ME THIS A BUS IS TRAVELLING TO AUCKLAND WITH 20 PEOPLE INCLUDING THE BUS DRIVER ONBOARD THE BUS CRASHES AND E RIDDLES WITH ANSWERS TO SOLVE - PUZZLES & BRAIN TEASERS

The woman. There is no such thing as the perfect man or aliens. Did you answer this riddle correctly?
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A tornado or a hurricane. The calm area in the middle of such a storm is called the eye and wind speeds can reach up to 300 mph in an extreme tornado. Neither one have any arms or legs, but that doesnt stop them from moving, does it? Did you answer this riddle correctly?
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3, 3, and 8. The only groups of 3 factors of 72 to have non-unique sums are 2 6 6 and 3 3 8 (with a sum of 14). The rest have unique sums:

2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13

The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
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Australia Did you answer this riddle correctly?
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Australia Did you answer this riddle correctly?
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Sugar Did you answer this riddle correctly?
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Black Ice/Sleet Did you answer this riddle correctly?
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Paint Did you answer this riddle correctly?
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Binary Did you answer this riddle correctly?
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He never did anything with the 7th guy. Did you answer this riddle correctly?
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The patch doubles in size every day and so on the 47th day the patch will be half the size it is on the 48th day Did you answer this riddle correctly?
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38

Logic :
From 1st the hexagon shape has value 15.
The shape has 15 edges(6 of hexagon,5 of Pentagon and 4 of Square)
From 2nd we get value of one bunch of bananas is 4.
So each banana has value of 1.
From 3rd we get that each clock has value of 3.
Which resembles the time on the clock which is 3.
Hence by using these insights, we get the last required values as
Clock = 2 (2 in the clock)
Bananas = 3 (3 bananas in the bunch)
Hexagon = 11 (Hexagon[6 sides] and pentagon[5 sides], so 6+5=11)
So required value is
2+3+3x11=?
2+3+33=? (Multiply first - Bodmas rule)
5+33=38 and hence the answer is 38. Did you answer this riddle correctly?
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Snake (Firework) Did you answer this riddle correctly?
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A possible solution is:

Q1: Ask god B, "If I asked you 'Is A Random?', would you say ja?". If B answers ja, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is indeed Random. Either way, C is not Random. If B answers da, either B is Random (and is answering randomly), or B is not Random and the answer indicates that A is not Random. Either way, you know the identity of a god who is not Random.

Q2: Go to the god who was identified as not being Random by the previous question (either A or C), and ask him: "If I asked you 'Are you False?', would you say ja?". Since he is not Random, an answer of da indicates that he is True and an answer of ja indicates that he is False.

Q3: Ask the same god the question: "If I asked you 'Is B Random?', would you say ja?". If the answer is ja, B is Random; if the answer is da, the god you have not yet spoken to is Random. The remaining god can be identified by elimination. Did you answer this riddle correctly?
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A Christmas tree Did you answer this riddle correctly?
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