Making Ten Riddle
Hint:
Yes it is possible in Roman Numerals. In Roman Numerals,
9 = IX
10 = X
11 = XI
Thus by removing one from 9, you are getting 10 and by removing one from 11, you are getting 10 again. Did you answer this riddle correctly?
YES NO
9 = IX
10 = X
11 = XI
Thus by removing one from 9, you are getting 10 and by removing one from 11, you are getting 10 again. Did you answer this riddle correctly?
YES NO
The Robbery On The Third Floor Riddle
My wife and I took a much-needed holiday in England. It's a long flight from New York to London. We checked into a nice hotel. After a long day of sightseeing we just collapsed into bed. Just a few minutes ago, we were woken up by some noises outside. I looked out the window and the police were everywhere. They yelled up to me that there was a robbery and a murderer on the second floor. I'm on the third floor, and I can see and I can see that the cops have the stairs and elevators locked down. The murderer can't get up to our floor, so we're in no danger. My wife and I are tired, so we're going back to bed. I really hope they catch the guy.
Why did the police yell to the guy if he was on the 3rd floor?
Why did the police yell to the guy if he was on the 3rd floor?
Hint:
America and England have different ways of numbering floors. In America, it goes 1st floor, 2nd floor, 3rd floor. In England, it goes ground floor, 1st floor, 2nd floor. Did you answer this riddle correctly?
YES NO
YES NO
A Room Full Of Water
Imagine youre in a room that is filling with water. There are no windows or doors. How do you get out?
Hint:
A Couple Of Cannibals Riddle
Michelangelo is being chased by a couple of cannibals who will kill him as soon as they get a hold of him. The only way to get rid of them is crossing the river bridge made of ropes and cut it on reaching the other end. He have found two diamonds in the woods each weighing 8 lbs. The rope is weak and can only accommodate a weight of 150 lbs. He weighs 140 lbs. Still he manages to cross the bridge and get rid of the cannibals with the diamonds without taking off any kind of clothing.
How?
How?
Hint:
Michelangelo juggles the diamonds across while crossing the bridge. Did you answer this riddle correctly?
YES NO
YES NO
The Jug Full Of Beer
A barman is having a 12 liters jug full of beer. He needs to divide or split that beer into two equal parts. All he has is two empty jugs of capacity 8 liters and 5 liters.
How will he do it using them?
How will he do it using them?
Hint:
First fill the 8 liters jug complete - 4, 8, 0
Fill the 5 liters jug with 8 liters jug - 4, 3, 5
Pour back the beer from 5 liters jug to 12 liters jug - 9, 3, 0
Pour the 3 liters from 8 liters jug to 5 liters jug - 9, 0, 3
Fill the 8 liters jug completely from 12 liters jug - 1, 8, 3
Fill the 5 liters jug from the 8 liters jug - 1, 6, 5
Pour the entire 5 liters jug back in 12 liters jug - 6, 6, 0
You have successfully split the beer into two equal parts. Did you answer this riddle correctly?
YES NO
Fill the 5 liters jug with 8 liters jug - 4, 3, 5
Pour back the beer from 5 liters jug to 12 liters jug - 9, 3, 0
Pour the 3 liters from 8 liters jug to 5 liters jug - 9, 0, 3
Fill the 8 liters jug completely from 12 liters jug - 1, 8, 3
Fill the 5 liters jug from the 8 liters jug - 1, 6, 5
Pour the entire 5 liters jug back in 12 liters jug - 6, 6, 0
You have successfully split the beer into two equal parts. Did you answer this riddle correctly?
YES NO
2 Dices Riddle
You are provided with two dices. You have a complete liberty to mark any number from 0 to 9 on the faces of both the dices. However, you should be able to represent the days from 1 to 31 by using them.
How will you achieve it or what numbers will you use on the two dices?
How will you achieve it or what numbers will you use on the two dices?
Hint:
On the faces of the first dice, you can write 0, 1, 2, 3, 5 and 7
On the faces of the second dice, you can write 0, 1, 2, 4, 6 and 8.
It is simple to crack. Basically, we need 1 and 2 on both the dices to display 11 and 22. Also, we need 0 on both the dices to display dates from 01 to 09.
Now we have taken every number on either dice except. This is the tricky part. Whenever you want to use a 9, you can simply rotate the face with 6 180 degrees. Did you answer this riddle correctly?
YES NO
On the faces of the second dice, you can write 0, 1, 2, 4, 6 and 8.
It is simple to crack. Basically, we need 1 and 2 on both the dices to display 11 and 22. Also, we need 0 on both the dices to display dates from 01 to 09.
Now we have taken every number on either dice except. This is the tricky part. Whenever you want to use a 9, you can simply rotate the face with 6 180 degrees. Did you answer this riddle correctly?
YES NO
150 Pens Riddle
Rihanna brought home 150 pens but while packing them, she misplaced some of them. When her brother asked how many she had misplaced, she told him:
If you count in pairs, one will remain
If you count in a group of three, two will remain
If you count in a group of four, three will remain
If you count in a group of five, four will remain
If you count in a group of six, five will remain
If you count in a group of seven, nothing will remain.
How many pens do you think has she misplaced ?
If you count in pairs, one will remain
If you count in a group of three, two will remain
If you count in a group of four, three will remain
If you count in a group of five, four will remain
If you count in a group of six, five will remain
If you count in a group of seven, nothing will remain.
How many pens do you think has she misplaced ?
Hint:
The Elf Plans Riddle
Santa always leaves plans for his elves to determine the order in which the reindeer will pull his sleigh. This year, for the European leg of his journey, his elves are working to the following schedule, that will form a single line of nine reindeer:
Comet behind Rudolph, Prancer and Cupid. Blitzen behind Cupid and in front of Donder, Vixen and Dancer. Cupid in front of Comet, Blitzen and Vixen. Donder behind Vixen, Dasher and Prancer. Rudolph behind Prancer and in front of Donder, Dancer and Dasher. Vixen in front of Dancer and Comet. Dancer behind Donder, Rudolph and Blitzen. Prancer in front of Cupid, Donder and Blitzen. Dasher behind Prancer and in front of Vixen, Dancer and Blitzen. Donder behind Comet and Cupid. Cupid in front of Rudolph and Dancer. Vixen behind Rudolph, Prancer and Dasher.
Comet behind Rudolph, Prancer and Cupid. Blitzen behind Cupid and in front of Donder, Vixen and Dancer. Cupid in front of Comet, Blitzen and Vixen. Donder behind Vixen, Dasher and Prancer. Rudolph behind Prancer and in front of Donder, Dancer and Dasher. Vixen in front of Dancer and Comet. Dancer behind Donder, Rudolph and Blitzen. Prancer in front of Cupid, Donder and Blitzen. Dasher behind Prancer and in front of Vixen, Dancer and Blitzen. Donder behind Comet and Cupid. Cupid in front of Rudolph and Dancer. Vixen behind Rudolph, Prancer and Dasher.
Hint: Poor old Dancer was last.
Prancer
Cupid
Rudolph
Dasher
Blitzen
Vixen
Comet
Donder
Dancer Did you answer this riddle correctly?
YES NO
Cupid
Rudolph
Dasher
Blitzen
Vixen
Comet
Donder
Dancer Did you answer this riddle correctly?
YES NO
Mixed Words Riddle
Two words are mixed up in each of the following items.
If you find out one word, the other will be its opposite.
Example : IOUNT = IN x OUT
1. Golyrbi
2. Gondylou
3. WpnuOd
4. Naawmnom
5. Titlghfer
6. Egmooc
7. Ydignhat
8. Yyiannnurs
9. Mmweetrrinus
10. Ciiavelglyt
If you find out one word, the other will be its opposite.
Example : IOUNT = IN x OUT
1. Golyrbi
2. Gondylou
3. WpnuOd
4. Naawmnom
5. Titlghfer
6. Egmooc
7. Ydignhat
8. Yyiannnurs
9. Mmweetrrinus
10. Ciiavelglyt
Hint:
1. Golyrbi : Girl - Boy
2. Gondylou : Young - Old
3. WpnuOd : Up - Down
4. naawmnom : Man - Woman
5. Titlghfer : Right - Left
6. Egmooc : Come - Go
7. Ydignhat : Day - Night
8. Yyiannnurs : Sunny - Rainy
9. Mmweetrrinus : Summer - Winter
10. ciiavelglyt : City - Village Did you answer this riddle correctly?
YES NO
2. Gondylou : Young - Old
3. WpnuOd : Up - Down
4. naawmnom : Man - Woman
5. Titlghfer : Right - Left
6. Egmooc : Come - Go
7. Ydignhat : Day - Night
8. Yyiannnurs : Sunny - Rainy
9. Mmweetrrinus : Summer - Winter
10. ciiavelglyt : City - Village Did you answer this riddle correctly?
YES NO
A Real Gun With Real Bullets
A man walks into a his bathroom and shoots himself right between the eyes using a real gun with real bullets. He walks out alive, with no blood anywhere. And no, he didn't miss and he wasn't Superman or any other caped crusader.
How did he do this?
How did he do this?
Hint:
How Many Triangles Are There?
Hint: Don't forget to count the outside :)
Can You Solve The Horse Sale Brain Teaser?
A man buys a horse for $60, then sells it for $70. He buys the horse back for $80, and then sells the horse for $90.
How much money did he make or lose?
Did he break even?
How much money did he make or lose?
Did he break even?
Hint: He didn't break even.
What Occurs Once In Every Minute Riddle
Hint:
Banana Clock Riddle
Hint: 1. Look closely at the clock.
2. Number of Bananas.
3. Some thing regarding the sides of the Shapes figure.
38
Logic :
From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38. Did you answer this riddle correctly?
YES NO
Logic :
From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38. Did you answer this riddle correctly?
YES NO
Shoe Man Whistle
Hint:
The third equation has a term with a pair of whistles. The last line involves a single whistle.
Furthermore, the man in the second and third lines are wearing a whistle, but the man in the last line is not wearing a whistle. Presumably the value of the whistle should be accounted for to get the correct answer.
The pictures can be translated into the following equations:
shoes + shoes + shoes = 30
shoes + (man + whistle) + (man + whistle) = 20
(man + whistle) + 2(whistles) + 2(whistles) = 13
shoes + (man) x (whistle) = ?
From the first equation we can solve for the shoes value:
shoes + shoes + shoes = 30
3(shoes) = 30
shoes = 10
We can then solve the second equation for the (man + whistle) value:
shoes + (man + whistle) + (man + whistle) = 20
10 + 2(man + whistle) = 20
2(man + whistle) = 10
man + whistle = 5
Then we solve the third equation for the whistle:
(man + whistle) + 2(whistles) + 2(whistles) = 13
5 + 4(whistles) = 13
4(whistles) = 8
whistle = 2
We also need to solve for the value of the man:
man + whistle = 5
man + 2 = 5
man = 3
Now we can evaluate the final expression, remembering the order of operations that multiplication should be evaluated before addition:
shoes + (man) x (whistle) = ?
10 + 3 x 2
= 10 + 3 x 2
= 10 + 6
= 16 Did you answer this riddle correctly?
YES NO
Furthermore, the man in the second and third lines are wearing a whistle, but the man in the last line is not wearing a whistle. Presumably the value of the whistle should be accounted for to get the correct answer.
The pictures can be translated into the following equations:
shoes + shoes + shoes = 30
shoes + (man + whistle) + (man + whistle) = 20
(man + whistle) + 2(whistles) + 2(whistles) = 13
shoes + (man) x (whistle) = ?
From the first equation we can solve for the shoes value:
shoes + shoes + shoes = 30
3(shoes) = 30
shoes = 10
We can then solve the second equation for the (man + whistle) value:
shoes + (man + whistle) + (man + whistle) = 20
10 + 2(man + whistle) = 20
2(man + whistle) = 10
man + whistle = 5
Then we solve the third equation for the whistle:
(man + whistle) + 2(whistles) + 2(whistles) = 13
5 + 4(whistles) = 13
4(whistles) = 8
whistle = 2
We also need to solve for the value of the man:
man + whistle = 5
man + 2 = 5
man = 3
Now we can evaluate the final expression, remembering the order of operations that multiplication should be evaluated before addition:
shoes + (man) x (whistle) = ?
10 + 3 x 2
= 10 + 3 x 2
= 10 + 6
= 16 Did you answer this riddle correctly?
YES NO
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