle correctly?
YES NO
Three People In A Room
Three people enter a room and have a green or blue hat placed on their head. They cannot see their own hat, but can see the other hats.
The color of each hat is purely random. They could all be green, or blue, or any combination of green and blue.
They need to guess their own hat color by writing it on a piece of paper, or they can write 'pass'.
They cannot communicate with each other in any way once the game starts. But they can have a strategy meeting before the game.
If at least one of them guesses correctly they win $50,000 each, but if anyone guess incorrectly they all get nothing.
What is the best strategy?
The color of each hat is purely random. They could all be green, or blue, or any combination of green and blue.
They need to guess their own hat color by writing it on a piece of paper, or they can write 'pass'.
They cannot communicate with each other in any way once the game starts. But they can have a strategy meeting before the game.
If at least one of them guesses correctly they win $50,000 each, but if anyone guess incorrectly they all get nothing.
What is the best strategy?
Hint:
Simple strategy: Elect one person to be the guesser, the other two pass. The guesser chooses randomly 'green' or 'blue'. This gives them a 50% chance of winning.
Better strategy: If you see two blue or two green hats, then write down the opposite color, otherwise write down 'pass'.
It works like this ('-' means 'pass'):
Hats: GGG, Guess: BBB, Result: Lose
Hats: GGB, Guess: --B, Result: Win
Hats: GBG, Guess: -B-, Result: Win
Hats: GBB, Guess: G--, Result: Win
Hats: BGG, Guess: B--, Result: Win
Hats: BGB, Guess: -G-, Result: Win
Hats: BBG, Guess: --G, Result: Win
Hats: BBB, Guess: GGG, Result: Lose
Result: 75% chance of winning! Did you answer this riddle correctly?
YES NO
Better strategy: If you see two blue or two green hats, then write down the opposite color, otherwise write down 'pass'.
It works like this ('-' means 'pass'):
Hats: GGG, Guess: BBB, Result: Lose
Hats: GGB, Guess: --B, Result: Win
Hats: GBG, Guess: -B-, Result: Win
Hats: GBB, Guess: G--, Result: Win
Hats: BGG, Guess: B--, Result: Win
Hats: BGB, Guess: -G-, Result: Win
Hats: BBG, Guess: --G, Result: Win
Hats: BBB, Guess: GGG, Result: Lose
Result: 75% chance of winning! Did you answer this riddle correctly?
YES NO
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
A Man Was Outside Taking A Walk When It Began To Rain
A man was outside taking a walk when it began to rain. He did not have an umbrella and he wasn't wearing a hat. His clothes were soaked, yet not a single hair on his head got wet. How could this happen?
Hint:
Old Man On London Bridge
I met an old man on London bridge,
As the sun set on the ridge,
He tipped his hat and drew his name,
And cheated at the guessing game.
What was the mans name?
As the sun set on the ridge,
He tipped his hat and drew his name,
And cheated at the guessing game.
What was the mans name?
Hint:
Andrew. In the third line, and drew his name. It works better when you say it. Did you answer this riddle correctly?
YES NO
YES NO
12 Clowns Riddle
On my way to the fair, I met a group. The group consisted of 12 clowns. Each clown had 30 cats, each cat had 20 hats, each hat had 41 rats, each rat had 4 mice, and each mice had 79 lice. How many of us were going to the fair?
Hint:
A Sharpshooter Riddle
A sharpshooter hangs up his hat, turns around and walks 5000 meters, then turns around and shoots his gun, putting a hole right through his hat. How did he do it?
Hint:
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