Riding To Seattle Riddle
You rode on January 1st 1996 to Seattle where you rode back on January 1st 1996 but while there stayed for 2 days how is that possible?
Hint:
New Years And Christmas Day Riddle
Everyone knows that both Christmas Day and New Year's Day always fall on the same day of the week. However, in 1939, the year of the outbreak of World War II, Christmas fell on a Monday and New Year's fell on a Sunday. Why?
Hint:
In any given year Christmas Day and New Year's Day fall on different days of the week. Christmas occurs around 51 weeks later in the year than New Years Day. 1939 was no different. Did you answer this riddle correctly?
YES NO
YES NO
I Bring Luck Riddle
At Chinese New Year celebrations
I breathe fire, dance and run amuck
With a few men to guide my steps
My presence brings good fortune and luck
What am I?
I breathe fire, dance and run amuck
With a few men to guide my steps
My presence brings good fortune and luck
What am I?
Hint:
More Than 90 Degrees Riddle
Hint:
The Blindfolded Sharpshooter Riddle
A sharpshooter hung up his hat and put on a blindfold. He then walked 100 yards, turned around, and shot a bullet through his hat. The blindfold was a perfectly good one, completely blocking the man's vision. How did he manage this?
Hint:
A Ram's Favorite Tune Riddle
Hint:
Fighting For Black Americans Riddle
I was born on May 19,1925.
I fought for black Americans.
I was a leader of the nation of Islam.
Who am I?
I fought for black Americans.
I was a leader of the nation of Islam.
Who am I?
Hint:
Missionary Among Slaves
I lived from 1797 to 1883.
I was a missionary among slaves in New York.
I used my talent of speaker for the slavery movement.
My name was changed by a Quaker family to Van Wagener.
I was a missionary among slaves in New York.
I used my talent of speaker for the slavery movement.
My name was changed by a Quaker family to Van Wagener.
Hint:
Fought For Education Riddle
I saw education as the key to improving the lives of African-Americans in the 1900s, and fought to educate my people. Who am I?
Hint:
Drowning Fish Riddle
Hint:
Rope Burn Riddle
You have two ropes. Each rope takes one hour to burn. These ropes are not identical, nor are they uniform; i.e. it does not necessarily take half an hour for half the rope to burn (if you have trouble visualizing this, imagine a rope of varying thickness across its length). With only these two ropes and a way to light them, how do you measure out 45 minutes?
Hint: You can light multiple ends and/or multiple ropes at the exact same time.
Light both ends of one rope, and only one end of the other rope. This will cause the first rope to burn out in 30 minutes. When the first rope burns out, there will be 30 minutes left on the second rope. So then, light the other end of the second rope, and the rest of it will burn out in 15 minutes. 30 + 15 = 45 minutes. Did you answer this riddle correctly?
YES NO
YES NO
If It's Information You Seek
If it's information you seek, come and see me.
If it's pairs of letters you need, I have consecutively three.
Who am I?
If it's pairs of letters you need, I have consecutively three.
Who am I?
Hint:
Prince Age Riddle
A princess is as old as the prince will be when the princess is twice the age that the prince was when the princess's age was half the sum of their present ages.
What are their ages?
What are their ages?
Hint:
Current Future Past
Princess x 2z (x+y)/2
Prince y x z
I then created three equations, since the difference in their age will always be the same.
d = the difference in ages
x y = d
2z x = d
x/2 + y/2 z = d
I then created a matrix and solved it using row reduction.
x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d
It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
This means that you can pick any difference you want (an even one presumably because you want integer ages).
Princess age: 4d
Prince age: 3d
Ages that work
Princess:
4
8
16
24
32
40
48
56
64
72
80
Prince:
3
6
12
18
24
30
36
42
48
54
60 Did you answer this riddle correctly?
YES NO
Princess x 2z (x+y)/2
Prince y x z
I then created three equations, since the difference in their age will always be the same.
d = the difference in ages
x y = d
2z x = d
x/2 + y/2 z = d
I then created a matrix and solved it using row reduction.
x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d
It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
This means that you can pick any difference you want (an even one presumably because you want integer ages).
Princess age: 4d
Prince age: 3d
Ages that work
Princess:
4
8
16
24
32
40
48
56
64
72
80
Prince:
3
6
12
18
24
30
36
42
48
54
60 Did you answer this riddle correctly?
YES NO
The Weight Of A Melon Riddle
Watermelon is 99% water. I have 100 pounds of watermelon. After a week, drying in the sun, the shriveled watermelon had only dried down to being 98% water. What is the total weight of the watermelon now?
Hint: We are to determine X the total mass of melon after the drying.
The Dry weight, DW is 1lb both before and after the drying.
The New Water weight, WNW is clearly X - DW or X - 1
The Rising Tide Riddle
A ship is at dock and the tide rises 3 feet. If the water level is at 4 on the "water marks" on the side of the ship, what is the water level read now?
Hint:
The water level never changes...it remains at 4. The ship rises with the tide. The "water marks" on the side of a ship designates load and weight capacity. Did you answer this riddle correctly?
YES NO
YES NO
Add Your Riddle Here
Have some tricky riddles of your own? Leave them below for our users to try and solve.