The Riddle Of Sphinx
Hint:
A person: ("Legs" is a metaphor for hands and knees in the first description and two legs and a cane in the last.) Did you answer this riddle correctly?
YES NO
YES NO
Never Coming Back Riddle
I'm sometimes white and sometimes black.
I'll take you there, but never bring you back.
What could I be? Body parts remaining: 6
I'll take you there, but never bring you back.
What could I be? Body parts remaining: 6
Hint:
The Perfect Yellow
At times they are green; at times they are brown,
and both of these times, they cause me to frown.
But just in between, for a very short while,
they're perfect and yellow, and cause me to smile.
They are?
and both of these times, they cause me to frown.
But just in between, for a very short while,
they're perfect and yellow, and cause me to smile.
They are?
Hint:
Men In The House Riddle
A blue man lives in a blue house. A green man lives in a green house. But I live in the white house. Who am I?
Hint:
Traveling On A Monday Riddle
There once was a cowboy who rode out on Monday and didn't return for two days. Yet he came back on Monday. How can that be?
Hint:
Hearing Without Seeing Riddle
Hint:
A Load Of Wood Riddle
On my way home the other day, I met with a load of wood that was neither straight nor crooked. What kind of wood was it?
Hint:
Extreme Weather Riddle
This is a type of extreme weather
That stretches from earth to sky
It is strong enough to uproot trees
Its center is called an eye
That stretches from earth to sky
It is strong enough to uproot trees
Its center is called an eye
Hint:
How Many Months?
Hint:
Boxes Of Balls Riddle
The first box has two white balls. The second box has two black balls. The third box has a white and a black ball.
Boxes are labeled but all labels are wrong!
You are allowed to open one box, pick one ball at random, see its color and put it back into the box, without seeing the color of the other ball.
How many such operations are necessary to correctly label the boxes?
Boxes are labeled but all labels are wrong!
You are allowed to open one box, pick one ball at random, see its color and put it back into the box, without seeing the color of the other ball.
How many such operations are necessary to correctly label the boxes?
Hint:
Just One!
Because we know all labels are wrong.
So the BW box must be either BB or WW. Selecting one ball from BW will let you know which.
And the other two boxes can then be worked out logically. Did you answer this riddle correctly?
YES NO
Because we know all labels are wrong.
So the BW box must be either BB or WW. Selecting one ball from BW will let you know which.
And the other two boxes can then be worked out logically. Did you answer this riddle correctly?
YES NO
The 9 Lettered Word
Which is the word in English that has nine letters, and remains a word at each step even when you remove one letter from it, right up to a single letter remaining. List each letter as you remove them, along with the resulting word at each step?
Hint:
'Startling' is the word. Begin by removing 'l', which makes it 'starting', then take away the 't', making it 'staring', and so on - string; sting; sing; sin; in; and, I. Did you answer this riddle correctly?
YES NO
YES NO
Twice Named City Riddle
This is a very large US city
The Empire State Building view is nice
Theres a famous Thanksgiving Day parade
The city is so good they named it twice
The Empire State Building view is nice
Theres a famous Thanksgiving Day parade
The city is so good they named it twice
Hint:
Pills A And B Riddle
You have two bottles of pills marked with the label A and B. The pills are identical. The doctor has asked you to take one A pill and one B pill daily. You cant take more or less than that.
While taking out the pills one day, you took out one pill from A and by mistake took out two from B. You have no idea which pill is which now.
You cant throw away the expensive pills. What will you do now?
While taking out the pills one day, you took out one pill from A and by mistake took out two from B. You have no idea which pill is which now.
You cant throw away the expensive pills. What will you do now?
Hint:
Cut each of the three pills in half and put each half in two piles. Now, each of the two piles will contain half of pill A and two halves of pill B.
Take one pill A and cut into half and put the two halves in the two piles. Now, each pile will have two halves of pill A and two halves of pill B which means one pill A and one pill B. You can take one pile today and one pile the next day. Did you answer this riddle correctly?
YES NO
Take one pill A and cut into half and put the two halves in the two piles. Now, each pile will have two halves of pill A and two halves of pill B which means one pill A and one pill B. You can take one pile today and one pile the next day. Did you answer this riddle correctly?
YES NO
Losing A New York Bet
You are hanging around in NYC when a person approaches you.
"Leaving the bald people aside, I can bet a hundred bucks that there are two people living in NYC who have same number of hairs on their heads," he says to you.
You say that you will take the bet. After talking to the man for a couple of minutes, you realize that you have lost the bet.
What did the person say to you that proved his statement ?
"Leaving the bald people aside, I can bet a hundred bucks that there are two people living in NYC who have same number of hairs on their heads," he says to you.
You say that you will take the bet. After talking to the man for a couple of minutes, you realize that you have lost the bet.
What did the person say to you that proved his statement ?
Hint:
This problem can be best solved using the pigeonhole principle.
The argument will go like this:
Assume that all the non-bald people in NYC have different number of hairs on their head. The population is about 9 million and let us assume that there are 8 million among them who are not bald.
Now, those 8 million people need to have different number of hairs. On an average, people have just 100, 000 hairs on their head. If we keep on assuming that there is someone with just one hair, someone with two, someone with three and so on, there will be 7, 900, 00 other people left who will have more than 100, 000 hairs on their head and need different number of hairs.
Now, as per this assumption, if we keep increasing one hair for each person, to make everybody hair different in numbers, we will come across someone with 8, 000, 000 hairs. But that is practically impossible (even 1, 000, 000 is impossible). Thus there must be two people who are having same number of hairs. Did you answer this riddle correctly?
YES NO
The argument will go like this:
Assume that all the non-bald people in NYC have different number of hairs on their head. The population is about 9 million and let us assume that there are 8 million among them who are not bald.
Now, those 8 million people need to have different number of hairs. On an average, people have just 100, 000 hairs on their head. If we keep on assuming that there is someone with just one hair, someone with two, someone with three and so on, there will be 7, 900, 00 other people left who will have more than 100, 000 hairs on their head and need different number of hairs.
Now, as per this assumption, if we keep increasing one hair for each person, to make everybody hair different in numbers, we will come across someone with 8, 000, 000 hairs. But that is practically impossible (even 1, 000, 000 is impossible). Thus there must be two people who are having same number of hairs. Did you answer this riddle correctly?
YES NO
BDay Bash Riddle
I engaged in a strange activity. My birthday was approaching and I decided to collect money for my birthday bash. On the first day of the month, I kept a dollar in my piggy bank, on the second, I kept two dollars and on the third, I kept three and so on.
On my birthday, I had a total of 276 dollars in my piggy bank. Can you find out on which day of the month was my birthday?
On my birthday, I had a total of 276 dollars in my piggy bank. Can you find out on which day of the month was my birthday?
Hint:
23rd.
The easiest way to find out without engaging in any formula would be to simply add them:
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 + 21 + 22 + 23 = 276 Did you answer this riddle correctly?
YES NO
The easiest way to find out without engaging in any formula would be to simply add them:
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 + 21 + 22 + 23 = 276 Did you answer this riddle correctly?
YES NO
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