I CUT THROUGH EVIL LIKE A DOUBLE EDGED SWORD AND CHAOS FLEES AT MY APPROACH R RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

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Riddles and Answers © 2024

Adorable Angles Riddle

Hint:
Acute angle.
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Weeping Red Tears

Hint:
A cherry
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Touching Only One Riddle

Hint:
A wedding ring.
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October Anniversary Riddle

Hint:
Spend time with his boo
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October Love Riddle

Hint:
Because the laves fall for them.
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Dancing Feet Riddle

Hint:
A centipede
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Cut Into Chunks

Hint:
Pineapple
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Goodbye Sweetheart Riddle

Hint:
Kissing
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I Love Softball Riddle

Hint:
Because diamonds are a girls best friend.
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The 3 Inch Cube Riddle

Hint: Visualize the core of the cube.
ZERO.

The core of the 3 inch cube when cut, has all faces that are not painted. Hence at least one cube with no painted face always occurs.
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The Coin Toss Riddle

Hint: Think what would be most likely to happen if you chose HHH, would this be a good decision?
The answer is to let your friend go first. This puzzle is based on an old game/scam called Penny Ante. No matter what you picked, your friend would be able to come up with a combination which would be more likely to beat yours. For example, if you were to choose HHH, then unless HHH was the first combination to come up you would eventually lose since as soon as a Tails came up, the combination THH would inevitably come up before HHH. The basic formula you can use for working out which combination you should choose is as follows. Simply take his combination (eg. HHT) take the last term in his combination, put it at the front (in this case making THH) and your combination will be more likely to come up first. Try it on your friends!
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Pirate Girls Makeup Riddle

Hint:
Ship gloss
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Fruity Smooches Riddle

Hint:
It puckered up!
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Laughing Oranges Riddle

Hint:
Tickle its navel!
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Age Of Three Daughters Riddles

Hint:
3, 3, and 8. The only groups of 3 factors of 72 to have non-unique sums are 2 6 6 and 3 3 8 (with a sum of 14). The rest have unique sums:

2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13

The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer.
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