Three People In A Room
Three people enter a room and have a green or blue hat placed on their head. They cannot see their own hat, but can see the other hats.
The color of each hat is purely random. They could all be green, or blue, or any combination of green and blue.
They need to guess their own hat color by writing it on a piece of paper, or they can write 'pass'.
They cannot communicate with each other in any way once the game starts. But they can have a strategy meeting before the game.
If at least one of them guesses correctly they win $50,000 each, but if anyone guess incorrectly they all get nothing.
What is the best strategy?
The color of each hat is purely random. They could all be green, or blue, or any combination of green and blue.
They need to guess their own hat color by writing it on a piece of paper, or they can write 'pass'.
They cannot communicate with each other in any way once the game starts. But they can have a strategy meeting before the game.
If at least one of them guesses correctly they win $50,000 each, but if anyone guess incorrectly they all get nothing.
What is the best strategy?
Hint:
Simple strategy: Elect one person to be the guesser, the other two pass. The guesser chooses randomly 'green' or 'blue'. This gives them a 50% chance of winning.
Better strategy: If you see two blue or two green hats, then write down the opposite color, otherwise write down 'pass'.
It works like this ('-' means 'pass'):
Hats: GGG, Guess: BBB, Result: Lose
Hats: GGB, Guess: --B, Result: Win
Hats: GBG, Guess: -B-, Result: Win
Hats: GBB, Guess: G--, Result: Win
Hats: BGG, Guess: B--, Result: Win
Hats: BGB, Guess: -G-, Result: Win
Hats: BBG, Guess: --G, Result: Win
Hats: BBB, Guess: GGG, Result: Lose
Result: 75% chance of winning! Did you answer this riddle correctly?
YES NO
Better strategy: If you see two blue or two green hats, then write down the opposite color, otherwise write down 'pass'.
It works like this ('-' means 'pass'):
Hats: GGG, Guess: BBB, Result: Lose
Hats: GGB, Guess: --B, Result: Win
Hats: GBG, Guess: -B-, Result: Win
Hats: GBB, Guess: G--, Result: Win
Hats: BGG, Guess: B--, Result: Win
Hats: BGB, Guess: -G-, Result: Win
Hats: BBG, Guess: --G, Result: Win
Hats: BBB, Guess: GGG, Result: Lose
Result: 75% chance of winning! Did you answer this riddle correctly?
YES NO
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
Making Moms Day
Hint:
Brighten Mom's Day Riddle
Hint:
It Floats Up To The Top
Blow this thing up nice and big
But do not let it pop
When its filled with helium
It floats up to the top
What is it?
But do not let it pop
When its filled with helium
It floats up to the top
What is it?
Hint:
Associated With Cob
Im yellow but Im not the sun
I grow in a field but Im not a sunflower
Im found on an ear but Im not a piece of jewelry
I go well with butter but Im not a slice of toast
Im associated with cob but Im not a web
What am I?
I grow in a field but Im not a sunflower
Im found on an ear but Im not a piece of jewelry
I go well with butter but Im not a slice of toast
Im associated with cob but Im not a web
What am I?
Hint:
Sweet And Bakes Riddle
I have eyes but I cant see
I have skin but I cant feel anything
I can be sweet but Im not a piece of candy
I can be baked but Im not a cake
I can be peeled but Im not a carrot
What could I be?
I have skin but I cant feel anything
I can be sweet but Im not a piece of candy
I can be baked but Im not a cake
I can be peeled but Im not a carrot
What could I be?
Hint:
A Country Of Great Animals
What country has great animals
Like a large bird called an emu
A cute and cuddly koala
Or a big hopping kangaroo?
Like a large bird called an emu
A cute and cuddly koala
Or a big hopping kangaroo?
Hint:
What Flattens All Mountains Riddle
What flattens all mountains, wipes out all species, destroy every building, and turns everything into pieces?
Hint:
I Am Food That Explodes Riddle
I am a food that explodes. But long before I explode, I am already dead. I can be small, I can be big, and I can be fragrant. My name is literal. What am I?
Hint:
You Are In A Cement Room Riddle
You're in a cement room with no windows or doors. The only thing you have is a mirror and a piece of wood. How do you get out?
Hint:
In the mirror, you will notice the dark patch and using the table wood, you can break the wall and escape.
A cement wall doesn't mean that the wall is wet or dry. You happen to notice the dark patch on the wall where the cement was wet, and thus if you push the wall using the table wood, it would break easily. Thus you can escape easily from the room. Did you answer this riddle correctly?
YES NO
A cement wall doesn't mean that the wall is wet or dry. You happen to notice the dark patch on the wall where the cement was wet, and thus if you push the wall using the table wood, it would break easily. Thus you can escape easily from the room. Did you answer this riddle correctly?
YES NO
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