Empty Pockets Riddle
Hint:
It has a hole. The hole is the thing (although it could be argued a pocket has air) Did you answer this riddle correctly?
YES NO
YES NO
Important To Both Human Beings And Animals
I am important to both human beings and animals. Both search for me but it is hard to find me. I travel to benefit them. What am I?
Hint:
A scent or smell. A scent is important to both humans and animals and both search for scents (for different reasons). A scent travels through the air to benefit humans and animals, again, for different reasons. Did you answer this riddle correctly?
YES NO
YES NO
The Greatest Air Pressure Riddle
Hint:
Swinging At The Park Riddle
A man and his 6 year old daughter are swinging together at the park. Each is on a separate, identical swing. The man has three times the mass of the child.
Which swings faster? And more importantly, why?
Which swings faster? And more importantly, why?
Hint:
The speed at which a pendulum swings is called the period and given by the equation:
2 x pi x square root of (length of rope from fulcrum to Center of Mass divided by gravity)
Since gravity is constant, the only thing that effects the period is the length of rope. In the above scenario, you assume the man is taller then the child. Therefore his center of mass is higher. This makes the distance between the fulcrum to the center of mass shorter then for the child. The man swings faster. Did you answer this riddle correctly?
YES NO
2 x pi x square root of (length of rope from fulcrum to Center of Mass divided by gravity)
Since gravity is constant, the only thing that effects the period is the length of rope. In the above scenario, you assume the man is taller then the child. Therefore his center of mass is higher. This makes the distance between the fulcrum to the center of mass shorter then for the child. The man swings faster. Did you answer this riddle correctly?
YES NO
The Air You Breathe Riddle
I am the element found in just about
everything. I am the air you breathe, and support the growth of all living things. What am I?
everything. I am the air you breathe, and support the growth of all living things. What am I?
Hint:
Prince Age Riddle
A princess is as old as the prince will be when the princess is twice the age that the prince was when the princess's age was half the sum of their present ages.
What are their ages?
What are their ages?
Hint:
Current Future Past
Princess x 2z (x+y)/2
Prince y x z
I then created three equations, since the difference in their age will always be the same.
d = the difference in ages
x y = d
2z x = d
x/2 + y/2 z = d
I then created a matrix and solved it using row reduction.
x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d
It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
This means that you can pick any difference you want (an even one presumably because you want integer ages).
Princess age: 4d
Prince age: 3d
Ages that work
Princess:
4
8
16
24
32
40
48
56
64
72
80
Prince:
3
6
12
18
24
30
36
42
48
54
60 Did you answer this riddle correctly?
YES NO
Princess x 2z (x+y)/2
Prince y x z
I then created three equations, since the difference in their age will always be the same.
d = the difference in ages
x y = d
2z x = d
x/2 + y/2 z = d
I then created a matrix and solved it using row reduction.
x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d
It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
This means that you can pick any difference you want (an even one presumably because you want integer ages).
Princess age: 4d
Prince age: 3d
Ages that work
Princess:
4
8
16
24
32
40
48
56
64
72
80
Prince:
3
6
12
18
24
30
36
42
48
54
60 Did you answer this riddle correctly?
YES NO
Dropping Coconuts Riddle
You have two coconuts and you want to find out how high they can be dropped from a 100 story building before they break. But you only have $1.40 and the elevator costs a dime each time you ride it up (it's free for rides down).
How can you drop the coconuts to guarantee you will find the lowest floor they will break at, while starting and ending at floor 1?
How can you drop the coconuts to guarantee you will find the lowest floor they will break at, while starting and ending at floor 1?
Hint: They break when dropped from the same height and they don't weaken from getting dropped.
You could drop it at floor 1 first (because you start at floor 1). Then you would go to the floors: 14, 27, 39, 50, 60, 69, 77, 84, 90, 95, 99, and 100. Whatever floor your first coconut breaks at, go to the floor above the last floor the coconut survived and drop the second coconut from this floor. Then go up by one floor until the second coconut breaks and that is the lowest floor it will break at. Did you answer this riddle correctly?
YES NO
YES NO
Age Of Three Daughters Riddles
I was visiting a friend one evening and remembered that he had three daughters. I asked him how old they were. The product of their ages is 72, he answered. Quizzically, I asked, Is there anything else you can tell me? Yes, he replied, the sum of their ages is equal to the number of my house. I stepped outside to see what the house number was. Upon returning inside, I said to my host, Im sorry, but I still cant figure out their ages. He responded apologetically, Im sorry, I forgot to mention that my oldest daughter likes strawberry shortcake. With this information, I was able to determine all three of their ages. How old is each daughter?
Hint:
3, 3, and 8. The only groups of 3 factors of 72 to have non-unique sums are 2 6 6 and 3 3 8 (with a sum of 14). The rest have unique sums:
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
2 + 2 + 18 = 22
2 + 3 + 12 = 18
2 + 4 + 9 = 15
3 + 4 + 6 = 13
The house number alone would have identified any of these groups. Since more information was required, we know the sum left the answer unknown. The presence of a single oldest child eliminates 2 6 6, leaving 3 3 8 as the only possible answer. Did you answer this riddle correctly?
YES NO
12 Islanders Teeter Totter Riddle
There is an island with 12 islanders. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11.
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There are no scales or other weighing device on the island.
How can you find out which islander is the one that has a different weight?
Hint:
Six on one side - six on the other = one side is heavier.
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Take the heavier six men, divide them into three and three (random).
Three on one side - three on the other = one side will one heavier.
Divide that three men from the heavier side side, have one on one side - one on the other.
Two results can determine which of the last three men weight is a different weight than each other.
With the last group of three men, have two men go head-to-head. The see-saw will either weight different: one weights more than the other man meaning the heavier man is the "12th man" or the see-saw will balance between the two men because they are the same weight. That means the third man standing on the sidelines by default weights more than the last two men weighted. Thus making that man on the sidelines the "12th man" that weights more than other 11.
Heavier wins 6v6; winner gets divided. Heavier wins 3v3; winner gets divided. Heavier wins 1v1 (12th man) or Equal 1v1 = third man weight more, he's the 12th man.
You could find the same results changing the process and picking from the lighter group three times. You’re only trying to find the difference in weight. Not the exact weight (more or less) of that "12th man."
Lightest 6v6; Lightest 3v3; Lightest 1v1 or Equal 1v1 = third man weight less. Did you answer this riddle correctly?
YES NO
Lighter Than Air Riddle
Hint:
Two Zero And Two Four Riddle
Hint:
B) 2024
When you pronounce a number say, 3006, it is pronounced as three thousand six. But, it is not pronounced as three two zero and six. Because, it will result in 3206. It might be grammatically but mathematically wrong or vice versa.
The pronunciation does not say how many but what the number is at the particular position.
Hence, 2024 has two zero and two four. Did you answer this riddle correctly?
YES NO
When you pronounce a number say, 3006, it is pronounced as three thousand six. But, it is not pronounced as three two zero and six. Because, it will result in 3206. It might be grammatically but mathematically wrong or vice versa.
The pronunciation does not say how many but what the number is at the particular position.
Hence, 2024 has two zero and two four. Did you answer this riddle correctly?
YES NO
What Comes Immediately Before Today Riddle
If today is four days before the day immediately before two days after Wednesday, WHAT DAY comes immediately before the day that is two days after the day immediately after the day which comes two days before the day which comes three days after the day before yesterday?
Hint: Determine what "Today" is, then work backwards until you determine the day in question.
MONDAY. "Today" is Sunday. Now, starting at Sunday and working backwards (from "the day before yesterday"), we have the following: - 2 + 3 -2 + 1 + 2 - 1 ...So, we go from Sunday to Fri. to Mon. to Sat. to Sun. to Tues. to MONDAY. Did you answer this riddle correctly?
YES NO
YES NO
12 Pills Riddle
You have 12 pills and they all got the same weight, except for one, which hasn't got the same weight. You don't know if it is heavier or easier. You have one scale to weight the pills. You now have to find out, which pill is the right one (the one with a different weight), but you can use the scale only three times. How do you know, which one is the right one?You have 12 pills and they all got the same weight, except for one, which hasn't got the same weight. You don't know if it is heavier or easier. You have one scale to weight the pills. You now have to find out, which pill is the right one (the one with a different weight), but you can use the scale only three times. How do you know, which one is the right one?
Hint:
E = easier in "1", H = heavier in "1". 1: Weight 4:4. If they balance go to "2", if they don't balance, go to "3". 2: Balance 1:1 of the pills you didn't weight yet. Then weight one you didn't weight and one you did weight. If they balanced in the first weighing, and balanced in the second weighing, the last pill is the right one. If they balanced in the first weighing and didn't balance in the second, the one you didn't use before is the right pill. If they didn't balance at all, it's the pill you weighed twice. If they didn't balance in the first weighing, but balanced in the second, it is the first pill. 3: Weight EHH : EHH. If they balance, weight one you already weighed, with an unweighed and go to "4". If they don't balance go to "5". 4: If they balance, the one you didn't weight at all is the right pill. If they don't balance, the one you only weighed once is the right one. 5: Give away every pill that was once easier AND once heavier. You should only have EHH left. Weight H:H. If they balance, E is the right one. If the don't balance, the one which was only heavier the whole time, is the right pill. Did you answer this riddle correctly?
YES NO
YES NO
I Can Be Hot I Can Be Cold Riddle
I can be hot, I can be cold, I can run and I can be still, I can be hard and I can be soft. What am I?
Hint:
This Lady Is All In Riddle
Black's 100, blue's 10, red's 5. This lady is all in. If to pass this door you strive, Find the total the dame's holdin.'
Hint: There are 3 colors. Blue, red and black.
From these, we must find at the correct answer. What about the poker chips were on the table?
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