As Close As A Friend Riddle
A mile from end to end, yet as close to as a friend. A precious commodity, freely given. Found on the rich, poor, short and tall, but shared among children most of all. What is it?
Hint:
Rescuing The Princess
I roam through the land hoping to rescue my love. I search high and low and will stomp on you if you get in my way. What am I?
Hint:
Mario, from Super Mario Brothers video game by Nintendo. He roams the land searching for the princess and his primary method of getting rid of folks is to stomp on them.
Thanks to Rowan for figuring this out. Did you answer this riddle correctly?
YES NO
Thanks to Rowan for figuring this out. Did you answer this riddle correctly?
YES NO
The Clown Dressed Goat Riddle
Hint:
No Clapping Riddle
Hint:
Crying Wolf Riddle
Hint:
Get There By Subway Riddle
You might go to Central Park
Or catch a show on Broadway
Where in the world would you be
To get to these by subway?
Or catch a show on Broadway
Where in the world would you be
To get to these by subway?
Hint:
Losing A New York Bet
You are hanging around in NYC when a person approaches you.
"Leaving the bald people aside, I can bet a hundred bucks that there are two people living in NYC who have same number of hairs on their heads," he says to you.
You say that you will take the bet. After talking to the man for a couple of minutes, you realize that you have lost the bet.
What did the person say to you that proved his statement ?
"Leaving the bald people aside, I can bet a hundred bucks that there are two people living in NYC who have same number of hairs on their heads," he says to you.
You say that you will take the bet. After talking to the man for a couple of minutes, you realize that you have lost the bet.
What did the person say to you that proved his statement ?
Hint:
This problem can be best solved using the pigeonhole principle.
The argument will go like this:
Assume that all the non-bald people in NYC have different number of hairs on their head. The population is about 9 million and let us assume that there are 8 million among them who are not bald.
Now, those 8 million people need to have different number of hairs. On an average, people have just 100, 000 hairs on their head. If we keep on assuming that there is someone with just one hair, someone with two, someone with three and so on, there will be 7, 900, 00 other people left who will have more than 100, 000 hairs on their head and need different number of hairs.
Now, as per this assumption, if we keep increasing one hair for each person, to make everybody hair different in numbers, we will come across someone with 8, 000, 000 hairs. But that is practically impossible (even 1, 000, 000 is impossible). Thus there must be two people who are having same number of hairs. Did you answer this riddle correctly?
YES NO
The argument will go like this:
Assume that all the non-bald people in NYC have different number of hairs on their head. The population is about 9 million and let us assume that there are 8 million among them who are not bald.
Now, those 8 million people need to have different number of hairs. On an average, people have just 100, 000 hairs on their head. If we keep on assuming that there is someone with just one hair, someone with two, someone with three and so on, there will be 7, 900, 00 other people left who will have more than 100, 000 hairs on their head and need different number of hairs.
Now, as per this assumption, if we keep increasing one hair for each person, to make everybody hair different in numbers, we will come across someone with 8, 000, 000 hairs. But that is practically impossible (even 1, 000, 000 is impossible). Thus there must be two people who are having same number of hairs. Did you answer this riddle correctly?
YES NO
Gym Class Riddle
Four different-colored balls are being used in a gym class activity blue, red, yellow and orange. Each student must hold two different-colored balls, but no two students can have the same two colors (for example, only one student can hold the blue and red ball).
How many students can play the game?
How many students can play the game?
Hint:
Six. Explanation: 1. Blue Red
2. Blue Yellow
3. Blue Orange
4. Red Yellow
5. Red Orange
6. Yellow Orange Did you answer this riddle correctly?
YES NO
2. Blue Yellow
3. Blue Orange
4. Red Yellow
5. Red Orange
6. Yellow Orange Did you answer this riddle correctly?
YES NO
Old Clocks Riddle
Hint:
Fish Land Riddle
Hint:
Oranges And Bells Riddle
Hint:
Devour All Things Riddle
This thing all things devours,
Birds, beasts, trees, and flowers.
Gnaws iron bites steel,
Grinds hard stones to meal,
Slays king, ruins town,
And beats high mountain down
Birds, beasts, trees, and flowers.
Gnaws iron bites steel,
Grinds hard stones to meal,
Slays king, ruins town,
And beats high mountain down
Hint:
Time. Iron, steel, stone and virtually any substance will be worn down given enough time. Did you answer this riddle correctly?
YES NO
YES NO
A Rickety Bridge Riddle
Four people need to cross a rickety bridge at night. Unfortunately, they have only one torch and the bridge is too dangerous to cross without one. The bridge is only strong enough to support two people at a time. Not all people take the same time to cross the bridge. Times for each person: 1 min, 2 mins, 7 mins and 10 mins. What is the shortest time needed for all four of them to cross the bridge?
Hint:
17 mins.
The initial solution most people will think of is to use the fastest person as an usher to guide everyone across. How long would that take? 10 + 1 + 7 + 1 + 2 = 21 mins. Is that it? No. That would make this question too simple even as a warm up question.
Let's brainstorm a little further. To reduce the amount of time, we should find a way for 10 and 7 to go together. If they cross together, then we need one of them to come back to get the others. That would not be ideal. How do we get around that? Maybe we can have 1 waiting on the other side to bring the torch back. Ahaa, we are getting closer. The fastest way to get 1 across and be back is to use 2 to usher 1 across. So let's put all this together.
1 and 2 go cross
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)
Total time = 2 + 2 + 10 + 1 + 2 = 17 mins Did you answer this riddle correctly?
YES NO
The initial solution most people will think of is to use the fastest person as an usher to guide everyone across. How long would that take? 10 + 1 + 7 + 1 + 2 = 21 mins. Is that it? No. That would make this question too simple even as a warm up question.
Let's brainstorm a little further. To reduce the amount of time, we should find a way for 10 and 7 to go together. If they cross together, then we need one of them to come back to get the others. That would not be ideal. How do we get around that? Maybe we can have 1 waiting on the other side to bring the torch back. Ahaa, we are getting closer. The fastest way to get 1 across and be back is to use 2 to usher 1 across. So let's put all this together.
1 and 2 go cross
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)
Total time = 2 + 2 + 10 + 1 + 2 = 17 mins Did you answer this riddle correctly?
YES NO
Parade Month Riddle
Hint:
Threw Away The Outside Food Riddle
First I threw away the outside and cooked the inside, then I ate the outside and threw away the inside, what did I eat?
Hint: It's a vegetable
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