Always On A Roll
If youre needing something adhesive
As attaching stuff is your goal
Then make sure you come looking for me
As I am always on a roll
I am?
As attaching stuff is your goal
Then make sure you come looking for me
As I am always on a roll
I am?
Hint:
The 5,000 Dollar Bank Account
A guy has 5,000 in his bank on Monday.
On Tuesday, they guy had 4,000 dollars in his bank, but he didn't spend or take out any money.
By Sunday, his mortgage strangely went up and he had no money left in his bank. and he kept on getting his mortgage up every Sunday. On the Saturday before that Sunday, he threw out a working computer because he got a new one. The only way to make his mortgage go up and his money go down is through the computer. The guy goes to visit his friend every day and doesn't come home until 5:00. By the next week his mortgage went up higher. He was getting suspicious and narrowed down three victims.
The mailman
His arch enemy that killed his wife.
And his computer hacking friend that lived in another state.
What happened and how? Who did it?
On Tuesday, they guy had 4,000 dollars in his bank, but he didn't spend or take out any money.
By Sunday, his mortgage strangely went up and he had no money left in his bank. and he kept on getting his mortgage up every Sunday. On the Saturday before that Sunday, he threw out a working computer because he got a new one. The only way to make his mortgage go up and his money go down is through the computer. The guy goes to visit his friend every day and doesn't come home until 5:00. By the next week his mortgage went up higher. He was getting suspicious and narrowed down three victims.
The mailman
His arch enemy that killed his wife.
And his computer hacking friend that lived in another state.
What happened and how? Who did it?
Hint:
The mailman did it. There is no mail on Sunday and the mailman fruaded the guys info. every Sunday the mailman would come at 4:00 and mess with his money and mortgage. After plunging the computer into his truck and turning it on. Did you answer this riddle correctly?
YES NO
YES NO
The Mandm Factory Riddle
Hint:
The Secret Santa Exchange
A group of ten friends decide to exchange gifts as secret Santas. Each person writes his or her name on a piece of paper and puts it in a hat. Then each person randomly draws a name from the hat to determine who has him as his or her secret Santa. The secret Santa then makes a gift for the person whose name he drew.
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
When it's time to exchange presents, each person walks over to the person he made the gift for and holds his or her left hand in his right hand.
What is the probability that the 10 friends holding hands form a single continuous circle?
Hint: It's not as difficult as it seems.
It's the number of ways the friends can form a circle divided by the number of ways the names can be drawn out of the hat.
1/10
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
For a group of n friends, there are n! (n factorial) ways to draw the names out of the hat. Since a circle does not have a beginning and end, choose one person as the beginning and end of the circle. There are now (n-1)! ways to distribute the remaining people around the circle. Thus the probability of forming a single circle is
(n-1)! / n!
Since n! = (n-1)! * n (for n > 1), this can be rewritten as
(n-1)! / (n*(n-1)!)
Factoring out the (n-1)! from the numerator and denominator leaves
1/n
as the probability. Did you answer this riddle correctly?
YES NO
The Coin Toss Riddle
You are in a bar having a drink with an old friend when he proposes a wager.
"Want to play a game?" he asks.
"Sure, why not?" you reply.
"Ok, here's how it works. You choose three possible outcomes of a coin toss, either HHH, TTT, HHT or whatever. I will do likewise. I will then start flipping the coin continuously until either one of our combinations comes up. The person whose combination comes up first is the winner. And to prove I'm not the cheating little weasel you're always making me out to be, I'll even let you go first so you have more combinations to choose from. So how about it? Is $10.00 a fair bet?"
You know that your friend is a skilled trickster and usually has a trick or two up his sleeve but maybe he's being honest this time. Maybe this is a fair bet. While you try and think of which combination is most likely to come up first, you suddenly hit upon a strategy which will be immensely beneficial to you. What is it?
"Want to play a game?" he asks.
"Sure, why not?" you reply.
"Ok, here's how it works. You choose three possible outcomes of a coin toss, either HHH, TTT, HHT or whatever. I will do likewise. I will then start flipping the coin continuously until either one of our combinations comes up. The person whose combination comes up first is the winner. And to prove I'm not the cheating little weasel you're always making me out to be, I'll even let you go first so you have more combinations to choose from. So how about it? Is $10.00 a fair bet?"
You know that your friend is a skilled trickster and usually has a trick or two up his sleeve but maybe he's being honest this time. Maybe this is a fair bet. While you try and think of which combination is most likely to come up first, you suddenly hit upon a strategy which will be immensely beneficial to you. What is it?
Hint: Think what would be most likely to happen if you chose HHH, would this be a good decision?
The answer is to let your friend go first. This puzzle is based on an old game/scam called Penny Ante. No matter what you picked, your friend would be able to come up with a combination which would be more likely to beat yours. For example, if you were to choose HHH, then unless HHH was the first combination to come up you would eventually lose since as soon as a Tails came up, the combination THH would inevitably come up before HHH. The basic formula you can use for working out which combination you should choose is as follows. Simply take his combination (eg. HHT) take the last term in his combination, put it at the front (in this case making THH) and your combination will be more likely to come up first. Try it on your friends! Did you answer this riddle correctly?
YES NO
YES NO
Turning Down A Job Offer Riddle
Hint:
Firing The Monkey Riddle
Hint:
Elephant Job Riddle
Hint:
Angel Lose His Job Riddle
Hint:
A Man And His Boss Have The Same Parents Riddle
Hint:
A Man Was Doing His Job Riddle
Hint:
My Age No Longer Sits On A Calendar Riddle
My age no longer sits on a calendar. I function when needed thats if my hands have not given up. A landmark and even a part of history. What am I?
Hint:
Toasting Toast
Jasmine has a toaster with two slots that toasts one side of each piece of bread at a time, and it takes one minute to do so.
If she wants to make 3 pieces of toast, what is the least amount of time she needs to toast them on both sides?
If she wants to make 3 pieces of toast, what is the least amount of time she needs to toast them on both sides?
Hint:
3 minutes. She puts two pieces in the toaster, toasting one side of each. Then she flips one of them, takes one out, and puts the completely untoasted piece into the toaster. Finally, she takes out the toasted piece and puts the two half-toasted pieces of bread into the toaster for a minute and she's done. Did you answer this riddle correctly?
YES NO
YES NO
Eight Eights
Hint:
How Many Batteries?
You have a flashlight that takes 2 working batteries. You have 8 batteries but only 4 of them work.
What is the fewest number of pairs you need to test to guarantee you can get the flashlight on?
What is the fewest number of pairs you need to test to guarantee you can get the flashlight on?
Hint:
7. If you break the batteries into 3 groups: Two groups of 3 and one group of 2. By doing this you guarantee that one of the groups has 2 working batteries. Both of the groups of 3 have 3 possible combinations of 2 batteries and the group of 2 only has 1 combination. So, 3 + 3 + 1 = 7 tries at most to find two working batteries. Did you answer this riddle correctly?
YES NO
YES NO
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